IMO - Mock Test

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IMO - Mock Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

If in a certain code, "APPLE" is written as "PAELP", then how is "MANGO" coded in that language?

A
GOMAN

B
ANGOM

C
AMOGN

D
MANOG

Solution

The position of the first two letters is interchanged. Also, the letters at the third, fourth and fifth position are written in reverse order after that.
Question 2
1 / -0

Zack is taller than Priya but shorter than Rena. Olivia is taller than Rena, who is taller than Joe. Who is the tallest?

A
Rena

B
Olivia

C
Zack

D
Priya

Solution

Zack is taller than Priya but shorter than Rena.

Rena > Zack > Priya ... (i)

Olivia is taller than Rena, who is taller than Joe.

Olive > Rena > Joe ....(ii)

From (i) and (ii),

Olivia > Rena > Zack > Priya > Joe

Or, Olivia > Rena > Joe > Zack > Priya

Hence, Olivia is the tallest among all.
Question 3
1 / -0

What is the rule for the following pattern?

1, 4, 9, 16, 25, 36, .......

A
Add 0, then add 4, then add 5, then 10 and so on.

B
Add 2, then add 4, then add 6, then add 8, then add 10 and so on.

C
Multiply by 1, then add 4 and so on.

D
Add the odd number starting with adding 3, then add 5, then add 7 and so on.

Solution

1 + 3 = 4

4 + 5 = 9

9 + 7 = 16

16 + 9 = 25

25 + 11 = 36
Question 4
1 / -0

If 'Water' is coded as 'Blue'. 'Blue' is coded as Yellow'. 'Yellow' is coded as 'White'. 'White' is coded as 'Sky'. 'Sky' is coded as 'Rain', then which of the following is the colour of 'Milk'?

A
Sky

B
White

C
Blue

D
Yellow

Solution

Colour of 'Milk' is 'White'. Here, 'White' is coded as 'Sky'.

So, the colour of 'Milk' is 'Sky'.
Question 5
1 / -0

Find the odd one out from the given alternatives.

A
17

B
27

C
37

D
61

Solution

27 is different from other numbers as it is not a prime number. All other numbers are prime numbers.
Question 6
1 / -0

If T = EO and O = JE, then J = E __?

A
E

B
J

C
O

D
T

Solution

T = 20(E = 5 + O = 15)
O = 15(J = 10 + E = 5)
J = 10(E = 5 + E = 5)
So, J = EE
Question 7
1 / -0

Write the prime factorisation of a number obtained by dividing 4200 with 2.

A
2 x 3 x 5

B
2 x 5 x 10 x 7

C
3 x 7 x 10²

D
2²x 3 x 5² x 7

Solution

4200 divided by 2 is 2100. Now, the prime factorisation will be 2²x 3 x 5² x 7.
Question 8
1 / -0

If x + 70 = y + 30, then which of the following is true?

A
y < x

B
x > y

C
y > x

D
x = 0

Solution

X + 70 = y + 30

= x - y = 30 - 70

= x - y = -40

Or, y - x = 40, which means that y > x (Only then will the answer be a positive number)
Question 9
1 / -0

Subtract 31.256 from 15.67 x 22.6?

A
321.896

B
321.900

C
321.925

D
322.886

Solution

15.67 x 22.6 = 354.142

Now, 354.142 – 31.256 = 322.886
Question 10
1 / -0

Find the value of the given expression?

8(6 + 5) - 23 + 5(6 - 5) + 12

A
128

B
104

C
96

D
82

Solution

Here, we have 8(6 + 5) - 23 + 5(6 - 5) + 12.

Following BODMAS order,

8(11) – 23 + 5(1) + 12

88 - 23 + 5 + 12

105 - 23 = 82
Question 11
1 / -0

Class 6 has two sections A and B. In section A, there are 50 students and each student gets Rs. 10 as pocket money. In B section, there are 20 students and each student gets Rs. 100 as pocket money. What is the difference between the total pocket money for both the sections?

A
90

B
240

C
400

D
420

Solution

Total pocket money of section A = 50 × 10 = 500

Total pocket money of section B = 100

So, difference between the total pocket money of both the sections = 500 - 100 = 400
Question 12
1 / -0

If the 1^st and 3^rd positions of the digits of all the following numbers are interchanged, find the sum of the digits of the smallest number.

254, 369, 457, 951

A
15

B
14

C
11

D
10

Solution

On interchanging 1^st and 3^rd positions of the all the numbers, we get

452, 963, 754, 159

So, the sum of all the digits of number 159 is 1 + 5 + 9 = 15
Question 13
1 / -0

If the cost of 8 balloons is 64 paise, then how many balloons can be bought in Rs. 2?

A
25

B
50

C
128

D
136

Solution

Cost of one balloon is given by 64/8 = 8 paise

Number of balloons bought in Rs. 2 = 200/8 = 25
Question 14
1 / -0

Which of the following is a perfect square?

A
1372

B
1521

C
1768

D
1852

Solution

A perfect square is a number that can be expressed as the product of two equal integers.
A perfect square always ends with 0, 1, 4, 5, 6 and 9.
1521 = 39 x 39
Hence, it is a perfect square.
Question 15
1 / -0

What would be the measure of the fourth angle of a quadrilateral if other three angles are each of 75^o?

A
132^o

B
135^o

C
136^o

D
138^o

Solution

75^o + 75^o + 75^o + x = 360^o

225^o + x = 360^o

x = 360^o - 225^o = 135^o
Question 16
1 / -0

Subtract 567 from 689 and write the answer in roman numerals.

A
MXXII

B
IXXII

C
CXXII

D
CXIIX

Solution

689 – 567 = 122

So, X = 10

C = 100

I = 1

So, 122 = CXXII
Question 17
1 / -0

Mr. Reginald purchased a land rectangular in shape. If the perimeter is 150 m, then what would be its length if its width is 25 m?

A
5 m

B
45 m

C
50 m

D
55 m

Solution

Perimeter = 2(l + b)

150 = 2(l + 25)

75 = l + 25

l = 75 - 25

l = 50 m
Question 18
1 / -0

How much sand can a cuboidal box of dimensions 12 cm, 8 cm and 6 cm hold?

A
854 cm³

B
576 cm³

C
357 cm³

D
257 cm³

Solution

Amount of sand that the box can hold = Capacity of the box
So, capacity of the box = 12 × 8 × 6 cm³ = 576 cm³
Question 19
1 / -0

Mike bought 9 books about plants and 2 books about fish. He also bought 9 science magazines. Each book costs Rs. 1,014 and each magazine costs Rs. 171. How much did Mike spend in all?

A
Rs. 12,693

B
Rs. 12,694

C
Rs. 12,695

D
Rs. 12,696

Solution

Step 1: Find the total number of books.

9 + 2 = 11

Step 2: Find the cost of the books.

Rs. 1,014 × 11 = Rs. 11,154

Step 3: Find the cost of the magazines.

Rs. 171 × 9 = Rs. 1,539

Step 4: Find the total cost.

Rs. 1,539 + Rs. 11,154 = Rs. 12,693

Mike spent Rs. 12,693.
Question 20
1 / -0

For breakfast, Darell bought a bagel for Rs. 131.50 and a glass of orange juice for Rs. 138.00. At lunch, Darell spent Rs. 484.00 on a sandwich and Rs. 69.00 on a carton of milk. How much more money did Darell spend on lunch than on breakfast?

A
Rs. 283.50

B
Rs. 284.50

C
Rs. 285.50

D
Rs. 286.50

Solution

Step 1: Find the total cost of breakfast.

Rs. 131.50 + Rs. 138.00 = Rs. 269.50

Step 2: Find the total cost of lunch.

Rs. 484.00 + Rs. 69.00 = Rs. 553.00

Step 3: Find how much more lunch cost than breakfast.

Rs. 553.00 – Rs.269.50 = Rs. 283.50

So, Darell spent Rs. 283.50 more on lunch.
Question 21
1 / -0

Manav cut trees in a forest. He cut trees at the rate of 5 trees per minute. How many trees would be cut in 24 hours?

A
7200

B
5000

C
300

D
120

Solution

Number of trees that he cut in 1 minute = 5

1 hour = 60 minutes

Therefore, number of trees that he cut in 24 hours (24 × 60 minutes) = 24 × 60 × 5 = 7200
Question 22
1 / -0

Robbie's dog eats 0.4 kg dog food each day. How much dog food will Robbie's dog eat in 9 days?

A
3.6 kg

B
12.2 kg

C
15.5 kg

D
19.2 kg

Solution

Multiply the amount of dog food the dog eats each day by the number of days.

Multiply as you would multiply whole numbers.

0.4 × 9 = 3

Robbie's dog will eat 3.6 kg of dog food in 9 days.
Question 23
1 / -0

Ernesto and Roscoe hung out at the mall on Saturday. They spent 1 hour and 15 minutes shopping for clothes and 1 hour and 15 minutes at the food court. Then, they spent 1 hour and 45 minutes at the video arcade before heading home. If it was 10:00 A.M. when Ernesto and Roscoe started shopping for clothes, what time was it when they left the mall?

A
2:15 P.M.

B
1:45 P.M.

C
12:15 P.M.

D
11:15 P.M.

Solution

Add the time to find the total elapsed time.

1 h 15 min + 1 h 15 min + 1 h 45 min = 4 h 15 min

Now, find 4 hours and 15 minutes after 10:00 A.M.

Add 4 hours to 10:00 A.M. This is 2:00 P.M.

Now, add 15 minutes to 2:00 P.M. This is 2:15 P.M.

It was 2:15 P.M. when Ernesto and Roscoe left the mall.
Question 24
1 / -0

Katie is driving from Lexington to Rockport, a total distance of 48.2 km. She stops at Seaside to get petrol. It is 5 km from Lexington to Seaside. How much further does she have left to drive?

A
43.2 km

B
44.2 km

C
46.2 km

D
47.2 km

Solution

Subtract the numbers of kilometres. Remember to line up the decimal points. You can write extra zeroes to make equivalent decimals.

48.2 - 5.0 = 43.2

Katie has another 43.2 km left to drive.
Question 25
1 / -0

Paras caters for three events, for which he is paid Rs. 718, Rs. 890 and Rs. 723. His total expenditure (cost of ingredients, to pay the people who work for him, for petrol and so on) is Rs. 823. How much profit does he make?

A
Rs. 1500

B
Rs. 1508

C
Rs. 1408

D
Rs. 1400

Solution

Total money that he gets for the three events = Rs. (718 + 890 + 723) = Rs. 2331
Profit = Income (money he gets for three events) – Expenditure (his cost)
= 2331 – 823 = Rs. 1508
Question 26
1 / -0

Harideep knows that it will take 7 minutes to prepare each dessert for an event. He needs to make 27 desserts (and only he can do them). When they are all prepared, they need to bake for 30 minutes. How much time will he need to prepare all the desserts and bake them?

A
189 minutes

B
219 minutes

C
221 minutes

D
250 minutes

Solution

Time required for preparation of 27 desserts = 27 x 7 = 189 minutes

Now, he needs to add 30 minutes more as the time to bake. So, total time required = 189 + 30 = 219 minutes.
Question 27
1 / -0

One of Hari's customers wants to know how many calories are there in a piece of cake. Hari works out that there were a total of 8800 calories in five identical cakes. Each cake is cut into eight equal pieces. How many calories are there in a piece of cake?

A
160

B
220

C
222

D
228

Solution

Amount of calories in cake = 8800 ÷ 5 = 1760

Amount of calories in one piece of cake = 1760 ÷ 8 = 220
Question 28
1 / -0

In monthly tests, marks scored by a student in different subjects are as follows.

24, 16, 28, 18, 25, 20

What is the percentage marks scored by the student if all the exams have a maximum score of 40?

A
56.45%

B
54.58%

C
52.56%

D
51.83%

Solution

Total marks scored by the student = 24 + 16 + 28 + 18 + 25 + 20 = 131Total maximum marks = 40 × 6 = 240Percentage scores marked =

131/240 × 100

= 54.58%
Question 29
1 / -0

In a class, there are 45 students. 30 of them are boys. The average weight of all the boys in a class is 50 kg and the average weight of the girls is 40 kg. What would be the average weight of all the students in the class?

A
46.67 kg

B
45 kg

C
44 kg

D
42.67 kg

Solution

Let the weight of all boys = b

Let the weight of all girls = g

b/30 = 50

b = 50 × 30

b = 1500 kg

Total number of girls = 45 – 30 = 15

g/15 = 40

g = 40 × 15

g = 600 kg

Total weight of all the students = 1500 + 600

= 2100 kg

Average weight of all the students = 2100/45 = 46.67 kg
Question 30
1 / -0

Study the statements given below and choose the correct answer.

Statement 1 - A mixed number is a number consisting of an integer and a proper fraction.
Statement 2 - Improper fractions are top heavy fractions.

A
Statement 1 is true and statement 2 is false.

B
Statement 1 is false and statement 2 is true.

C
Both statements are true.

D
Both statements are false.

Solution

A mixed number is a number consisting of an integer and a proper fraction. For example - 3 7/11.
An improper fraction has a top number larger than (or equal to) the bottom number.

They are also known as top heavy fractions. For example - 7/4.

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Re-Attempt Weekly Quiz Competition

IMO - Mock Test - 4

Result

IMO - Mock Test - 4

Score

-

Rank

-

SHARING IS CARING

Question 1

GOMAN

ANGOM

AMOGN

MANOG

Solution

Question 2

Rena

Olivia

Zack

Priya

Solution

Question 3

Add 0, then add 4, then add 5, then 10 and so on.

Add 2, then add 4, then add 6, then add 8, then add 10 and so on.

Multiply by 1, then add 4 and so on.

Add the odd number starting with adding 3, then add 5, then add 7 and so on.

Solution

Question 4

Sky

White

Blue

Yellow

Solution

Question 5

17

27

37

61

Solution

Question 6

E

J

O

T

Solution

Question 7

2 x 3 x 5

2 x 5 x 10 x 7

3 x 7 x 102

22 x 3 x 52 x 7

Solution

Question 8

y < x

x > y

y > x

x = 0

Solution

Question 9

321.896

321.900

321.925

322.886

Solution

Question 10

128

104

96

82

Solution

Question 11

90

240

400

420

Solution

Question 12

15

14

11

10

Solution

3 x 7 x 10²

2²x 3 x 5² x 7

132^o

135^o

136^o

138^o

854 cm³

576 cm³

357 cm³

257 cm³