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IMO - Mock Test - 10

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IMO - Mock Test - 10
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  • Question 1
    1.2 / -0
    Find the missing character in the given pattern.

    Solution
    The pattern is,
    (4 + 5)2 = (9)2 = 81
    (9 + 8)2 = (17)2 = 289
    (4 + 6)2 = (10)2 = 100
    Similarly, (10 + 8)2 = (18)2 = 324
  • Question 2
    1.2 / -0
    What is the sum of fractions of the shaded parts, if the shaded parts are expressed in fractions?

    Solution
    Shaded fraction = =
  • Question 3
    1.2 / -0
    Find the odd one out.
    Solution
    In each option, except (4), there are 5 circles and 2 stars.
  • Question 4
    1.2 / -0
    Complete the number series given below.

    1, 4, 2, 8, 6, 24, 22, 88, (?)
    Solution
  • Question 5
    1.2 / -0
    Rahul put his timepiece on the table in such a way that at 6:00 P.M. the hour hand points towards north. In which direction will the minute hand point at 9:15?
    Solution
  • Question 6
    1.2 / -0
    A, B, C, D, E, F, and G are sitting in a row facing north.

    (i) F is to the immediate right of E.
    (ii) E is fourth to the right of G.
    (iii) C is the immediate neighbour of B and D.
    (iv) The person who is third to the left of D is at one of the ends.

    Who are the immediate neighbours of B?
    Solution
    From the given instructions, the below mentioned arrangement is obtained.
    Note: All are facing in one direction, i.e. north.
    The person who is third to the left of D is at one of the ends.
    C is the immediate neighbor of B and D.
    E is fourth to the right of G.



    F is to the immediate right of E.
    In possibility 2 F cannot be placed to the immediate right of E.
    So, possibility 2 is not correct and canceled.
    If F is towards the right of E then we are left with A.
    Hence the sitting would like the figure given below:

    Hence, C and G are immediate neighbors of B.
  • Question 7
    1.2 / -0
    Some letters are given which are numbered 1, 2, 3, 4 and 5. Find the combination of numbers from the options so that the letters arranged accordingly form a meaningful word.

    Solution
    The word formed is,
  • Question 8
    1.2 / -0
    Ritesh is the son of Varun. Sarika, Varun's sister, has a son Rahul and a daughter Riya. Sahil is the maternal uncle of Rahul. How is Ritesh related to Rahul?
    Solution

    Sarika is the sister of Varun and Rahul is Sarika's son. So, Varun is the maternal uncle of Rahul. Ritesh is the son of Varun. Hence, Ritesh is the cousin of Rahul.
  • Question 9
    1.2 / -0
    Which of the following options will complete the pattern in Figure (X)?

    Solution
  • Question 10
    1.2 / -0
    Select the correct mirror-image of Figure (X) if the mirror is placed vertically to the right.

    Solution
  • Question 11
    1.2 / -0
    Consider the figures X and Y showing a sheet of paper being folded and punched in figure Z. Select the figure which will most closely resemble the unfolded form of figure Z.

    Solution
  • Question 12
    1.2 / -0
    What is the sum of the numbers which belong to only two figures in the given Venn diagram?


    Solution
    Sum of the numbers belonging to only two figures = 7 + 6 + 2 + 8 = 23
  • Question 13
    1.2 / -0
    Which of the following options will exactly make up the Figure (X)?

    Solution
    Figure (X) contains two circles and one dot. Also, there are 2 pairs of four equal lines each. Hence, all these parts are contained in option (1).
  • Question 14
    1.2 / -0
    Which of the following figures will continue the same series as established by the five problem figures.


    Solution
    The element(s) are moving in following pattern:



    The element(s) move(s) forward, a new similar element appears at point of origin (upper left corner) which is 180° degrees rotated version of element at upper right corner.

  • Question 15
    1.2 / -0
    Select the figure from among the options which when placed in the blank space of Figure (X), would complete the pattern.

    Solution
    The pattern of alphabets is:

    Now, the triangles with C and G are mirror images of each other. Similarly, the triangles with A and E will be mirror images of each other.
  • Question 16
    1.2 / -0
    Pranav was asked to divide a number by 11. Instead he divided the number by 6 and got the answer as 22. The number to be divided was ____
    Solution
    The number to be divided was 22 x 6 = 132 because the question says he divided a number by 6 and got the answer as 22. So, to find out the number, we multiply 6 by 22 to get 132.
  • Question 17
    1.2 / -0
    Which of the following is the predecessor of -12?
    Solution
    The predecessor of a whole number is one less than the given number.
    So, the predecessor of -12 is:
    -12 - 1 = -13
    -13 is the answer.
  • Question 18
    1.2 / -0
    If KT = 5 m, TY = KT + 2 m, YP = TY + 2 m, PJ = YP + 2 m, what is the length of KJ?

    Solution
    KT = 5 m, TY = 7 m, YP = 9 m and PJ = 11 m
    Hence, length of KJ = (5 + 7 + 9 + 11) m = 32 m
  • Question 19
    1.2 / -0
    Find the value of x in the given expression.

    445.21 + 145.71 = x – 215.44
    Solution
    445.21 + 145.71 = x – 215.44
    590.92 = x – 215.44
    x = 590.92 + 215.44
    x = 806.36
  • Question 20
    1.2 / -0
    Study the given pattern and find the value of X and Y respectively.


    Solution


    3c + b = 35 (from (vii)) ... (A)
    2b + 2c = 30 (from (iii))
    b + c = 15 ... (B)

    2c + (c + b) = 35 {from A}
    2c + 15 = 35 {using (A) and (B)}
    2c = 20 c = 10 and b = 5
    Now, b + a + 2c = 26 (from (ii))
    5 + a + 20 = 26 a = 1

    Also, b + a + c + d = 18 (from (vi))
    5 + 1 + 10 + d = 18 d = 2
    Hence, X = 2b + c + d = 10 + 10 + 2 = 22
    Y = 3b + c = 15 + 10 = 25
  • Question 21
    1.2 / -0
    If '+' is written as '÷', '-' is written as '+', '×' is written as '-' and '÷' is written as '×', then what is the value of 6 - 4 of 7 + [20 + {5 - (3 - 2)}]?
    Solution
    We have,
    6 - 4 of 7 + [20 + {5 - (3 - 2)}]
    According to the question, we get:
    6 + 4 of 7 ÷ [20 ÷ {5 + (3 + 2)}]
    = 6 + 4 of 7 ÷ [20 ÷ {5 + 5}]
    = 6 + 4 of 7 ÷ [20 ÷ 10]
    = 6 + 4 of 7 ÷ 2 = 6 + 4 of 3.5
    = 6 + 4 × 3.5 = 6 + 14 = 20
  • Question 22
    1.2 / -0
    How many parts should be shaded in Figure Q to make it the same fraction as the unshaded part in Figure P?


    Solution
    Total number of parts in P = 4
    Number of unshaded parts in P = 3
    ∴ Unshaded fraction in P =
    Now,
    Unshaded fraction in P = Shaded fraction in Q

    ∴ Number of shaded parts in Q =
  • Question 23
    1.2 / -0
    Which of the following has/have at least two lines of symmetry?

    Solution


    So, P, Q, R and S all have more than two lines of symmetry.
  • Question 24
    1.2 / -0
    Ali will be 6y years old in 6 years time. How old was Ali 4y years ago?
    Solution
    Age of Ali after 6 years = 6y
    ∴ Present age of Ali = 6y - 6
    So, age of Ali 4y years ago = 6y - 6 - 4y = 2y - 6
  • Question 25
    1.2 / -0
    Express the given expression in the standard form.

    0.0001289 - 0.0000000274 × 1293 + 0.0000419032
    Solution
    We have,
    0.0001289 - 0.0000000274 × 1293 + 0.0000419032
    = 0.0001289 - 0.0000354282 + 0.0000419032
    = 0.000135375
    = 1.35375 × 10-4
  • Question 26
    1.2 / -0
    Prateek, Divyanshu and Manish jog daily in the morning around a rectangular park. They take 3 minutes, 10 minutes and 5 minutes, respectively, to take one complete round. One morning, all of them start at the same time from the same point and jog in the same direction for an hour.

    (a) After how many minutes will all three of them meet again?
    (b) How many times will they meet together during the 1 hour period?

    (a) (b)
    A. 20 minutes 3 times
    B. 25 minutes 2 times
    C. 30 minutes 2 times
    D. 60 minutes 1 time
    Solution
    (a) The time at which they meet again is the L.C.M. of 3, 10 and 5.



    ∴ L.C.M. = 3 × 2 × 5 = 30
    So, they meet after 30 mins.
    (b) In 1 hour period, they meet 2 times.
  • Question 27
    1.2 / -0
    The given table shows the temperature of a country for 7 consecutive hours.

    Hour 1 2 3 4 5 6 7
    Temperature (°C) -6 15 -2 23 12 0 -4

    Calculate the difference between the highest and the lowest temperature of the country over the 7-hour period.
    Solution
    Highest temperature = 23°C
    Lowest temperature = -6°C
    ∴ Difference = 23°C - (-6°C) = 29°C
  • Question 28
    1.2 / -0
    Select the figure from the options that will replace the question mark(?) in the problem figure and continue the pattern.


    Solution
    The pattern is,
    9O - 6O = 3O
    6O - 4O = 2O
    ∴ 3O - 2O = 1O
    Here, O is shape in question figure.
  • Question 29
    1.2 / -0
    If 3 × 6 = 18; 4 × 7 = 22; 9 × 1 = 20, then 5 × 2 = ?
    Solution
    The pattern is,
    3 × 6 = 18 = (3 + 6) × 2
    4 × 7 = 22 = (4 + 7) × 2
    9 × 1 = 20 = (9 + 1) × 2
    So, 5 × 2 = (5 + 2) × 2 = 14
  • Question 30
    1.2 / -0
    Select the correct match.
    Solution
    LXV = 50 + 10 + 5 = 65 ≠ 75
    LXIX = 50 + 10 + 9 = 69 ≠ 79
    XCVIII = 90 + 8 = 98
    LXXX = 50 + 30 = 80 ≠ 90
  • Question 31
    1.2 / -0
    Express the number of storybooks that Mohit read in December as a fraction of the total number of storybooks read in four months.

    Solution
    Total number of books that Mohit read in 4 months = 4 + 2 + 10 + 8 = 24
    Number of books read in December = 8
    Required fraction =
  • Question 32
    1.2 / -0
    Sara is counting by 3's. If she starts counting at -30, what are the two missing numbers?

    Solution
  • Question 33
    1.2 / -0
    Which of the following statements about the 3-dimensional figure appears to be true?

    Solution
    The given figure has 3 congruent rectangular and 2 congruent triangular faces.
  • Question 34
    1.2 / -0
    Which equation does this set of algebra tiles represent?


    Solution
    According to the question,
    L.H.S. = X + 1 + 1 + 1 + 1 + 1 + 1 = X + 6
    R.H.S. = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 10
    Hence, we get X + 6 = 10
  • Question 35
    1.2 / -0
    Find the value of (24 - 16) × 8 - 64 ÷ (10 - 2) + 4.
    Solution
    Applying BODMAS rule, we have:
    (24 - 16) × 8 - 64 ÷ (10 - 2) + 4
    = 8 × 8 - 64 ÷ 8 + 4
    = 8 × 8 - 8 + 4
    = 64 - 8 + 4
    = 56 + 4
    = 60
  • Question 36
    1.2 / -0

    Directions For Questions

    Directions: Look at the bar graph and answer the following question.

    ...view full instructions

    How many cars were sold in the last quarter of the year?
    Solution


    Cars sold in last quarter of the year, i.e. in Oct., Nov. and Dec. = 35 + 50 + 20 = 105
  • Question 37
    1.2 / -0
    Zarrin collected 1346 eggs. 38 of them were broken. She sold the rest at Rs. 8 each. What was the total collection from her sale of the eggs?
    Solution
    Total number of eggs = 1346
    Number of broken eggs = 38
    ∴ Remaining number of eggs = 1346 - 38 = 1308
    Cost of 1 egg = Rs. 8
    So, cost of 1308 eggs = 8 × 1308 = Rs. 10,464
  • Question 38
    1.2 / -0
    Beena bought 12 kg of sugar. After filling 11 containers of the same size, she had 3.2 kg left. How much sugar was there in each container?
    Solution
    Total quantity of sugar = 12 kg
    Let the quantity of sugar in each container be x.
    According to question,
    11 × x + 3.2 = 12
    11x = 12 - 3.2 = 8.8 x = 0.8
    So, amount of sugar in each container = 0.8 kg
  • Question 39
    1.2 / -0
    A bottle is 3/4 full of water. The water in the bottle can fill 5 glasses. If the water in the bottle is poured out to fill 3 glasses, find the fraction of the water left in the bottle.
    Solution
    Fraction of water that filled 5 glasses = of bottle
    ∴ Fraction of water that filled 1 glass = of bottle
    ∴ Fraction of water that filled 3 glasses = of bottle
    So, fraction of water left
    =
  • Question 40
    1.2 / -0
    Mini has some pencils. If she gives 3 pencils to each pupil, she will have 20 pencils left. If she gives 4 pencils to each pupil, she will have none left. How many pencils does she have?
    Solution
    Let the total number of pupils be x.
    According to question,
    3x + 20 = 4x
    x = 20
    So, total number of pencils = 3 × 20 + 20 = 60 + 20 = 80
  • Question 41
    1.2 / -0
    Abhay found the perimeter of a square to be 12 metres. Which of the following could be used to find the length (l) of one edge of the square?
    Solution
    Perimeter of square = 4 × Length of side
    12 = 4 × Length of side
    Length of side (l) = 12 ÷ 4
  • Question 42
    1.2 / -0
    Armaan was asked to multiply a number by 25. Instead, he multiplied the number by 52 and got the answer 324 more than the correct answer. The number to be multiplied was _____.
    Solution
    Let the number be x.
    Original multiplication = 25x
    Multiplication done by Armaan = 52x
    ∴ According to question,
    52x - 25x = 324
    27x = 324 x = 324 ÷ 27 = 12
  • Question 43
    1.2 / -0
    The weekly milk order of Aryan's shop includes 40 litres of low-fat milk and 15 litres of chocolate milk. What is the ratio of the litres of low-fat milk to chocolate milk in Aryan's weekly milk order?
    Solution
    Quantity of low-fat milk = 40 litres
    Quantity of chocolate milk = 15 litres
    Required ratio = 40 : 15 = 8 : 3
  • Question 44
    1.2 / -0
    A square shaped floor tile has length of 25 cm each. How many tiles will be needed for a rectangular lawn 12 m long and 10 m wide? Find the total cost at the rate of Rs. 8 per tile.
    Solution
    Area of 1 square tile = 25 × 25 = 625 cm2
    Length of lawn = 12 m = 12 × 100 cm = 1200 cm
    Breadth of lawn = 10 m = 10 × 100 cm = 1000 cm
    ∴ Area of lawn = 1200 × 1000 = 12,00,000 cm2
    So, required number of tiles = = 1920
    Now, cost of 1 tile = Rs. 8
    ∴ Total cost = Rs. (8 × 1920) = Rs. 15,360
  • Question 45
    1.2 / -0
    Your mother says, ''To calculate your pocket money, multiply your age by itself and then double it''. If your age is x years, write an algebraic expression representing your pocket money. How much do you get as pocket money if your age is 11 years?
    Solution
    Let the age be x.
    According to question,
    Multiply age by itself = x × x = x2
    Doubling it: 2x2
    So, pocket money = 2x2
    Now, if x = 11, then:
    Pocket money = 2 × 11 × 11 = 2 × 121 = Rs. 242
  • Question 46
    1.2 / -0
    A lady parked her car on the 6th floor and took a lift 17 floors up to the Finance Department. She then went down 9 floors to the Tax Department. On which floor would you find the lady?
    Solution
    Floor on which car is parked = 6th
    Floor of Finance department = 6 + 17 = 23rd
    Floor of Tax department = 23 - 9 = 14th
    ∴ Lady is on the 14th floor.
  • Question 47
    1.2 / -0
    If the temperature of City A is -20° C and the temperature of City B is 10°C, the difference in the temperatures of the two cities is _____.
    Solution
    Temperature of City A = -20°C
    Temperature of City B = 10°C
    Difference between temperature of two cities = 10°C - (-20°C) = 10°C + 20°C = 30°C
  • Question 48
    1.2 / -0
    Fill in the blank:

    A _____ of a circle is a region in the interior of the circle enclosed by an arc and a chord.
    Solution
    A segment of a circle can be defined as a region bounded by a chord and a corresponding arc lying between the chord's endpoints. In other words, chord of a circle divides the circle into two regions, which are called the segments of the circle. The minor segment is the region bounded by the chord and the minor arc intercepted by the chord. The major segment is the region bounded by the chord and the major arc intercepted by the chord.

  • Question 49
    1.2 / -0
    Match the columns:

    Column - I
    (Figure)
    Column - II
    (Shaded Fraction)
    (p) (i) Two-fifths
    (q) (ii) One-half
    (r) (iii) One-fourth
    (s) (iv) One-third
    Solution
    (p) Total number of equal parts = 8
    Number of shaded parts = 2
    ∴ Shaded fraction = = One-fourth

    (q) Total number of equal parts = 10
    Number of shaded parts = 4
    ∴ Shaded fraction = = Two-fifth
    (r) Total number of equal parts = 6
    Number of shaded parts = 2
    Shaded fraction = = One-third

    (s) Total number of equal parts = 12
    Number of shaded parts = 6
    ∴ Shaded fraction = = One-half
  • Question 50
    1.2 / -0
    At a park, Ashmit intends to hire a buggy to help him get around more easily. The table shows the rate for hiring a buggy.

    Deposit Rs. 24
    First hour Rs. 12
    Every additional hour and part thereof Rs. 10

    Ashmit intends to hire the buggy from 8:15 a.m. to 2:30 p.m. How much does he have to pay?
    Solution
    Total time from 8:15 a.m. to 2:30 p.m = 6 hrs 15 mins
    ∴ Total amount paid = Rs. (24 + 12 + 5 × 10 + 10)
    = Rs. 96
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