Mix Test

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Mix Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

The speed of a car is $45$ km/hr. How much distance can it travel in $50$ seconds?

A
$575$ m

B
$625$ m

C
$650$ m

D
$550$ m

Solution

Given,
Speed of car $= 45$ km/hr
To convert speed from km/hr in m/s we multiply it with $\frac{5}{18}$ .
$∴$ Speed of car $= 45 \times \frac{5}{18} = \frac{25}{2}$ m/s
Time taken $= 50$ s
As we know,
Speed $= \frac{Distance}{Time}$
Distance $=$ Speed $\times$ Time
$∴$ Distance $= \frac{25}{2} \times 50$
$= 25 \times 25$
$= 625$ m
So, the distance travelled is $625$ m.
Hence, the correct option is (B).
Question 2
1 / -0

Find the volume of a cuboid whose length is $100$ m, breadth is $0.2$ m and height is $0.15$ m.

A
$3$ m $^{3}$

B
$4$ m $^{3}$

C
$5$ m $^{3}$

D
$6$ m $^{3}$

Solution

Given,
Length $= 100$ m
Breadth $= 0.2$ m
Height $= 0.15$ m
As we know,
Volume of the cuboid $=$ Length $\times$ Breadth $\times$ Height
Volume of the cuboid $= 100 \times 0.2 \times 0.15 = 3$ m $^{3}$
Hence, the correct option is (A).
Question 3
1 / -0

The sum of $64 %$ of a number and $76 %$ of the same number is $84$ . What is $40 %$ of that number?

A
$24$

B
$30$

C
$60$

D
$64$

Solution

Let the number be $x$ .
According to the question,
$64 %$ of $x + 76 %$ of $x = 84$
$\Rightarrow \frac{64}{100} x + \frac{76}{100} x = 84$
$\Rightarrow (\frac{64 + 76}{100}) x = 84$
$\Rightarrow \frac{140}{100} x = 84$
$\Rightarrow x = \frac{84 \times 100}{140}$
$\Rightarrow x = 60$
$∴ 40 %$ of $60 = \frac{40}{100} \times 60 = 24$
Hence, the correct option is (A).
Question 4
1 / -0

Find the area of a circle whose radius is $21$ cm. [Take $π = \frac{22}{7}$ ]

A
$1836$ cm $^{2}$

B
$1436$ cm $^{2}$

C
$1636$ cm $^{2}$

D
$1386$ cm $^{2}$

Solution

Given,
Radius $r = 21$ cm
$π = \frac{22}{7}$
As we know,
Area of the circle $= π r^{2}$
Area of the circle $= \frac{22}{7} \times 21 \times 21$
$= 22 \times 3 \times 21$
$= 1386$ cm $^{2}$
Hence, the correct option is (D).
Question 5
1 / -0

Find the simple interest on the sum of Rs. $35000$ for $2$ years at $12 %$ per annum.

A
Rs. $8600$

B
Rs. $9400$

C
Rs. $8800$

D
Rs. $8400$

Solution

Given,
Principal $=$ Rs. $35000$
Time $= 2$ years
Rate of interest $= 12 %$ per annum
As we know,
Simple Interest $= \frac{P \times R \times T}{100}$
Where, $P =$ Principal, $R =$ Rate of interest and $T =$ Time period.
Simple Interest $= \frac{(35000 \times 12 \times 2)}{100} =$ Rs. $8400$
$∴$ The simple interest is Rs. $8400$ .
Hence, the correct option is (D).
Question 6
1 / -0

Cost price of an article is Rs. $200$ . If it is sold for Rs. $198$ then find the loss percentage?

A
$2 %$

B
$1 %$

C
$8 %$

D
$12 %$

Solution

Given,
Cost price $(C P) =$ Rs. $200$
Selling Price $(S P) =$ Rs. $198$
As we know,
Loss $=$ Selling Price $-$ Cost Price
Loss $=$ Rs. $(200 - 198) =$ Rs. $2$
Loss $% = (\frac{Loss}{C P}) \times 100$
Loss $% = (\frac{2}{200}) \times 100 = 1 %$
Hence, the correct option is (B).
Question 7
1 / -0

If $P %$ of $P$ is $36$ , then $P$ is equal to:

A
$3600$

B
$60$

C
$15$

D
$600$

Solution

Given,
$P %$ of $P$ is $36$ .
$∴ \frac{P}{100} \times P = 36$
$\Rightarrow \frac{P^{2}}{100} = 36$
$\Rightarrow P^{2} = 36 \times 100$
$\Rightarrow P^{2} = 3600$
$\Rightarrow P = \sqrt{3600}$
$\Rightarrow P = 60$
$∴$ The value of $P$ is $60$ .
Hence, the correct option is (B).
Question 8
1 / -0

The cost price of a hard disk is Rs. $3200$ and the selling price is Rs. $3300$ , find the profit percentage.

A
$3.5 %$

B
$3.125 %$

C
$3.75 %$

D
None of these

Solution

Given,
The cost price of a Hard disk $(CP) =$ Rs. $3200$
The selling price of a Hard disk $(SP) =$ Rs. $3300$
As we know,
Profit $% = \frac{(SP - CP)}{CP} \times 100$
$\Rightarrow$ Profit $% = \frac{(3300 - 3200)}{(3200)} \times 100$
$\Rightarrow$ Profit $% = \frac{100}{3200} \times 100 = 3.125 %$
$∴$ Profit Percentage is $3.125 %$ .
Hence, the correct option is (B).
Question 9
1 / -0

I travel a distance of $10$ km and come back in $2 \frac{1}{2}$ hours. What is my speed?

A
$7$ km/hr

B
$10$ km/hr

C
$8$ km/hr

D
$14$ km/hr

Solution

Total distance covered $= 10$ km $+ 10$ km $= 20$ km
Time taken $= 2 \frac{1}{2} = \frac{5}{2}$ hours
As we know,
Speed $= \frac{Distance}{Time}$
Speed $= \frac{20}{\frac{5}{2}}$
$= \frac{20 \times 2}{5}$ km/hr
$= 8$ km/hr
Hence, the correct option is (C).
Question 10
1 / -0

A man took a loan of Rs. $700$ at the rate of $5 %$ per annum for $4$ years. Find the simple interest obtained on it.

A
Rs. $120$

B
Rs. $150$

C
Rs. $210$

D
Rs. $140$

Solution

Given,
Principal $(P) =$ Rs. $700$
Rate $(R) = 5 %$
Time $(T) = 4$ years
As we know,
Simple Interest $= \frac{(P \times R \times T)}{100}$
Simple Interest $= \frac{(700 \times 5 \times 4)}{100}$
$= 7 \times 20$
$=$ Rs. $140$
$∴$ The simple interest obtained is Rs. $140$ .
Hence, the correct option is (D).

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Mix Test - 2

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Mix Test - 2

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SHARING IS CARING

Question 1

575 m

625 m

650 m

550 m

Solution

Question 2

3 m3

4 m3

5 m3

6 m3

Solution

Question 3

24

30

60

64

Solution

Question 4

1836 cm2

1436 cm2

1636 cm2

1386 cm2

Solution

Question 5

Rs. 8600

Rs. 9400

Rs. 8800

Rs. 8400

Solution

Question 6

2%

1%

8%

12%

Solution

Question 7

3600

60

15

600

Solution

Question 8

3.5%

3.125%

3.75%

None of these

Solution

Question 9

7 km/hr

10 km/hr

8 km/hr

14 km/hr

Solution

Question 10

Rs. 120

Rs. 150

Rs. 210

Rs. 140

Solution

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Question Analysis

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$575$ m

$625$ m

$650$ m

$550$ m

$3$ m $^{3}$

$4$ m $^{3}$

$5$ m $^{3}$

$6$ m $^{3}$

$24$

$30$

$60$

$64$

$1836$ cm $^{2}$

$1436$ cm $^{2}$

$1636$ cm $^{2}$

$1386$ cm $^{2}$

Rs. $8600$

Rs. $9400$

Rs. $8800$

Rs. $8400$

$2 %$

$1 %$

$8 %$

$12 %$

$3600$

$60$

$15$

$600$

$3.5 %$

$3.125 %$

$3.75 %$

$7$ km/hr

$10$ km/hr

$8$ km/hr

$14$ km/hr

Rs. $120$

Rs. $150$

Rs. $210$

Rs. $140$