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Probability Test - 5

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Probability Test - 5
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  • Question 1
    1 / -0

    A basket contains seven apples and fourteen oranges. If we select two fruits at random, then what is the probability that both will be different?

    Solution

    Case (1): Event A: First is apple; second is orange. Then, P (A) = (7/21)  (14/20) = 7/30.
    Case (2): Event B: First is orange; second is apple. Then, P (B) = (14/21)  (7/20) = 7/30.

    So, the required probability is P (A) + P (B) = 7/15.

     

  • Question 2
    1 / -0

    The probabilities of three doctors, A, B and C, achieving success in an operation are 0.5, 0.2 and 0.3, respectively. Find the probability that the operation is not successful.

    Solution

    Since A, B or C could perform the operation independently, these are mutually exclusive events.

    Therefore, the required probability is (1 - 0.5) × (1 - 0.2) × (1 - 0.3) = 0.28.

     

  • Question 3
    1 / -0

    State True (T) and False (F) for the following statements.

    (i) The probability of an event can never be greater than 1.
    (ii) When two dice are rolled, the probability of getting the sum of 13 of two numbers appeared is 1/36.
    (iii) In a 12-month period, the probability of a month having 31 days is 1/2.
    (iv) In the English alphabet, if a letter is randomly chosen, the probability that the letter is a consonant is 21/26.

    Solution

    (i) The probability of an event can never be greater than 1. This statement is true as the probability of an event lies between 0 and 1 (both inclusive).

    (ii) When two dice are rolled, the probability of getting the sum of 13 of two numbers appeared is 1/36. This statement is false because when two dice are rolled, the maximum number as the sum of both the numbers on the dice is 12, i.e. 6 + 6. Therefore, this is an impossible event.

    (iii) In a 12-month period, the probability of a month having 31 days is 1/2. This statement is also false as there are seven months having 31 days in a year.
    So, probability of a month having 31 days = 7/12

    (iv) In the English alphabet, if a letter is randomly chosen, the probability that the letter is a consonant is 21/26. This statement is true as there are 21 consonants and 5 vowels in the English alphabet.

     

  • Question 4
    1 / -0

    Two bats are flipped simultaneously. Find A and B, respectively.

    Number of hills up Required probability
    (i) 0 A
    (ii) 2 B
    Solution

    Let hills up be denoted by H and flats up be denoted by F.
    Total number of outcomes = {HH, HF, FH, FF} (4 outcomes)

    From the given information,
    (i) Probability of no hills up = 1/4 (only one possibility out of 4)
    (ii) Probability of two hills up = 1/4 (only one possibility out of 4)

     

  • Question 5
    1 / -0

    The following table gives the estimated height of people living in a society.

    Number of people Height (in inches)
    13 48-51
    9 51-54
    23 54-57
    10 57-60
    5 60-63

    Note: 48-51 means (48 ≤ height < 51)

    If a person is selected at random from the society, then which of the following statements is INCORRECT?

    Solution

    Number of persons having height less than 60 inches = Number of persons having height between 48 inches and 60 inches = 13 + 9 + 23 + 10 = 55

    Probability of the persons having height less than 60 inches = 55/60 = 11/12

     

  • Question 6
    1 / -0

    A survey was conducted on 500 students by a certain group to analyse the sectors which they chose after passing class 12th, having their stream of education as Arts, Commerce and Science after class 10th. The data of the survey is given below.

      Arts Commerce Science
    Bachelor's Degree 50 100 210
    Business 2 30 20
    Sports 4 6 3
    Photography 16 4 1
    Others 28 10 16


    Find the probability of students:
    (a) Having Science or Arts as their stream choosing the Business sector
    (b) Having Photography as their sector
    (c) Having Commerce as their stream choosing the Sports or 'Others' sector with respect to all the Commerce students.

      (a) (b) (c)
    (i) 17/350 19/500 8/75
    (ii) 11/175 21/500 8/75
    (iii) 11/350 21/500 8/75
    (iv) 11/175 21/500 11/75
    Solution

    Total number of students = 500

    (a) From the table,
    Number of students choosing the Business sector having Science or Arts as their stream of education = 20 + 2 = 22

    Total number of students having Science or Arts as their stream = 50 + 2 + 4 + 16 + 28 + 210 + 20 + 3 + 1 + 16 = 350

    So, the probability of students having Science or Arts as their stream choosing the Business sector = 22/350 = 11/175

    (b) From the table,
    Number of students choosing Photography as their sector = 16 + 4 + 1 = 21

    So, the probability of students having Photography as their sector = 21/500

    (c) From the table,
    Number of Commerce students = 100 + 30 + 6 + 4 + 10 = 150

    Number of students having Commerce as their stream choosing the Sports or 'Others' sector = 16

    So, the probability of students having Commerce as their stream choosing the Sports or 'Others' sector with respect to all the Commerce students = 16/150 = 8/75

     

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