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Chemical Bonding & Molecular Structure Test - 4

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Chemical Bonding & Molecular Structure Test - 4
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  • Question 1
    1 / -0
    Which of following is not correctly matched?
    Solution
    H2 (2 electrons): (1s)2
    No unpaired electrons; Diamagnetic

    Li2 (6 electrons): (1s)2 (*1s)2 (2s)2
    No unpaired electrons; Diamagnetic

    C2 (12 electrons): (1s)2 (*1s)2 (2s)2 (*2s)2 (2px)2 (2py)2
    No unpaired electrons; Diamagnetic

    B2 (10 electrons): (1s)2 (*1s)2 (2s)2 (*2s)2 (2px)1 (2py)1
    Two unpaired electrons; Paramagnetic

    Hence, option (3) is not correctly matched.




  • Question 2
    1 / -0
    Which of the following molecules has sp3d3 hybridisation and one lone pair of electrons?
    Solution
    1) IF7 has 7 shared pairs, no lone pairs and sp3d3 hybridisation.
    2) XeF6 has 6 shared pairs, one lone pair and sp3d3 hybridisation.
    3) SF6 has 6 shared pairs, no lone pairs and sp3d2 hybridisation.
    4) ClF5 has 5 shared pairs, one lone pair and sp3d2 hybridisation.
    Hence, (2) is the correct answer.
  • Question 3
    1 / -0
    Which of the following statements is false?
    Solution
    At maximum, a water molecule can have is 4 hydrogen bonds.
  • Question 4
    1 / -0
    Which of the following species contains four bond pairs and two lone pairs around the central atom?
    Solution
    XeF4 has 4 bond pairs and 2 lone pairs around the central atom (sp3d2 hybridization).
  • Question 5
    1 / -0
    Which of the following conversions involves a change in both hybridisation and geometry?
    Solution
    AlCl3 : sp2 hybridisation, trigonal planar geometry
    AlCl4- : sp3 hybridisation, tetrahedral geometry
    Hence, option (2) is correct.

    NH3 : sp3 hybridisation, trigonal pyramidal geometry
    NH4+ : sp3 hybridisation, tetrahedral geometry
    AlCl3 : sp2 hybridisation, trigonal planar geometry
    AlCl4- : sp3 hybridisation, tetrahedral geometry
    PCl3 : sp3 hybridisation, trigonal pyramidal geometry
    PCl4+ : sp3 hybridisation, tetrahedral geometry
  • Question 6
    1 / -0
    Which of the following statements is INCORRECT?
    Solution
    O2+ (15 electrons): (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2, (π2py)2 = (π2px)2, (π*2px)1
    O2 (16 electrons): (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2, (π2py)2 = (π2pz)2, (π*2py)1 = (π*2px)1
    Both O2+ and O2 are paramagnetic due to presence of unpaired electrons.
    F2 (18 electrons) : (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2, (π2py)2 = (π2px)2, (π*2px)2 = (π*2py)2
    No unpaired electrons; diamagnetic.
  • Question 7
    1 / -0
    In which of the following changes is an electron added to antibonding (π*) orbital?
    Solution
    O2+ (15 electrons) : (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2,(π2px)2=( π2py)2, (π*2px)1
    O2 (16 electrons) : (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2, (π2px)2=( π2py)2, (π*2px)1=( π*2py)1
    During change of O2+ to O2, an electron is added to π* orbital.
  • Question 8
    1 / -0
    Which of the following statements is NOT true?
    Solution
    On ionization of NO to form NO+, the nitrogen-oxygen bond becomes stronger (the bond order increases from 2.5 in NO to 3 in NO+ cation).
  • Question 9
    1 / -0
    In allene CH2 = C = CH2, hybridisations of carbon atoms are ______, respectively.
    Solution
    Hybridisations of respective carbon atoms are identified correctly.
  • Question 10
    1 / -0
    Which of the following matchings is not correct?
    Solution
    XeF4 has 4 shared pairs and two lone pairs; sp3d2 hybridisation; and square planar geometry.
  • Question 11
    1 / -0
    Which of the following sets represents molecules with linear geometry only?
    Solution
    CO2, BeCl2, I3-, IF2- : All have linear geometry
  • Question 12
    1 / -0
    Which of the following sets represents molecules with trigonal planar geometry only?
    Solution
    BF3, SO3, GaF3, NO3- : All have trigonal planar geometry.
  • Question 13
    1 / -0
    Which of the following sets represents molecules with see-saw geometry only?
    Solution
    SF4, TeCl4, XeO2F2: All have see-saw geometry.

  • Question 14
    1 / -0
    Which among the following have unpaired electrons?

    B2, C2, N2, O2
    Solution
    B2 (10 electrons): (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (π2px)1 (π2py)1
    O2 (16 electrons): (σ1s)2, (σ*1s)2, (σ2s)2, (σ*2s)2, (σ2pz)2, (π2px)2 = (π2py)2, (π*2px)1 = (π*2py) 1
    Both B2 and O2 have 2 unpaired electrons each.
  • Question 15
    1 / -0
    Which of the following statements is true?
    Solution
    F is more electronegative than Cl, but due to the greater bond length of the C-Cl bond as compared to the C-F bond, the dipole moment of CH3Cl is more than that of CH3F.
  • Question 16
    1 / -0
    Which of the following sets is correct with respect to molecule/ion, hybridisation of central atom and shape of the molecule/ion?
    Solution
    AsH3: sp3 hybridization, trigonal pyramidal shape
  • Question 17
    1 / -0
    Geometry of the conjugate base of NH4+ ion is _________.
    Solution
    Conjugate base of NH4+ ion is NH3. NH3 has trigonal pyramidal shape (sp3 hybridization; 3 shared pairs and one lone pair)
  • Question 18
    1 / -0
    Which of the following statements is TRUE?
    Solution
    B-F bond is larger in BF4- than in BF3. This is due to the fact that in BF4-, boron atom is sp3 hybridised, while in BF3, boron atom is sp2 hybridised and bond length decreases with increase in s-character, since s-orbital is smaller than p-orbital.
  • Question 19
    1 / -0
    Which of the following sets represents molecules with zero dipole moment only?
    Solution
    BeCl2, BF3, AlCl3, CO2, CCl4 : All are non-polar molecules with zero dipole moment.
    The dipole moment of the individual bonds is cancelled out due to the regular molecular geometry.
    BeCl2 and CO2 have linear geometry; BF3 and AlCl3 have a trigonal planar geometry and CCl4 has tetrahedral geometry.
  • Question 20
    1 / -0
    Which of the following combinations of 'molecule : shape' is incorrect?
    Solution
    XeOF4 has square pyramidal shape.

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