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IMO - Mock Test - 1

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IMO - Mock Test - 1
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Find the next term in the following number series:

    5, 15, 9, 27, 21, 63, 57, ___

    Solution

    This is an alternating multiplication and subtraction series. First multiply by 3 and then subtract 6.

    5 × 3 = 15

    15 - 6 = 9

    9 × 3 = 27

    27 - 6 = 21

    21 × 3 = 63

    63 - 6 = 57

    57 × 3 = 171

     

  • Question 2
    1 / -0

    Ring is to finger as watch is to ______.

    Solution

    A person wears a ring on a finger and the watch on the wrist.

     

  • Question 3
    1 / -0

    Find the next term in the given series: 3, 8, 6, 11, 9, 14, _

    Solution

    Series is going in +5 and -2

    3 + 5 = 8
    8 - 2 = 6
    6 + 5 = 11
    11 - 2 = 9
    9 + 5 = 14
    14 - 2 = 12

     

  • Question 4
    1 / -0

    Find the next term in the given series:

    6, 12, 36, 144, __

    Solution

    The pattern followed in the given series is:

    6 × 2 = 12

    12 × 3 = 36

    36 × 4 = 144

    So, the next term will be:

    144 × 5 = 720

     

  • Question 5
    1 / -0

    Find the number which replaces the question mark (?).

    9 : 729 : : ? : 1728

    Solution

    As 729 is the cube of 9, 1728 is the cube of 12. Hence, 12 is the answer.

     

  • Question 6
    1 / -0

    Choose the number which is different from the rest.

    Solution

    93 is different from other numbers as 93 is not a prime number and all other numbers are prime numbers.

     

  • Question 7
    1 / -0

    In a certain language, LINES is written as MJOFT. How is ANGLES written in that language?

    Solution

    While writing LINES, each letter is moved one step forward.

    So, ANGLES : BOHMFT

    A + 1 = B

    N + 1 = O

    G + 1 = H

    L + 1 = M

    E + 1 = F

    S + 1 = T

     

  • Question 8
    1 / -0

    Choose the odd one out from the given numbers.

    Solution

    All are prime numbers except 93 as 93 = 3 × 31.

     

  • Question 9
    1 / -0

    In the assembly, Bill is standing at 14th position from the back in the row of 30 students. What is his position from the front?

    Solution

    Total number of students in the row = 30
    Bill's position from back = 14
    Bill's position from the front = 30 - 14 +1 = 17

     

  • Question 10
    1 / -0

    In a certain language, if ANSWER is coded as HPQRNT, then how is NEWS coded in that language?

    Solution

    While coding ANSWER,
    A is written as H
    N is written as P
    S is written as Q
    W is written as R
    E is written as N
    R is written as T
    So, NEWS is coded as PNRQ (As, N is P, E is N, W is R and S is Q).

     

  • Question 11
    1 / -0

    Rearrange the following letters to make a single word and then choose the category to which it belongs.

    G A E L E

    Solution

    G A E L E = EAGLE, which is a bird.

     

  • Question 12
    1 / -0

    What day is day after tomorrow if yesterday was Friday?

    Solution

    As yesterday was Friday, therefore, today is Saturday, tomorrow is Sunday and day after tomorrow is Monday.

     

  • Question 13
    1 / -0

    Five friends are sitting in a row. Sachin and Rahul are on the extreme ends. Dishant is sitting next to the left of Rahul. Sohan is sitting next to Ram and is the immediate neighbour of Sachin. Who is sitting in the middle?

    Solution

    Sitting arrangement = Sachin, Sohan, Ram, Dishant and Rahul
    Hence, Ram is sitting in the middle.

     

  • Question 14
    1 / -0

    Which of the following is the correct representation of the number - twelve thousand eighty-two?

    Solution

    Twelve thousand eighty-two = 12,000 + 82 = 12,082

     

  • Question 15
    1 / -0

    Which of the following expressions is true?

    Solution

    4 x 7 - (6 + 12)
    = 4 x 7 - 18
    = 28 - 18 = 10

     

  • Question 16
    1 / -0

    Shanu adds 3.971 to the product of 55.9 and 12.5. What will be her answer?

    Solution

    Product of 55.9 and 12.5
    55.9 x 12.5 = 698.75
    Adding 3.971 to 698.75 = 702.721

     

  • Question 17
    1 / -0

    Order the given temperatures starting with the warmest.

    -42°C, 11°C, -3°C, 46°C, -15°C, 73°C

    Solution

    73°C, 46°C, 11°C, -3°C, -15°C, -42°C is the correct order from the warmest to the coldest.

     

  • Question 18
    1 / -0

    Simplify 14 ÷ (21 ÷ 3) + 7 - 1

    Solution

    Using BODMAS, we have

    14 ÷ (21 ÷ 3) + 7 - 1

    14 ÷ 7 + 7 - 1

    2 + 7 – 1

    8

     

  • Question 19
    1 / -0

    What will be the difference of 74512 and 66142 rounded to the nearest thousand?

    Solution

    Required difference = (74512 - 66142) = 8370
    Difference rounded off to the nearest thousand = 8000

     

  • Question 20
    1 / -0

    Pranav was asked to divide a number by 11. Instead he divided the number by 6 and got the answer as 22. The number to be divided was ____

    Solution

    The number to be divided was 22 × 6 = 132 because the question says he divided a number by 6 and got the answer as 22. So, to find out the number we multiply 6 by 22 to get 132.

     

  • Question 21
    1 / -0

    4 × 10000 + 7 × 100 + 8 × 10 + 2, is the same as

    Solution

    4 × 10000 + 7 × 100 + 8 × 10 + 2 = 40782. This is the correct form of numbers when written.

     

  • Question 22
    1 / -0

    Which of the following is the predecessor of -12?

    Solution

    The predecessor of a whole number is one less than the given number.

    So, the predecessor of -12 is

    -12 - 1 = -13

     

  • Question 23
    1 / -0

    Study the statements given below and select the correct answer.

    Statement 1 - Numbers which are only divisible by 1 and itself are prime numbers.
    Statement 2 - 1 is a prime number.

    Solution

    Statement 1 - Numbers which are only divisible by 1 and itself are prime numbers. This statement is true. For example, 3 , 5 , 7 , etc.

    Statement 2 - 1 is a prime number . This statement is false. As 1 has only one factor, i.e. 1.

     

  • Question 24
    1 / -0

    Find the value of x in the given expression.

    445.21 + 145.71 = x – 215.44

    Solution

    445.21 + 145.71 = x – 215.44

    590.92 = x – 215.44

    x= 590.92+215.44

    x = 806.36

     

  • Question 25
    1 / -0

    Jack had Rs. 54000 in the bank. He wanted to distribute the money among his 3 children; P, Q and R. P gets 3/4 of what Q gets and Q gets 1/5 of what R gets. What would be the share of Q?

    Solution

    Let share of R be Rs. 20a
    So, share of Q = 1/5 × Rs. 20a = Rs. 4a
    Share of P = 3/4 × Rs. 4a = Rs. 3a
    Now, Rs.(3a + 4a + 20a) = Rs. 27a = Rs. 54000
    Or a = 2000
    Thus, share of Q = Rs. 4a = Rs. 4 × 2000 = Rs. 8000

     

  • Question 26
    1 / -0

    What are the composite factors of 42?

    Solution

    Composite numbers are the numbers which are divisible by more than 2 numbers.

    So, factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42

    So, composite factors are = 6, 14, 21 and 42

     

  • Question 27
    1 / -0

    The length of a rectangular room is twice its breadth. If the breadth of the room is 4 m .Find it's area.

    Solution

    Length of the room = 2 × 4 m = 8 m

    Breadth of the room = 4 m

    Area of the rectangular room will be L × B

    8 m × 4 m = 32 m2

     

  • Question 28
    1 / -0

    Ram bought 1 kg cardamom at the rate of Rs. 75.26 per 250 g and 2 kg black pepper at the rate of Rs. 20.37 per 100 g. How much money did he pay?

    Solution

    Cost of 250 g cardamom = Rs. 75.26

    Cost of 1 kg cardamom = Rs 75.26 × 4 = Rs 301.04

    Cost of 100 g black pepper = Rs. 20.37

    Cost of 2 kg black pepper = 20.37 × 20 = Rs. 407.4

    Total money paid = Rs. 301.04 + Rs. 407.4 = Rs. 708.44

     

  • Question 29
    1 / -0

    Shelly got 59 marks in Math, 52 marks in English and 51 marks in Science. John got 48 marks in Math, 32 marks in English and 54 marks in Science. How many marks did they score altogether?

    Solution

    Total marks that Shelly scored in all the three subjects = 59 + 52 + 51 = 162 marks.

    Total marks that John scored in all the three subjects = 48 + 32 + 54 = 134 marks.

    Marks they scored altogether = 162 + 134 = 296 marks.

     

  • Question 30
    1 / -0

    The marks obtained out of 15 by 20 students in a test are listed below:

    6, 8, 9, 14, 11, 13, 10, 8, 7, 10, 12, 10, 14, 5, 8, 4, 12, 13, 8 and 10.

    The number of students whose marks are more than 8 is

    Solution

    Number of students whose marks are more than 8 is 12.

    9, 14, 11, 13, 10, 10, 12, 10, 14, 12, 13 and 10

     

  • Question 31
    1 / -0

    A movie star organised a rock show for charity. The cost of one early bird ticket is Rs. 150.50 and VIP a ticket is Rs. 255.50. He gave away 159 early bird tickets and 108 VIP tickets to children of the charity. What is the total cost of the tickets that he gave away for free?

    Solution

    The cost of one early bird ticket = Rs. 150.50
    Cost of 159 early bird tickets = 159 × Rs. 150.50 = Rs. 23,929.5
    Cost of one VIP ticket = Rs. 255.5
    Cost of 108 VIP tickets = Rs.255.5 × 108 = Rs. 27,594
    So, total cost of tickets he gave away for free =Rs. 23,929.5 + 27,594 = Rs. 51,523.5

     

  • Question 32
    1 / -0

    There was a fair in a school for 2 days. The earning on the first day was Rs. 3657 and on the second day was Rs. 4671. Find the total earning of the school from the fair.

    Solution

    Earning on the first day = Rs. 3657

    Earning on the second day = Rs. 4671

    Total earning = Rs. 3657 + Rs. 4671 = Rs. 8328

     

  • Question 33
    1 / -0

    Fatima scores 2578 points in an online game. To clear that level, she needs 5000 points in total. How many more points does she need to go to the next level of the game?

    Solution

    Total points needed = 5000

    Current points of Fatima = 2578

    Points required = 5000 - 2578 = 2422

     

  • Question 34
    1 / -0

    The number of students in each class of a school is 25. The fee paid by each student is Rs. 812 per month. If there are 40 classes in the school, what is the total fee collected in a month?

    Solution

    Number of students in a class = 25

    Fee paid by 1 student = Rs. 812

    Fee paid by all the students of a class = 25 × 812 = Rs. 20,300

    Total number of classes = 40

    So, total fee collected in a month = 40 × 20,300 = Rs. 8,12,000

     

  • Question 35
    1 / -0

    There are four friends: P, Q, R and S. A sum of money is distribured among the four friends in the ratio 7 : 6 : 5 : 3, respectively. P's share is Rs. 3000 more than R's share. How much money does S get?

    Solution

    Let the shares of P, Q , R and S be Rs. 7x, Rs. 6x, Rs. 5x and Rs. 3x, respectively.

    Now, Rs. (7x – 5x) = Rs. 3000

    2x = 3000

    x = 3000/2

    x = 1500

    Share of S = Rs. 3x = Rs. 3 × 1500 = Rs. 4500

     

  • Question 36
    1 / -0

    The cost of 3 bats and 5 balls is Rs. 2400. The cost of 2 bats and 8 balls is Rs. 3000. How much money is needed to buy 5 balls?

    Solution

    Let the cost of a bat be Rs. x.

    Let the cost of a ball be Rs. y.

    Now, 2 (3x + 5y = 2400)

    3 (2x + 8y = 3000)

    6x + 10y = 4800 ...(i)

    6x + 24y = 9000 ...(ii)

    Subtracting (i) from (ii) and solving for y, we get
    y = 300

    Cost of 5 balls = Rs. 300 × 5 = Rs. 1500

     

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