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Profit And Loss Test - 5

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Profit And Loss Test - 5
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  • Question 1
    1 / -0
    Chirag bought 50 kg of rice at Rs. 25 per kg. He also bought vanaspati and onions. The quantity of vanaspati is equal to the collective sum of quantities of rice and onions. Also, the sum of the quantities of vanaspati and onions is equal to twice the quantity of rice he has bought. If Chirag bought the onions at Rs. 10 per kg, what is the difference in the amounts spent by Chirag on onions and rice?
    Solution
    Let R, V and O be the quantities of rice, vanaspati and onions, respectively.
    R = 50 kg V + O = 2R, i.e. V + O = 100 kg …(1)
    Also, V = R + O, i.e. V – O = 50 kg … (2)
    Solving (1) and (2):
    V = 75 kg, O = 25 kg.
    Amount spent on rice = Rs. 25 x 50 = Rs. 1250

    Amount spent on onions = Rs.10 x 25 = Rs. 250
    Difference in both the amounts = Rs. 1250 – Rs. 250 = Rs. 1000

  • Question 2
    1 / -0
    Deepika sells her goods 10% cheaper than those of Nidhi and 10% costlier than those of Gurpreet. A customer purchases goods from Nidhi worth Rs. 100. How much would he have saved if he bought the same goods from Gurpreet?
    Solution
    Selling price of goods sold by Nidhi = Rs. 100
    Selling price of goods sold by Deepika = Rs. 90
    Now, according to the question:
    110% of selling price of goods sold by Gurpreet = Rs. 90
    Selling price of goods sold by Gurpreet = (100/110) x 90 = Rs. 900/11

    So, Gurpreet's goods are cheaper than Nidhi's goods by =

    Therefore, the customer would have saved 18.18%, if he bought the goods from Gurpreet instead of buying them from Nidhi.
  • Question 3
    1 / -0
    Harry and Jon plan to spend the afternoon at the fair. After paying the entrance price of Rs.5.00 each they entered the fair ground. Jon looked around and saw that the Dragon ride was Rs.3.50 and the Loppo was Rs.2.75. In addition, there were 3 activities he wanted to do which cost Rs.1.50 each. Jon guessed that snacks and drinks would cost Rs.3.50. Jon could see that he did not have enough money. Jon then borrowed Rs.6.00 from Harry. They noted that after Harry gave Jon Rs.6, Harry still had Rs.12.00 more than Jon. How much more money did Harry have than Jon had before Harry gave Jon Rs.6.00?
    Solution
    The problem asks for how much more money Harry had than Jon.
    How much more = Harry had - Jon had
    This equation first requests information about the amount of money Harry had.
    This is surely the amount he now has plus the amount he gave to Jon.
    Harry had = Harry has + 6.00
    The requesting equation now requests information about the amount of money Jon had.
    This is surely the amount he had less the amount Harry gave him.
    Jon had = Jon has - 6.00
    Substitution provides
    How much more = (Harry has + 6.00) - (Jon has - 6.00)
    How much more = (Harry has - Jon has) + 12.00
    The problem tells us that after the lending
    Harry has - Jon has = 12.00
    Substitution gives
    How much more = (12.00) + 12.00 = Rs.24.00.
    Harry had Rs.24.00 more than Jon when he loaned Jon Rs.6.00.

  • Question 4
    1 / -0
    A sold an article to B at a profit of 20%. B sold it to C at a profit of 15%. C paid Rs. 190 more than the cost of article for A. What profit did A make?
    Solution
    Let the article's cost be Rs. X for A.
    A's selling price = B's cost price = X × 1.2
    B's selling price = C's cost price = X × 1.2 × 1.15
    Now, X × 1.2 × 1.15 - X = 190
    1.38X - X = 190
    0.38X = 190
    X = = Rs. 500
    A's profit = 20% of 500 = Rs. 100
  • Question 5
    1 / -0
    Gulnaaz bought some bananas at the rate of 6 per rupee. She bought the same number of bananas at the rate of 3 per rupee. She mixed both the types and sold them at the rate of 10 for Rs. 3. In this business, she earned a profit of Rs. 5. What was the total number of bananas that she bought?
    Solution
    Let the number of bananas bought at 6 per rupee be x.
    Total number of bananas be 2x.
    (x at 6 per rupee and x at 3 per rupee)
    S.P. of 10 bananas = Rs. 3
    S.P. of 2x bananas = Rs. = Rs.
    Total C.P. = (x/6) + (x/3) = x/2
    According to the question,
    (3x/5) - (x/2) = x/10 = 5
    Total number of bananas = 2x = 100
  • Question 6
    1 / -0
    A sold a watch to B at a gain of 5% and B sold it to C at a gain of 4%. Find the price paid by A, if C paid Rs. 1092 for it.
    Solution
    C paid Rs. 1092.
    Suppose A paid Rs. X.
    Then, amount paid by B to A = Rs. 1.05X
    Amount paid by C to B = 1.04 × 1.05X = Rs. 1092
    X = Rs. 1000

    Shortcut method
    :

    From options:
    Suppose A paid Rs. 1000.
    Then, amount paid by B to A = Rs. 1000 × + Rs. 1000 = Rs. 1050
    And amount paid by C to B = Rs. 1050 + = Rs. 1092
    It satisfies the given condition.
  • Question 7
    1 / -0
    On selling an article for Rs. 240, a trader loses 4%. In order to gain 10%, at what price he must sell the article?
    Solution
    SP = Rs. 240
    Loss = 4%
    0.96CP = 240
    CP = 250
    Now, the trader wants to earn 10% on the transaction.
    Thus, new SP = 250 x 1.1 = Rs. 275


  • Question 8
    1 / -0
    The percentage of profit made when an article is sold for Rs. 81 is thrice when it is sold for Rs. 67. Find the cost price of the article.
    Solution
    Let CP of the article be Rs. x.
    Percentage profit when article is sold for Rs. 81 = × 100 ...... (1)
    Also, when the article is sold for Rs. 67,
    % profit = × 100 ...... (2)
    From (1) and (2),
    × 100 = 3 × 100
    ⇒ 81 - x = 201 - 3x
    ⇒ 2x = 120
    ⇒ x = 60
    Thus, cost price of the article = Rs. 60
    Hence, answer option 2 is correct.
  • Question 9
    1 / -0
    Kishore asks his servant to buy eggs and oranges. Each egg is worth Rs. 2 and each orange is worth Rs. 3. Each egg weighs 0.3 kg and each orange weighs 0.5 kg. The servant's bag can carry at most 15 kg. What should he buy to spend the maximum money?
    Solution
    Do it by going through the options.
    (1) Weight of 30 eggs and 12 oranges = (30 × 0.3) + (12 × 0.5) = 15 kg
    Amount = 30 × 4 + 12 × 3 = Rs. 96
    (2) Weight of 28 eggs and 14 oranges = (28 × 0.3) + (14 × 0.5) = 15.4 kg (Not possible)
    (3) Weight of 30 oranges = 30 × 0.5 = 15 kg
    Amount = 30 × 3 = Rs. 90
    (4) Weight of 50 eggs = 50 × 0.3 = 15 kg
    Amount = 50 × 2 = Rs. 100

    Answer: (4)
  • Question 10
    1 / -0
    Anu, Manu and Kanu respectively invest Rs. 30,000, Rs. 20,000 and Rs. 15,000 in cloth business. Anu and Manu respectively get 15% and 5% of total profit. The remaining profit is divided among the three friends in the ratio of their investments. If Anu gets Rs. 800 more than Manu, find Anu's share in the profit.
    Solution
    Let the total profit be p and a, b and c be the respectively shares of Anu, Manu and Kanu in the profit.
    Since 20% of the profit is divided among Anu and Manu,
    Actual profit to be divided according to their investments = 0.80p

    a =

    p = 800 p = Rs.3586
    Hence, Anu's share in the profit =
    a = Rs. 1862
  • Question 11
    1 / -0
    Mohan sold two books for Rs. 140 each. His profit on one was 20% and his loss on the other was 20%. Which of the following statements is correct according to the given conditions?
    Solution
    For 20% Profit:
    120% = 140
    100% =
    So, CP of the 1st book = Rs. 116.67
    Profit = Rs. (140 - 116.67) = Rs. 23.3 (approx.)

    For 20% Loss:
    80% = 140
    100% =
    So, CP for the 2nd book = Rs. 175
    Loss = 175 - 140 = Rs. 35
    So, overall loss = Rs. (35 - 23.3) = Rs. 11.7 = Rs. 12 (approx.)
  • Question 12
    1 / -0
    A sweet-seller declares that he sells sweets at the cost price. However, he uses a weight of 800 g instead of 1 kg. What is his percentage profit?
    Solution
    Fair CP of 1 kg sweets = Rs. 100
    Actual CP of 1 kg sweets (using false weight of 800 g) = Rs. 80
    Profit earned (due to false weight) = Rs. 20
    Profit % = 20 x 100/80 = 25%
  • Question 13
    1 / -0
    The S.P. of 12 articles is equal to the C.P. of 10 articles. What is the loss percentage?
    Solution
    There is a loss of 2 articles for every 12 articles.
    Therefore, percentage loss = × 100 = 16.66%.
  • Question 14
    1 / -0
    The accounts of a company show sales of Rs. 12,600. The primary cost is 35% of sales and trading cost accounts for 25% of the gross profit. Gross profit is arrived at by excluding the primary cost plus the cost of advertising expenses of Rs. 1400, director`s salary of Rs. 650 per annum plus 2% of annual sales as miscellaneous costs. Find the percentage profit (approx.) on a capital investment of Rs. 14,000.
    Solution
    Primary cost = x 12600 = Rs. 4410
    Gross profit = 12600 - (4410 + 1400 + 650 + 2 x ) = 12600 - (4410 + 2050 + 252) = Rs. 5888
    Trading cost = x 5888 = Rs. 1472
    Net profit = 5888 - 1472 = Rs. 4416
    % profit on capital investment = = 31.54%
  • Question 15
    1 / -0
    Beetel is a telephone manufacturing company. It has a target of 18% gain by selling 1,000 sets. But to some buyers, it sells at cheaper prices. It sells some at a gain of 25% and the rest at a gain of 15% and achieves its target. How many sets does it sell, respectively?
    Solution
    Let the number of sets sold at 25% profit be x.
    1.25x + (1000 - x)(1.15) = 1000 x 1.18
    1.25x +1150 - 1.15x = 1180
    0.1x = 30
    x = 300
    300 at the profit of 25% and 700 at the profit of 15%
  • Question 16
    1 / -0
    A grocer mixes 26 kg of tea, which costs Rs. 20 per kg with 30 kg of tea, which costs Rs. 36 per kg. He sells the mixture at Rs. 30 per kg. What is his profit percentage?
    Solution
    Total CP = 26 20 + 30 36 = Rs. 1600
    Total SP = (26 + 30) 30 = 56 30 = Rs. 1680
    Profit = 1680 - 1600 = Rs. 80
    Profit percentage = = 5%
  • Question 17
    1 / -0
    A man sells an article at a gain of 10%. If he had bought it at 10% less and sold it for Rs. 132 less, he would have still gained 10%. Find the cost price of the article.
    Solution
    Let the CP of the article be Rs. x.
    According to the given condition:
    1.1 x - 132 = 1.1(0.9x)
    1.1x - 0.99x = 132
    0.11x = 132
    x = 1200
    Therefore, cost price = Rs. 1200
  • Question 18
    1 / -0
    There are 800 waiters in a hotel, of which 60% are males and the rest are females. The male waiters get a tip of 5% of the bill and the female waiters get a tip of 8% of the bill. If the ratio of the number of males to that of females gets reversed next year, but the total number of waiters remains the same, then find the percentage change in the total tip amount. (Assume that each male waiter gets an order of Rs. 600 and each female waiter gets an order of Rs. 500.)
    Solution
    Number of male waiters = 800 × = 480
    Number of female waiters = 800 × = 320
    Total tip amount to male waiters = 480 × 600 × = Rs. 14,400
    Total tip amount to female waiters = 320 × 500 × = Rs. 12,800
    Total tip amount = 14,400 + 12,800 = Rs. 27,200
    Now, the ratio of male and female waiters are reversed.
    Total tip amount to male waiters = 320 × 600 × = Rs. 9,600
    Total tip amount to female waiters = 480 × 500 × = 19,200
    Total tip amount = 9,600 + 19,200 = Rs. 28,800
    % change = × 100 = 5.88% increase
  • Question 19
    1 / -0
    X, Y and Z invested in a company. X invests of Z, and Y invests of X and Z invests Rs.50000. The profit of the Firm is 25% of the total capital invested. X, Y and Z get 10%, 12% and 15% of their capital respectively. X is the manager of the company. Find how much would X get extra per month for managing the company.
    Solution
    z = 50000
    x = 50000 x = 37500

    y = 37500 ´ = 25000
    Profit = (50,000 + 25,000 + 37500) x

    = 28125

    Z = 7500

    Y = 3000

    X = 3750

    Total = 14250

    Rest of the profit goes to X for managing the company.
    So, extra money received by X (per month) = (28125 - 14250)/12 = 1156.25

  • Question 20
    1 / -0
    The cost of running a printing machine is Rs. 320 per 1000 copies. The cost of setting is Rs. 2000 up to 5000 copies and after this, the cost of setting is 30 paise per copy. The other costs are 60 paise per copy. 10,000 copies are printed but only 8260 copies at the rate of Rs. 1.75 are sold. What is the sum to be obtained from advertisement to give a profit of 30% on the cost?
    Solution
    Total cost = 3200 + (2000 + 1500) + 6000 = 12,700
    Selling price = 8260 x 1.75 = 14,455
    Total sum (With 30% profit) = 12,700 x = 16,510
    Net sum to be received from advertisement = 16,510 - 14,455 = Rs. 2055.
  • Question 21
    1 / -0
    Rajgopalan purchased a second hand TV for Rs. 4800 and spent 20% of the cost on its repairing. If he wants to earn (by selling) Rs. 1440 as net profit on it, how much percentage should he increase the purchase price of the TV?
    Solution
    Repairing cost = 0.2 4800 = Rs. 960
    To earn net profit of Rs. 1440, he should also recover his repair cost.
    It means he has to add Rs. 2400, i.e. (1440 + 960), to his purchase price to earn Rs. 1440 as net profit.
    % markup = () × 100 = 50%
  • Question 22
    1 / -0
    The marked price of two articles are in the ratio of 3 : 7. The retailer gave the equal discount (in Rs. terms) on both the articles, and the selling prices of these two articles are in the ratio of 1 : 5. What are their respective marked prices?
    Solution
    Lets say the marked prices are 3x and 7x.
    And he gives Rs.y as discount
    Selling price = (3x - y) and (7x - y)
    The ratio of selling price = =
    15x - 5y = 7x - y
    8x = 4y

    But this ratio, doesn`t conclude any thing. So, we are unable to find the marked prices of these two articles.

  • Question 23
    1 / -0
    A businessman marks his goods in such a way that even after allowing 12.5% discount on cash purchase, he gains 20%. If the cost price of the goods is Rs. 140, find the marked price.
    Solution
    12.5% or discount is on the marked price (MP).
    ∴ SP = MP …(1)
    Also, CP = Rs. 140
    Profit = 20%
    SP = Rs. 1.2 × 140 = Rs. 168 …(2)
    From (1) and (2), we get
    MP = Rs. 168
    MP = Rs. 192
  • Question 24
    1 / -0
    A dealer marks articles at a price that gives him a profit of 30%. Unfortunately, 6% of the goods were lost in a fire accident and 24% were soiled and had to be sold at half of the cost price. If the remaining of the goods were sold at the marked price, what percentage profit or loss did the dealer earn?

    Enter your answer in the box given below:
    Solution
    Let the total number of articles be N and the cost of each article be $100
    Marked price = $130
    Selling price of soiled article (24%) = 24% of N x 50 = 12N
    Selling price of rest of the articles = 70% of N x 130 = 91N
    Total selling price = 91N + 12N = 103N
    Hence, profit = 3%
  • Question 25
    1 / -0
    A pharmaceutical company produce 6000 bottles of cough syrup for Rs.1,32,000. It distributed 20% of the bottles to the doctors as a sample and sold of the remaining bottles at 25% discount. The remaining bottles were sold at the printed price of the bottle that was 50% more than the cost price. It gives 10% discount on the sale price to the shopkeepers. Find the profit or loss.
    Solution
    Cost price = = Rs.22
    Selling Price =
    Selling price of rest of the bottles
    = 4800 x
    = 720 x 110 = Rs.79,200
    SP of the remaining = 1600 x 33 x = Rs.47520
    Total S.P. = Rs.1,26,720
    Loss (%) = = 4%

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