Question 1 1.2 / -0
If 687 + 509 = 560897, then 619 + 703 = ?
Solution
We have,
Similarly,
Question 2 1.2 / -0
Find out from the options, which is the mirror-image of the given word, if the mirror is placed vertically right. CONTENTS
Question 3 1.2 / -0
How many flowers will be there in Pattern 6?
Solution
The pattern is, Number of flowers in Pattern 1 = 1 + 0 = 1 Number of flowers in Pattern 2 = 3 + 2 = 5 Number of flowers in Pattern 3 = 5 + 4 + 3 = 12 Number of flowers in Pattern 4 = 7 + 6 + 5 + 4 = 22 Number of flowers in Pattern 5 = 9 + 8 + 7 + 6 + 5 = 35 Number of flowers in Pattern 6 = 11 + 10 + 9 + 8 + 7 + 6 = 51
Question 4 1.2 / -0
Count the number of cubes in the given figure.
Solution
Total number of cubes = 5
Question 5 1.2 / -0
Find the missing figure so that the series formed by problem figures is continued.
Solution
One semi-circle gets rotated by 180° in each of the subsequent figure in counter-clockwise direction.
Question 6 1.2 / -0
Given below is the generation tree of X. He has _____ great grandsons.
Solution
There is no great grandson of X as X only has son and grandson.
Question 7 1.2 / -0
Identify the shape which is NOT exactly embedded in Figure (X).
Solution
Figures given in options (ii), (iii) and (iv) are embedded as shown above in the diagram.
Question 8 1.2 / -0
Read the information given below and answer the question that follows. P * Q means P and Q are of the same age. P - Q means Q is younger than P. P + Q means P is younger than Q. Shreya * Meena - Priti means
Solution
Shreya * Meena - Priti means Shreya and Meena are of the same age and Priti is younger than Shreya and Meena. So, Priti is the youngest.
Question 9 1.2 / -0
There is a certain relationship between figures (P) and (R). Establish the similar relationship between figures (Q) and (S) and find the missing figure.
Solution
The pattern followed between R and P is
According to the same analogy, we have
Question 10 1.2 / -0
Which net will make this figure?
Solution
The given figure has 4 rectangular faces and 2 square faces. So, option (2) is correct
Question 11 1.2 / -0
Statement 1- Class A has higher enrolment than Class B. Statement 2- Class C has a lower enrolment than Class B. Statement 3- Class A has a lower enrolment than Class C. If the first two statements are true, then the third statement is _______.
Solution
According to the given information, A > B C < B A < C The descending order of the number of students in the classes is, A > B > C So, the third statement is false.
Question 12 1.2 / -0
Which number will be on the face opposite to the face which has 2 dots on it?
Solution
Numbers on adjacent faces of 2 are 5, 3 and 1. Taking dice 1st and 2nd and counting in anti-clockwise direction, we have 5 - 3 - 2 5 - 4 - 6 So, 6 is on the opposite face of 2.
Question 13 1.2 / -0
Study the diagram and identify the students who play all the three games.
Solution
Student S is in common region of Football, Kabbaddi and Cricket. So, student S plays all the three games.
Question 14 1.2 / -0
If husband is called wife, wife is called grandfather, grandfather is called grandmother, grandmother is called maternal grandmother, maternal grandmother is called maternal grandfather, maternal grandfather is called maternal uncle, and maternal uncle is called maternal aunt, then what will the father of the mother be called?
Solution
The father of the mother is called maternal grandfather and maternal grandfather is called maternal uncle. So, the father of the mother will be called maternal uncle.
Question 15 1.2 / -0
Find the figure from the given options which completes the pattern in fig. (X).
Question 16 1.2 / -0
Minimum number of straight lines required to draw the given figure is ______.
Solution
Number of straight lines used to make 3 triangles is 9. Total straight lines drawn = 9 + 7 = 16 (not-triangles)
Question 17 1.2 / -0
In the given series, how many pairs of alternate numbers have a difference of 2? 6 4 1 2 2 8 7 4 2 1 5 3 8 6 2 1 7 1 4 1 3 2 8 6
Solution
We have,
So, there are 2 such pairs.
Question 18 1.2 / -0
In the given question, a series of small letters which follows a pattern where some letters are missing is given. Find the missing letters so that a proper sequence of letters is formed. ab _ _ _ b _ bbaa _
Solution
The sequence is, ab b a a b a bbaab The pattern repeated is abb / aab / abb / aab.
Question 19 1.2 / -0
The weights of three boys are
kg,
kg and
kg. Total weight of the three boys is _____.
Solution
Total weight of three boys =
=
=
kg
Question 20 1.2 / -0
Subtract 29.375 from the sum of 85.75 and 5.9.
Solution
Sum of 85.75 and 5.9 = 85.75 + 5.90 = 91.65 Now, difference = 91.650 - 29.375 = 62.275
Question 21 1.2 / -0
To balance the scale, write the missing fraction.
Solution
Let x be the missing fraction.
Then, we have
So, required fraction =
Question 22 1.2 / -0
Arrange the following in ascending order. P: Eight thousand six hundred fifty two Q: Ninety six thousand seven hundred forty one R: Fifty nine thousand nine hundred eighty six S: Eighty two thousand nine hundred six
Solution
P = 8652, Q = 96741, R = 59986, S = 82906 So, ascending order is, 8652, 59986, 82906, 96741 i.e. P, R, S, Q
Question 23 1.2 / -0
Look at the graph.
On which day did Kirti receive the fewest text messages?
Solution
Messages received by Kirti on Sunday = 90 Messages received by Kirti on Monday = 100 Messages received by Kirti on Tuesday = 100 Messages received by Kirti on Wednesday = 60 Messages received by Kirti on Thursday = 100 Messages received by Kirti on Friday = 100 Messages received by Kirti on Saturday = 70 So, Kirti received fewest messages on Wednesday.
Question 24 1.2 / -0
A coach conducted a survey to determine how many students plan to tryout tennis and golf. The results of the survey are shown below. (i) A total of 30 students plan to try out tennis. (ii) A total of 40 students plan to try out golf. (iii) 10 students plan to try out both tennis and golf. Which of the following diagrams best represents this information?
Solution
Total number of students who plan to try out tennis = 20 + 10 = 30 Total number of students who plan to try out golf = 30 + 10 = 40 Also, 10 students plan to try out both tennis and golf So, option (1) satisfies all given conditions.
Question 25 1.2 / -0
Sneha bisects an angle to form two new angles. If the original angle had a measure of 8°, what is the measure of each new angle?
Solution
Measure of angle = 8°
Measure of each bisected angle =
= 4°
Question 26 1.2 / -0
Rehan attended a basketball camp for two weeks. His parents paid Rs. 50.00, which was
the cost of attending the camp. Rehan had saved money to pay the rest of the cost. Which equation can be used to find c, the entire cost of attending the camp?
Solution
Let total cost be 'c'.
Cost paid = Rs. 50
According to question, we have
of c = 50
× c = 50
c = 50 × 3
Question 27 1.2 / -0
What is the value of p + q from the given number line?
Solution
Here, 15 units in 5 divisions, i.e. 1 division = 3 units So, p = - 9 and q = 3 ∴ p + q = - 9 + 3 = - 6.
Question 28 1.2 / -0
Fill in the blank 1 million = ______ hundred thousand
Solution
1 million = 1000000 = 10,00,000 = Ten hundred thousand
Question 29 1.2 / -0
Which of the following statements is CORRECT?
Solution
(1) 0 is a whole number, but not a natural number. So, all whole numbers are not natural numbers. (2) 1 is a natural number with no predecessor. (3) x divide by 0 is ∞ ( not defined). (4) 0 is a whole number with no predecessor.
Question 30 1.2 / -0
The sum of the prime factors of 63 is ______.
Solution
Prime factors of 63 = 3 and 7
Sum = 3 + 7 = 10
Question 31 1.2 / -0
The fractional number corresponding to the given number ''9 tens + 5 ones + 3 tenths + 7 hundredths'' is _______.
Solution
We have, 9 tens + 5 ones + 3 tenths + 7 hundredths
= 90 + 5 +
Question 32 1.2 / -0
ABCD and PQRS are two squares of same dimensions. Find the area of shaded part.
Solution
The given figure is
After rearrangement, the given figure becomes,
Here PS = AB = 7 + 7 = 14 cm
So, area of shaded part = area of square PQRS
= PS × PS = 14 × 14
= 196 cm
2
Question 33 1.2 / -0
If
of a number is 63, then
of the number is _________.
Solution
Let the number be x.
Now,
of x = 63
So,
of 81 =
= 27
Question 34 1.2 / -0
Priya had Rs. 50. After buying 5 identical pens, she was left with Rs. y. The cost of 1 pen in terms of y is _____.
Solution
Amount of money Priya had = Rs. 50
According to question,
Cost of 5 pens + Money left = Rs. 50
5 × cost of 1 pen = 50 - y
Cost of 1 pen =
Rs.
Question 35 1.2 / -0
The given square PQRS is made up of 4 smaller squares. What is the ratio of the area of the shaded part to the area of the unshaded part?
Solution
Number of equal parts = 4
Number of shaded part = 1
Number of unshaded parts = 3
Let the side of each square be x units.
Shaded area = 1 × x × x = x
2 sq. units.
Also, unshaded area = 3 × x × x = 3x
2 sq. units
So, required ratio = x
2 : 3x
2 = 1 : 3
Question 36 1.2 / -0
On Monday, there were thrice as many peanuts in Sack X as in Sack Y. On Tuesday, 3952 peanuts in Sack X were sold. Now there were thrice as many peanuts in Sack Y as Sack X. How many peanuts were there in Sack X at first?
Solution
Let the number of peanuts in Sack Y be x.
Then, the number of peanuts in Sack X = 3x
According to question,
x = 3(3x - 3952)
x = 9x - 3 × 3952
8x = 3 × 3952
x = 1482
So, the number of peanuts in sack X = 1482 × 3 = 4446
Question 37 1.2 / -0
The length of a rectangular hall is 5 metres more than its breadth. If the breadth of the hall is 25 metres, then area of the hall is ________.
Solution
Breadth of the hall = 25 m
Length of the hall = 25 + 5 = 30 m
Area of the hall = 30 × 25 = 750 m
2
Question 38 1.2 / -0
How many minimum squares must be shaded to make the given figure symmetric?
Solution
For horizontal line of symmetry only 2 squares must be shaded.
Question 39 1.2 / -0
Mrs. Khan had m eggs. She used 5 eggs to bake a cake and gave 6 eggs to her neighbour. How many eggs was she left with?
Solution
Number of eggs Mrs. Khan had = m Number of eggs she used to bake the cake = 5 Number of eggs she gave to her neighbour = 6 Number of eggs left with her = m - (5 + 6) = m - 11
Question 40 1.2 / -0
Latika's monthly salary was Rs. 30,525. She spent Rs. 1800 and saved the rest. How much did she save in a year?
Solution
Monthly salary = Rs. 30,525 Amount spent by Latika = Rs. 1800 ∴ Amount saved in 1 month = 30,525 – 1800 = 28,725 So, amount saved in 1 year = 12 × 28,725= Rs. 3,44,700
Question 41 1.2 / -0
Mr. Kapoor left his office at 15:45 to attend a 3-hour seminar in Delhi. He took 2 hours 20 minutes to drive there, but he was 25 minutes late for the seminar. At what time did the seminar end?
Solution
Time at which Mr. Kapoor left the office = 15:45
Time taken to drive = 2 hours 20 minutes
Time at which he reached the seminar hall = 18:05
So, time at which the seminar started was 25 mins before 18:05 = 17:40
Duration of the seminar = 3 hours
Time at which the seminar ended = 20:40
Question 42 1.2 / -0
Shalini spent Rs. 835.75 on buying clothes, Rs. 309.15 on buying fruits and vegetables, Rs. 168.90 on buying sweets and Rs. 60.50 on transport. She had 3 five hundred rupee notes in her purse. How much money was left with her?
Solution
Total money spent = Rs. (835.75 + 309.15 + 168.90 + 60.50)
= Rs. 1374.30
Amount in the purse = (3 × 500) = Rs. 1500
Amount left = Rs. (1500 - 1374.30) = Rs. 125.70
Question 43 1.2 / -0
A wheel barrow can hold _______ kg, if four rocks weighing
kg,
kg,
kg and
kg are to be loaded into the wheel barrow.
Solution
Capacity of wheel barrow =
=
=
kg
Question 44 1.2 / -0
Which relationship between units of time is correct?
Solution
We know that,
60 seconds = 1 minute
1 second =
minute
So, 1 second is
of one minute.
Question 45 1.2 / -0
Rohan rolled 3 fair number cubes, and the numbers shown below came out on top.
If each number is used only once, then which group shows all the 3-digit numbers that can be made with these digits?
Solution
The numbers formed from digits 4, 5, 6 are 456, 465, 564, 546, 645, 654.
Question 46 1.2 / -0
Fill in the blanks. Any drawing (straight or non-straight) done without lifting the pencil may be a __P_ _. A/An __Q_ _ is the one that does not cross itself. A curve is said to be __R_ _, if its ends are joined. A __S__ is a simple closed curve made up of line segments.
Solution
Any drawing done without lifting the pencil may be a curve . A/An simple curve is the one that does not cross itself. A curve is said to be closed , if its ends are joined. A polygon is a simple closed curve made up of line segments.
Question 47 1.2 / -0
Coach Kabir needs to buy 12 T-shirts for the girl's basketball team. The list below shows the prices of T-shirts at 2 stores. (i) Store X: One T-shirt costs Rs. 250. (ii) Store Y: A package of 6 T-shirts costs Rs. 1200. What is the amount of money coach Kabir will save if he buys 12 T-shirts from store Y?
Solution
Cost of 12 T-shirts bought from store X = Rs. (12 × 250) = Rs. 3000
Cost of 12 T-shirts bought from store Y = Rs. (1200 × 2) = Rs. 2400
Amount saved = Rs. (3000 - 2400) = Rs. 600
Question 48 1.2 / -0
Find P, Q, R and S respectively. A square pyramid has a __P__ base, __Q__ faces, __R__ edges, __S__ vertices.
Solution
It has a square base.
Vertices = 1 + 4 = 5
Edges = 4 + 4 = 8
Faces = 1 + 4 = 5
The given square pyramid has 5 corners, 8 edges and 5 faces.
Question 49 1.2 / -0
Which of the following is true?
Statement I: A fraction is said to be in the simplest (or lowest) form if its numerator and denominator have no common factor except 1.
Statement II: Simplest form of
is
.
Solution
Statement 1 is true. A fraction is in lowest form when the numerator and denominator of the fraction share no common factors other than 1. A fraction written in lowest form is called a simplified fraction.
Statement 2 is false. Simplest form of
(H.C.F. being 343)
Question 50 1.2 / -0
Smriti bought 19 boxes of sweets. Each box contains 228 sweets. How many sweets would be left with her after giving 519 sweets to friends?
Solution
Number of boxes of sweets = 19
Sweets in each box = 228
Total sweets = 19 × 228 = 4332
Sweets given to friends = 519
Remaining number of sweets = 4332 - 519 = 3813