Quantitative and Numerical Ability Test

Result

Quantitative and Numerical Ability Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

If 14x² - 13x + 3 = 0 and 99y² - 62y + 8 = 0, then which of the following can be the values of x and y?

A
x = 2/11,y = 4/9

B
x= 3/7, y = 1/2

C
x = 1/3, y = 4/9

D
x = 3/7, y = 4/9

E
x = 3/7, y = 3/11

Solution

We have 14x² - 13x + 3 = 0 ⇒ (7x – 3) (2x – 1) = 0 ⇒ x = 3/7 or 1/2.

And 99y² - 62y + 8 = 0 ⇒ (11y – 2) (9y - 4) = 0 ⇒ y = 2/11 or 4/9.

Hence x = 3/7, y = 4/9.
Question 2
1 / -0

Deepak invests, an amount of Rs 1,200 at the rate of 5 p.c.p.a. What amount of compound interest will be obtained at the end of 2 years?

A
Rs 120

B
Rs 125

C
Rs 130

D
Rs 128

E
None of these

Solution
Question 3
1 / -0

If 20 boys and 12 girls can do a work in 9 days and 12 boys and 16 girls can do the same work in 10 days, then find the efficiency ratio of a boy to a girl.

A
1 : 2

B
5 : 7

C
11 : 13

D
13 : 15

E
9 : 11

Solution

Given:

20 boys and 12 girls can do work in 9 days and 12 boys and 16 girls can do the same work in 10 days.

We know that,
Question 4
1 / -0

X₁, X₂, X₃, X₄, X₅, X₆, X₇are 7 natural numbers. The median and mode of the given set of observations are 14 and 12 respectively. The mean of the given observation is 19. X₄ is the median. No two scores above the median are similar.

What is the maximum possible value of X₇?

A
63

B
54

C
51

D
57

E
69

Solution

The median is 14, so X₄= 14. Now the mean of all the terms is 19, so the total = 19 × 7 = 133. We need to find the maximum possible value of X₇.

As the mode is 12, so we can take the values as X₁ = 1, X₂ = 12, X₃= 12,

X₄ = 14, X₅= 15, X₆ = 16. So there sum is 70. So the maximum possible value of X₇= 133 – 70 = 63.
Question 5
1 / -0

In the following question, two equations numbered I and II are given. You have to solve both the equations and give your answer:

I. 17m² + 48m = 9

II. 26n² = 4(16n – 6)

A
m=n or the relationship cannot be established

B
m>n

C
m<n

D
m≥ n

E
m ≤ n

Solution

We will solve both the equations separately

Equation (1)

17m² + 48m = 9

⇒ 17m² + 48m – 9 = 0

⇒ 17m²+ 51m – 3m – 9 = 0

⇒ 17m(m + 3) – 3(m + 3) = 0

⇒ (17m – 3) (m + 3) = 0
Question 6
1 / -0

The price of petrol is increased by 25%. By what per cent must a car owner reduce his consumption of petrol so as to not increase his expenditure on petrol?

A
25%

B
50%

C
30%

D
20%

E
None of these

Solution

Suppose the cost of fuel was 100 and it is now 125. Suppose initial consumption was X and the new consumption is Y.

Then, 100X = 125Y. Solving this yields Y = 0.8X. Thus the consumption is reduced by 20%.

Hence option
Question 7
1 / -0

What is the standard deviation of the given set of series? (rounded off to the nearest integer)

3 11 8 16 21 55 5

A
12

B
13

C
19

D
17

E
9

Solution
Question 8
1 / -0

If 14x + 5y = 16 and 15y - 7x = 6, then what is the value of x - y?

A
4/27

B
4/39

C
2/35

D
4/33

E
2/29

Solution

We have 14x + 5y = 16……(i)

and 15y - 7x = 6 …….(ii)

Multiply (ii) by 2 and add to (i), we get y = 28/35.

Put this value of y in (i), we get x = 6/7.

so x-y = 6 / 7 - 28 / 35 = 2 / 35
Question 9
1 / -0

A sum of Rs. 600 amount to Rs. 720 in 5 years. What will be the amount if the rate of interest is increased by 3%?

A
820

B
810

C
800

D
805

E
815

Solution
Question 10
1 / -0

A
3

B
2

C
1/2

D
6

Solution

Since age of Sumit is 8 years, so age of Dolly is 4 years. Hence the age of Sonu is 20 years and age of Manu is 24 yeras.

So Manu's age is 6 times that of Dolly.