Mensuration Test

Result

Mensuration Test - 5

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Weekly Quiz Competition

Question 1
1 / -0

If the length of each side of an equilateral triangle is multiplied by 7, then the new perimeter is __ times the original perimeter.

A
7

B
3.5

C
5

D
14

Solution

Let the perimeter of the equilateral triangle be X.
The new perimeter will be 7X.
So, the new perimeter is 7 times the original perimeter.
Question 2
1 / -0

The area of a rectangular sheet is 425 cm² and its breadth is 17 cm. Which of the following options is 4 times the length of the rectangle?

A
50 cm

B
100 cm

C
150 cm

D
200 cm

Solution

Area = L × B (L = length and B = breadth)
B = 17
425 = L × 17

L = 425/17

L = 25 cm
4 times the length = 4 × 25 = 100 cm
Question 3
1 / -0

If the perimeter of a square is numerically equal to the area of a rectangle and the breadth of the rectangle is equal to the side of the square, then what is the length of the rectangle?

A
1 unit

B
2 units

C
3 units

D
4 units

Solution

Perimeter of the square = Area of the rectangle
4 x Side = Length × Breadth
But, Breadth of the rectangle = Side of the square

So,

4 x Side = Length × Side
Length = 4 units
Question 4
1 / -0

Find the ratio of the perimeter to the area of a square with side 12 cm.

A
1 : 3

B
3 : 1

C
2 : 3

D
4 : 5

Solution

Ratio of the perimeter to the area of the square = 4 × side/(side)² = (4 × 12)/(12 × 12) = 4/12 = 1 : 3
Question 5
1 / -0

There is a garden with length 80.5 m and width 70 m. Find the perimeter of the fence required for fencing the garden.

A
345 m

B
198 m

C
405 m

D
301 m

Solution

Perimeter = 2(Length + Breadth)
= 2(80.5 + 70)
= 2 × 150.5
= 301 m
So, required length = 301 m
Question 6
1 / -0

The lid of a square box of side 40 cm is sealed all round with the tape. What is the length of the tape required if the lid is sealed 4 times?

A
540 cm

B
640 cm

C
160 cm

D
120 cm

Solution

Length of tape required = 4(perimeter of the lid) = 4(4 × 40) = 640 cm
Question 7
1 / -0

Find the number of tiles, each measuring 25 cm by 6 cm, which can cover a wall of dimensions 12 m by 8 m.

A
6400

B
9800

C
8000

D
7200

Solution

Area of a tile = 25 × 6 = 150 cm²
Area of the wall (in cm) = 1200 × 800 = 9,60,000 cm²

Number of tiles required = 9,60,000 ÷ 150
= 6400

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Re-Attempt Weekly Quiz Competition

Mensuration Test - 5

Result

Mensuration Test - 5

Score

-

Rank

-

SHARING IS CARING

Question 1

7

3.5

5

14

Solution

Question 2

50 cm

100 cm

150 cm

200 cm

Solution

Question 3

1 unit

2 units

3 units

4 units

Solution

Question 4

1 : 3

3 : 1

2 : 3

4 : 5

Solution

Question 5

345 m

198 m

405 m

301 m

Solution

Question 6

540 cm

640 cm

160 cm

120 cm

Solution

Question 7

6400

9800

8000

7200

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

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