Self Studies
Selfstudy
Selfstudy

Probability Test - 3

Result Self Studies

Probability Test - 3
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    In a box, there are 5 red, 9 green and 6 black balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

    Solution

    Total number of balls = 5 + 9 + 6 = 20
    E = event that the ball drawn is neither red nor green = event that the ball drawn is black = 6

    Therefore, P(E) = 6/20 = 3/10

     

  • Question 2
    1 / -0

    In a box, there are 5 Nestle and 18 Dairy Milk chocolates. Mohan picks up a chocolate without looking at it. What is the probability that it will be a Nestle chocolate?

    Solution

    Number of Nestle chocolates = 5
    Number of Dairy Milk chocolates = 18
    Total number of chocolates = 18 + 5 = 23

    Probability that a picked up chocolate is Nestle = 5/23

     

  • Question 3
    1 / -0

    A card is drawn from a pack of 52 cards. What is the probability of getting a non-face card or an ace card?

    Solution

    There are 40 non-face cards and 4 ace cards which are already counted in non face cards.
    So, the total number of favourable cases are 40.
    Required Probability = 40/52 = 10/13

     

  • Question 4
    1 / -0

    Suresh throws 2 dice simultaneously. What is the probability of getting two numbers whose product is odd?

    Solution

    In a two dice throw, the total number of cases are 36 i.e., n(S) = 36

    Let E be the event of getting two numbers whose product is odd.
    Then, E = {(1, 1), (1, 3), (1, 5), (3, 1), (3, 3), (3, 5), (5, 1), (5, 3), (5, 5)}
    n(E) = 9

    So, probability = 9/36 = 1/4

     

  • Question 5
    1 / -0

    From a deck of playing cards, one card is removed randomly & found to be a Jack of hearts. Then a second card is drawn without replacing the first one. What is the probability of getting a second card as a Jack of red colour?

    Solution

    The first card is a jack of red colour.

    On the second turn, there is only one remaining Jack card of red colour (Jack of diamond) &
    total no. of remaining cards is 51.

    So, probability = 1/51

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now