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    The length of a glass rod is found to be 1m on a meter scale made of Copper when both were at 50°C. The copper scale is correct at 0°C. If the coefficient of linear expansion of Copper and glass are 1.7 x 10-5 /°C and 0.8 x 10-5 /°C, then the length of the glass rod at 0°C is

    Solution

    The length of the scale at 50°C is 1(1 + 1.7 x 10-5 x 50) and the length of the glass rod is L (1 + 0.8 x 10-5 x 50). As both are equal, 1(1 + 1.7 x 10-5 x 50) = L (1 + 0.8 x 10-5 x 50), solving for L we get, L =1.0045 m

     

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