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Electromagnetic Induction Test - 1

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Electromagnetic Induction Test - 1
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    In an LR circuit, the reactance of the given inductor L is 40Ω , and the value of R is 30 Ω. If in the circuit, an alternating emf of 200 V at 50 cycles/s is connected, the impedance of the circuit and the current will be

    Solution

    Z = (R2 + XL2)1/2,

    Z = {(40)2 + (30)2}1/2 = 50 ohm

    I = V/Z = 200/50 = 4 A

     

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