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Atomic Structure & Chemical Bonding Test - 3

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Atomic Structure & Chemical Bonding Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following species will produce the shortest wavelength for the transition n = 2 to n = 1?
    Solution
    Larger the value of Z, larger the transition energy and hence shorter the wavelength.
  • Question 2
    1 / -0
    Suppose 10-17 Jouls of light energy is required by the interior of the human eye to see on object. How many photons of green light are needed to generate this minimum amount of energy?
    Solution
  • Question 3
    1 / -0
    Non-directional orbital is
    Solution
    3s-Orbital is spherical, hence it is non directional.
  • Question 4
    1 / -0
    When the frequency of light incident on a metallic plate is doubled, the KE of the emitted photo electrons will be
    Solution
  • Question 5
    1 / -0
    In an atom two eletrons move around the nuclens in circular orbit of R and 4R. The ratio of the time taken by them to complete one revolution is
    Solution
  • Question 6
    1 / -0
    A 3 p-orbital has
    Solution
  • Question 7
    1 / -0
    Calculate no. of photons emitted in 10 hrs by a 60 W sodium 1 amp
    Solution
  • Question 8
    1 / -0
    Directions: The following question has four choices out of which ONLY ONE is correct.

    What will be the frequency of electron in Bohr orbit?
    If v = 2.19 x 105ms-1 and r = 0.5287 x 10-10m.
    Solution
  • Question 9
    1 / -0
    What is the speed of an electron whose de-Broglie wavelength is 0.1 nm?
    Solution

    = 7.28 x 106 m/s
  • Question 10
    1 / -0
    Find the product of uncertainty in position and velocity for an electron of mass 9.1 x 10-31 kg?
    Solution
  • Question 11
    1 / -0
    How many photons of light having a wavelength of 4000 Å are required to provide 1 Joule of energy?
    Solution
  • Question 12
    1 / -0
    Which one the following fundamental particles is the heaviest?
    Solution
    Mass of a proton = 1.6726 x 10-24 g or 1.0073 u
    Mass of a neutron = 1.6740 x 10-24 g or 1.0078 u
    Mass of an electron = 9.1094 x 10-28 g or 0.00054858 u
    Hence, neutron is the heaviest fundamental particle in an atom.
  • Question 13
    1 / -0
    Directions: The following question has four choices, out of which ONLY ONE is correct.

    The number of waves made by a Bohr electron in an orbit of maximum magnetic quantum number 3 is
    Solution
    Negative quantum number has values from −l to +l.
    ∴ l = 3
    Now, l has value from 0 to n − 1.
    ∴ 3 = n − 1
    n = 4
    No. of waves made by Bohr electron, n = 4
  • Question 14
    1 / -0
    Which of the following orbital notations does not have spherical node?
    Solution
    The number of nodes is equal to (n – 1) and the number of spherical nodes is given by the expression (n – l – 1).
  • Question 15
    1 / -0
    The distance between 3rd and 2nd orbit in the H-atom is
    Solution
    The distance between 3rd and 2nd orbit in the H-atom is 2.646 x 10-8 cm.
  • Question 16
    1 / -0
    13.5 gm of Al when changed to Al+3 ion in solution, will lose
    Solution

    Since Al changes to Al3+ ions by losing 3 electrons, thus number of electrons emitted by 13.5 g = 3 x 3.011 x 1023 = 9.033 x 1023 electrons
  • Question 17
    1 / -0
    In Bohr's model of H-atom, the ratio of the period of revolution of an electron in the orbit n = 1 to the period of revolution of an electron in the orbit n = 2 is
    Solution
  • Question 18
    1 / -0
    The ionisation potential of H atom is 13.6 eV. If hydrogen atom in the ground state is excited by monochromatic light of energy 12.1 eV, what will be the number of spectral lines emitted according to Bohr's theory?
    Solution
    En = E1 + E = - 13.6 + 12.1 = - 1.5 eV
    As En = - , so n2 = = 9
    Hence, on absorption, H atom is excited to n = 3. The possible transitions are 3 1, 3 2 and 2 1.
  • Question 19
    1 / -0
    The wave length of a certain line in Balmer series is observed to be 4341Å. To what value of "n" does this correspond?
    Solution
  • Question 20
    1 / -0
    Which one is not possible?
    Solution
    l can take values only up to n - 1.
    Hence, for n = 2, l can have only two values:
    l = 0 (s-subshell)
    l = 1 (p-subshell)
  • Question 21
    1 / -0
    Directions: The following question has four choices out of which ONLY ONE is correct.

    The two unpaired electrons of carbon differ in terms of their ____ quantum number.
    Solution
    The two unpaired electrons of carbon differ in terms of their spin quantum number.
  • Question 22
    1 / -0
    Isotopes are possible due to difference in the number of
    Solution
    The mass of an atom is on account of the nucleons (protons + neutrons). All atoms of an element have the same atomic number (same number of protons) but may have different mass due to difference in the number of neutrons.
    Hence option (3) is correct.
  • Question 23
    1 / -0
    The maximum number of electrons having n = 1, l = 0, m = 0, and s = 1/2, is
    Solution
    The given values of quantum numbers correspond to 1s orbital, which can accommodate a maximum of 2 electrons.
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