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Surface Area And Volume Test - 2

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Surface Area And Volume Test - 2
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  • Question 1
    1 / -0

    A hollow iron pipe is 42 cm long and its inner radius is 7 cm. If the thickness of the pipe is 1.5 cm and iron weights 10 gm/cm3, find the mass of the pipe (in kg).

    Solution

    External radius = 7 + 1.5 = 8.5 cm
    Internal radius = 7 cm.
    Volume of iron = π × ((R × R) - (r × r))h = 22/7 × ((8.5 × 8.5) - (7 × 7)) × 42 = 3069 cm3
    Mass of iron pipe = (3069 cm3 × 10 gm/cm3)
    = 30690 gm
    = 30.69 kg

     

  • Question 2
    1 / -0

    A tank 12 m long and 8 m wide contains water up to a height of 2.5 m. The total area of the wet surface is

    Solution

    Area of the wet surface = [2(lb + bh + lh) - lb] = 2(bh + lh) + lb = [2 (8 × 2.5 + 12 × 2.5) + 12 × 8] m2 = 196 m2

     

  • Question 3
    1 / -0

    A wooden box measures externally 4 m × 3 m × 2 m. The thickness of all four sides is 5 cm. If the capacity of the box is 18.096 m3, find the thickness of the bottom.

    Solution

    Let the thickness of the bottom = x m
    Then, volume = 18.096
    (4 - 0.10) × (3 - 0.10) × (2 - 2x) = 18.096
    2 - 2x = 1.6
    x = 0.2
    So, thickness of the bottom is 0.2 m.

     

  • Question 4
    1 / -0

    A cylinder is formed by folding a rectangular tin sheet along its length, and the dimensions of the sheet are 44 cm by 20 cm. What is the curved surface area of the cylinder?

    Solution

    As the rectangular sheet has been folded along its length, circumference of base of the cylinder = 2π × r = 44 cm and height of the cylinder = 20 cm.

    Now, curved surface area of the cylinder = 2π × r × h = 44 × 20 = 880 cm2

     

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