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Quadratic Equations Test - 4

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Quadratic Equations Test - 4
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  • Question 1
    1 / -0

    Each side of a square measures 4 cm more than each side of another square. If the sum of their areas is 400 sq. cm, then what is the area of the larger square?

    Solution

    Let each side of the smaller square measure x cm.
    Then, length of each side of the larger square = (x + 4) cm

    According to problem:
    (x + 4)2 + x2 = 400 {Area of square = Side × Side}

    x2 + 8x + 16 + x2 = 400
    Or 2x2 + 8x - 384 = 0
    ⇒ x2 + 4x - 192 = 0

    Or (x + 16)(x - 12) = 0
    ⇒ x = 12
    So, length of each side of the larger square = (12 + 4) cm = 16 cm

    Area = (16)2 cm= 256 cm2

     

  • Question 2
    1 / -0

    B's age is the square of the age of A. After 5 years, B will be 3 times as old as A. What is the difference between their ages?

    Solution

    Let the age of A be x.
    So, B's age = x2

    After 5 years, x2 + 5 = 3(x + 5)
    x2 + 5 – 3x – 15 = 0

    x2 – 3x – 10 = 0 ⇒ x = -2, 5
    x is +ve, so x = 5

    So, A's age = 5 years
    B's age = 25 years

    Difference = (25 – 5) years = 20 years
    Thus, answer option 4 is correct.

     

  • Question 3
    1 / -0

    Read the following statements carefully and choose the suitable.

    Statement I: The quadratic equation ax2 + bx + c = 0 has no real roots if b2 - 4ac > 0.
    Statement II: The number of possible values of m (m is a whole number) is 5 if the quadratic equation 4x2 + 16x + 4m = 0 has real roots.

    Solution

    Statement I is false because if the quadratic equation ax2 + bx + c = 0 has no real roots, then b2 - 4ac < 0.

    Statement II is true because for the equation 4x2 + 16x + 4m = 0 to have real roots, b2 – 4ac must be greater than or equal to 0, i.e. 256 - 64m ≥ 0 or 4 ≥ m, m being a whole number.

    So, m can have 0, 1, 2, 3 and 4 as possible values. So, 5 values are possible for m.

     

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