Measurement Test

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Measurement Test - 2

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Question 1
1 / -0

Amar leaves for his office at 7:40 a.m. and arrives at 8:25 a.m. How long does it take Amar to reach his office?

A
55 minutes

B
20 minutes

C
35 minutes

D
45 minutes

Solution

He leaves for his office at 7:40 a.m.
So, from 7:40 a.m. to 8:00 a.m, there are 20 minutes.
And from 8:00 a.m. to 8:25 am, there are 25 minutes.
So, time taken by Amar to reach his office = 20 minutes + 25 minutes = 45 minutes
Question 2
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126 km 17 m + 41 km 42 m =

A
177 km 59 m

B
162 km 69 m

C
161 km 71 m

D
167 km 59 m

Solution

As we know, 1 km = 1000 m
126 km = 126 x 1000 = 1,26,000 m
So, 126 km 17 m = 1,26,000 m + 17 m = 1,26,017 m
Also,
41 km = 41 x 1000 = 41,000 m
41 km 42 m = 41,000 m + 42 m = 41,042 m

126 km 17 m + 41 km 42 m = 1,26,017 m + 41,042 m = 1,67,059 m
1,67,059 m = 167 km 59 m
Question 3
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How many 250g packets of oats are required to make 3 kg?

A
6

B
8

C
10

D
12

Solution

As 1 kg = 1000 g
Four 250g packets of oats would make 1 kg (as 4 x 250g = 1000 g).
Therefore, to make 3 kg, three lots of four 250g packets of oats are required.
i.e. 3 x (4 x 250 g) = 3000 g = 3 kg
So, twelve 250g packets of oats are needed to make 3 kg. (as 3 x 4 = 12)
Question 4
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If the cost of a 600g packet of coco powder is Rs. 50, then what is the price of a 120g packet of coco powder?

A
Rs. 12

B
Rs. 20

C
Rs. 15

D
Rs. 10

Solution

Rs. 50 = Cost of 600g packet of coco powder.
Therefore Rs. 1 = Cost of 12g packet of coco powder
Accordingly, Rs. 10 = Cost of 120g packet of coco powder.
Question 5
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The weight of each of the seven identical balls is ____.

A
2 kg

B
6.5 kg

C
7.5 kg

D
7 kg

Solution

Weight of seven identical balls = 14 kg (7.5 kg + 6.5 kg)

Hence, weight of one ball = kg = 2 kg
Question 6
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Which of the following combinations is identical to

A

B

C

D

Solution

300 ml + 300 ml + 300 ml + 300 ml = 1200 ml
Question 7
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How heavy is the watermelon?

A
500 g

B
450 g

C
350 g

D
400 g

Solution

Six bananas weight 300 g. So, the weight of one banana is 50 g.
Weight of 3 bananas + weight of 1 watermelon = 550 g
150 g + weight of 1 watermelon = 550 g
Hence, weight of 1 watermelon = 550 g - 150 g = 400 g
Question 8
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How much does the shoe cost?

A
Rs. 30

B
Rs. 16

C
Rs. 25

D
Rs. 14

Solution

Cost of 2 chocolates = Rs. 14
Cost of 1 chocolate = Rs. 7
Cost of shoe + football + chocolate + donut = Rs. 30
Cost of shoe + football + chocolate = Rs. 25 (Given)
Hence, Cost of a donut = Rs. 5.
Cost of a football + 2 donuts = Rs. 14
Cost of a football = Rs. 4
Cost of the shoe + Cost of Football + Cost of Chocolate + Cost of Donut = Rs. 30
Cost of Shoe + Rs. 4 + Rs. 7 + Rs. 5 = Rs. 30
Cost of Shoe = Rs. 30 - Rs. 16
Cost of Shoe = Rs. 14
Question 9
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The total weight of Box O and Box X is _____.

A
2400 g

B
1800 g

C
1200 g

D
2000 g

Solution

O measures 1500 g.
X measures 500 g
Hence, total weight of Box O and Box X = 1500 g + 500 g = 2000 g

Question 10

1 / -0

The following is Mr. Sharma's bill of groceries bought from a nearby shop. If he paid Rs. 1000, how much will he get back?

Oats	Rs. 320
Peanut Butter	Rs. 300
Banana	Rs. 80
Ice-cream	Rs. 125

Rs. 320

Rs. 210

Rs. 158

Rs. 175

Solution

Total amount to be paid = Rs. 320 + Rs. 300 + Rs. 80 + Rs. 125 = Rs. 825
Amount he will get back = Rs. 1000 - Rs. 825 = Rs. 175

Question 11
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The bigger jute bag can hold ___ g of weight more than the smaller bag.

A
4445

B
5474

C
4754

D
4575

Solution

Weight that the bigger jute bag can hold = 5 kg 125 g = (5 × 1000 g) + 125 g = 5000 g + 125 g = 5125 g
5125 g - 550 g = 4575 g
Hence, the bigger jute bag can hold 4575 g more than the smaller bag.

Question 12

1 / -0

Directions: Read the list of groceries available in a newly opened grocery shop and answer the following question.

If Sam bought 3 energy drinks, 4 deodorants and 2 yogurts, then how much does he have to pay?

Item	Cost	Item	Cost
Coke	Rs. 35	Biscuits	Rs. 45
Energy Drink	Rs. 105	Facewash	Rs. 130
Vegetable Oil	Rs. 250	Deodorant	Rs. 350
Oats	Rs. 300	Yogurt	Rs. 40

Rs. 1950

Rs. 1579

Rs. 1975

Rs. 1795

Solution

Cost of 3 energy drinks = 3 x 105 = Rs. 315
Cost of 4 deodorants = 350 x 4 = Rs. 1400
Cost of 2 yogurts = 40 x 2 = Rs. 80
Total = Rs. 1400 + Rs. 80 + Rs. 315 = Rs. 1795

Question 13

1 / -0

Directions: Read the list of groceries available in a newly opened grocery shop and answer the following question.

Maya went to the store for the first time and bought 1 vegetable oil, 4 packs of oats and 2 facewashes. How much she has to pay?

Item	Cost	Item	Cost
Coke	Rs. 35	Biscuits	Rs. 45
Energy Drink	Rs. 105	Facewash	Rs. 130
Vegetable Oil	Rs. 250	Deodorant	Rs. 350
Oats	Rs. 300	Yogurt	Rs. 40

Rs. 1170

Rs. 2150

Rs. 1650

Rs. 1710

Solution

Cost of vegetable oil = Rs. 250
Cost of 4 packs of oats = Rs. 300 x 4 = Rs. 1200
Cost of 2 facewashes = Rs. 130 x 2 = Rs. 260
Total = Rs. 250 + Rs. 260 + Rs. 1200 = Rs. 1710

Question 14
1 / -0

In the following grid, each item stands for a different value. The sum of each row and column is given.

What is the value of?

A
Rs. 75

B
Rs. 36

C
Rs. 48

D
Rs. 50

Solution

Sum of 2^nd column = Rs. 84
Which means that 3 bottles = Rs. 84
Hence, The value of 1 bottle = Rs. 28

Sum of 2^nd row = Rs. 89
Bottle + Bottle + Car = Rs. 89
Hence,
Rs. 28 + Rs. 28 + Car = Rs. 89
Therefore, the value of Car = Rs. 33

Now, Sum of 1^st column = Rs. 271
Computer + Bottle + Car = Rs. 271
Computer + Rs. 28 + Rs. 33 = Rs. 271
Hence, the value of Computer = Rs. 210

Finally, Sum, of last column is:
Truck + Car + Computer = Rs. 293
Truck + Rs. 33 + Rs. 210 = Rs. 293
Hence, the value of Truck = Rs. 50
Question 15
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Find the heaviest item among the given ones. (Maximum limit of all weighing machines is 5000 g i.e. 5 kg)

A
Popcorn

B
Flour

C
Money

D
Rice

Solution

Weight of flour = 1 kg = 1000 g ( as the mark points at 1 and the scale measures in kg)
Weight of popcorn = 500 g
Weight of rice = 1.5 kg = 1500 g
Weight of money bag = 200 g

Therefore, the heaviest item is rice.
Question 16
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The given figure shows how two different groups of objects balance a scale.

4 horseshoes balance ____.

A
6 hammers

B
12 hammers

C
6 blocks

D
10 hammers

Solution

1 Block = 2 Horseshoes.
From 1st diagram, it is clear that 1 block balances 2 horseshoes.
2 Blocks = 4 Horseshoes
Similarly, 2 Blocks will balance 4 Horseshoes ----(i)

Now, From the 2nd diagram,
It is clear that,
2 Blocks balances 6 Hammers. --- (ii)

Therefore,
From (i) and (ii)
4 Horseshoes will balance 6 Hammers.
Question 17
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Atul wants to mark on the calendar the date on which his exam result would be declared. It is five days after his parents' anniversary, which falls on third Tuesday of the given month.

Using this calendar, find the day on which his result would be declared.

A
25^th December, Sunday

B
25^th December, Monday

C
23^rd December, Sunday

D
18^th December, Tuesday

Solution

The third Tuesday falls on 20^th December. Five days after 20^th will be 25^th December, Sunday.
Question 18
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Alex takes 18 minutes and 12 seconds in the morning to deliver newspapers in his area. One day, he takes a different route, which takes him 15 minutes and 31 seconds to complete the delivery. How much time does he save by taking the new route?

A
2 minutes and 11 seconds

B
2 minutes and 14 seconds

C
3 minutes and 41 seconds

D
2 minutes and 41 seconds

Solution

Time spent to deliver newspapers in the morning = 18 minutes and 12 seconds = 1092 seconds [1 minute = 60 seconds]
After taking a different route, time taken = 15 minutes and 31 seconds = 931 seconds

Hence,
Time saved = 1092 seconds - 931 seconds = 161 seconds = 2 minutes and 41 seconds.
Question 19
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What is the weight of a star?

A
22 kg and 220 g

B
2 kg and 200 g

C
21 kg and 220 g

D
22 kg and 200 g

Solution

1 Star = 3 Hearts
1 Star = 1 Heart + 14.8 kg
3 Hearts = 1 Heart + 14.8 kg
2 Hearts = 14.8 kg
1 Heart = 7.4 kg
3 Hearts = 7.4 kg x 3 = 22.2 kg = 22 kg and 200 g
Question 20
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Which of the following is incorrect?

A
1 kg and 30 g = 1030 g

B
5 kg and 140 g = 5140 g

C
5 kg and 577 g = 5577 g

D
4 kg and 12 g = 4120 g

Solution

4 kg = 4000 g
4 kg and 12 g = 4000 + 12 = 4012 g
Question 21
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Jatin traveled 158 km and 610 m by road in his car and 118 km and 65 m by ship to reach his destination. What distance did he travel in total?

A
271 km and 175 m

B
276 km and 765 m

C
267 km and 675 m

D
276 km and 675 m

Solution

Distance traveled by road in km = 158 km and 610 m = 158000 + 610 m = 158610 m
Distance traveled by ship in km = 118 km and 65 m = 118000 + 65 = 118065 m
Hence, total distance traveled = 158610 m + 118065 m = 276675 m = km = 276.675 km.
Therefore, total distance traveled by Jatin is 276 km and 675 m.
Question 22
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Fahim left to attend his music class at 5:20 pm. He told his mom that he would be back after 2 hours and 30 minutes. At what time would Fahim be back?

A
7:30 pm

B
6:45 pm

C
7:50 am

D
7:50 pm

Solution

Time when Fahim left his home = 5:20 pm.
He would be back after = 2 hours and 30 minutes.

Hence,
Time he left the home + 30 minutes = 5:20 pm + 30 minutes = 5:50 pm
5:50 pm + 2 hours = 7:50 pm.

Hence, Fahim would be back at 7:50 pm.
Question 23
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Arjun went to a carnival with his friend. He bought 2 tickets for Rs 120 each. He bought 4 cotton candies for Rs. 10, 5 milkshakes for Rs. 25 and 2 tickets to a show. What information is needed to find the total amount spent by Arjun?

A
The cost of milkshakes

B
The name of the carnival

C
Number of people in the carnival

D
The cost of tickets to the show

Solution

Cost of 1 ticket = Rs. 120
Hence, Cost of 2 tickets = Rs. 120 x 2 = Rs. 240

Money spent on Cotton candies = Rs. 10
Money spent on Milkshakes = Rs. 25
Money spent for 2 tickets to a show = ?

Total money spent = Cost of 2 tickets + Money spent on Cotton candies + Money spent on Milkshakes + Money spent on 2 tickets to a show.
=> Rs. 240 + Rs. 10 + Rs. 25 + Money spent on 2 tickets to a show.

Hence, the cost of tickets to the show is the only information needed to calculate the total amount spent by Arjun.
Question 24
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A box contains 45 chocolates. A grocer empties the contents of the box in 5 bags. How many chocolates would each bag contain?

A
12

B
45

C
5

D
9

Solution

The box contains 45 chocolates.
45 chocolates need to be divided into 5 bags.
45 ÷ 5 = 9
Hence, each bag would contain 9 chocolates.
Question 25
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Jack has 67 kg and 210 g of flour. He uses 12 kg and 890 g of flour to bake some cakes. How much flour does he have left with him?

A
34 kg and 300 g

B
44 kg and 302 g

C
41 kg and 230 g

D
54 kg and 320 g

Solution

Total quantity of flour = 67 kg and 210 g = 67,210 g
Quantity of flour used to bake cake = 12 kg and 890 g = 12,890 g
Quantity of flour left = 67,210 g - 12,890 g = 54,320 g which is 54 kg and 320 g.
Question 26
1 / -0

= 19 kg,
= 74 kg
and= 9 kg.
Now, find the weights of.

A
Nail cutter = 6 kg; Nail polish = 4 kg

B
Nail cutter = 6 kg; Nail polish = 5 kg

C
Nail cutter = 11 kg; Nail polish = 4 kg

D
Nail cutter = 7 kg; Nail polish = 4 kg

Solution

Nail + Nail cutter = 19 kg
4 nails + 3 Nail cutters + 1 Nail polish = 74 kg
Nail + 3 (Nail + Nail cutter) + 1 Nail polish = 74 kg
Nail + 3(19) + 1 Nail polish = 74 kg
Nail + 57 + 1 Nail polish = 74 kg
Nail + Nail polish = 17 kg

Nail - Nail polish = 9 kg
Nail = 13 kg
Nail + Nail cutter = 19 kg
Nail cutter = 6 kg

Nail + Nail polish = 17 kg
Nail polish = 4 kg
Question 27
1 / -0

Ankit wants to go to the supermarket to buy some groceries. He is currently at his home. He wants to take the shortest route. Which route should he take?

A
Home - School - Mall - Supermarket

B
Home - School - Post Office - Supermarket

C
Home - Clothing Store - Supermarket

D
Home - Post office - Car Repair Shop - Supermarket

Solution

Home - School - Mall - Supermarket
6 km + 1 km + 2 km = 9 km

Home - Clothing store - Supermarket
6 km + 8 km = 14 km

Home - Post-office - Car repair shop - Supermarket
3 km + 5 km + 2 km = 10 km

Hence, Home - School - Mall - Supermarket is the shortest route he should take.
Question 28
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Find out the cost of from the given figure.

A
Rs. 390

B
Rs. 360

C
Rs. 960

D
Rs. 630

Solution

Sum of 3rd column = Rs. 2580
i.e. cost of 2 Wrenches + cost of 1 Hammer = Rs. 2580
Or, cost of 1 Hammer = Rs. 2580 - cost of 2 Wrenches

Also, from 1st row, it is clear that
Cost of 2 Hammers + Cost of 1 Wrench = Rs. 2040
2 (Rs. 2580 - Cost of 2 Wrenches) + Cost of 1 Wrench = Rs. 2040
Rs. 5160 - Cost of 4 Wrenches + Cost of 1 Wrench = Rs. 2040
Rs. 5160 - Cost of 3 Wrenches = Rs. 2040
Hence, Cost of 3 Wrenches = Rs. 3120
Cost of 1 Wrench = Rs. 1040

Now, Cost of 1 Hammer = Rs. 2580 - Cost of 2 Wrenches
Cost of 1 Hammer = Rs. 2580 - Rs. 2080 = Rs. 500

Now, from 3rd row, it is clear that,
Cost of 1 Screwdriver + Cost of 1 Hammer + Cost of 1 Wrench = Rs. 1780
Hence,
Cost of 1 Screwdriver + Rs. 500 + Rs. 1040 = Rs. 1780
Therefore, Cost of 1 Screwdriver = Rs. 240

Now, from 1st column,
Cost of 1 Hammer + Cost of 1 Saw + Cost of 1 Screwdriver = Rs. 1100
Rs. 500 + Cost of 1 Saw + Rs. 240 = Rs. 1100
Therefore, Cost of 1 Saw = Rs. 360
Question 29
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Stick 1 is thrice as long as stick 2. Stick 3 is 90 cm shorter than stick 1. Stick 3 is 180 cm long. What is the total length of all the sticks?

A
500 cm

B
550 cm

C
450 cm

D
540 cm

Solution

Length of Stick 1 = 3 x length of Stick 2 ---(i)
Length of Stick 3 = Length of Stick 1 - 90 cm ---(ii)
Length of Stick 3 = 180 cm (Given)

From (ii)
180 cm = Length of Stick 1 - 90 cm
Hence, Length of Stick 1 = 180 cm + 90 cm = 270 cm
Therefore, Length of Stick 1 = 270 cm

Also, from (i)
270 cm = 3 x Length of Stick 2
270 cm / 3 = Length of Stick 2
Therefore Length of Stick 2 = 90 cm

Hence, total length of all the sticks = Length of Stick 1 + Length of Stick 2 + Length of Stick 3
= 270 cm + 90 cm + 180 cm = 540 cm
Question 30
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If , and the total weight of is 3200 kg, then what is the weight of?

A
70 kg

B
80 kg

C
90 kg

D
100 kg

Solution

Star - Hexagon = 20 kg
Hexagon = Star - 20 kg
Rhombus - Star = 70 kg
Rhombus = 70 kg + Star
10 Rhombuses + 10 Stars + 10 Hexagons = 3200 kg
10 (70 + Star) + 10 Stars + 10 (Star - 20) = 3200 kg
700 kg + 10 Stars + 10 Stars + 10 Stars - 200 kg = 3200 kg
30 Stars = 2700 kg
Star = 90 kg