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NSO - Mock Test - 3

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NSO - Mock Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Read the following information carefully and answer the question.

    If the code for FOOTBALL is 8 and the code for HOCKEY is 6, then what is the code for BADMINTON?

    Solution

    The given codes are according to the number of letters. The word 'football' has 8 letters and 'hockey' has 6 letters. In the same manner, 'badminton' will have 9 as its code.

     

  • Question 2
    1 / -0

    In the following numbers, one number is incorrect. Find out the odd number.

    54, 9, 15, 6, 24, 4, 16

    Solution

    Two alternate series are going as follows:
    54, 15, 24, 16
    16 × 1.5 = 24
    24 × 1.5 = 36
    36 × 1.5 = 54
    The second series is 9, 6, 4
    4 × 1.5 = 6
    6 × 1.5 = 9
    So, 15 is the wrong number.

     

  • Question 3
    1 / -0

    Read the following information carefully and answer the question given below.

    Amit was looking at a photograph in his house nostalgically, it was a photo of a young man. While pointing at it Amit said, "I have no brother or sister but that man's father is my father's son." What was the relation of Amit to the man in the photograph?

    Solution

    Since Amit has no brother, his father's son is he himself.
    So, the man who is talking is the father of the man in the photograph.
    The man in the photograph is his son.

     

  • Question 4
    1 / -0

    There is some relationship between the two pairs of numbers on the left of the sign (: :). The same relationship exists between the two terms to its right, of which one is missing. Find the missing term from the given alternatives.

    26 : 63 : : 511 : ____

    Solution

    (3)3 - 1 = 26
    (4)3 - 1 = 63

    Similarly,
    (8)3 - 1 = 511
    (9)3 - 1 = 728

     

  • Question 5
    1 / -0

    Which number should come next in the given series?

    600, 650, 702, 756, ?

    Solution

    25 × 25 = 625 - 25 = 600
    26 × 26 = 676 - 26 = 650
    27 × 27 = 729 - 27 = 702
    28 × 28 = 784 - 28 = 756
    29 × 29 = 841 - 29 = 812

     

  • Question 6
    1 / -0

    A uniform electric field and a uniform magnetic field are produced, pointed in the same direction. An electron is projected with its velocity pointed in the same direction. Then,

    Solution

    When the charge particle is moving parallel to the magnetic field, force exerted by the magnetic field on it will be zero. The force exerted by the electric field on the electron will be opposite to the direction of the electric field.

    Hence, if the electron is moving parallel to the electric field and the magnetic field, the electron will move in the same straight direction with decreasing speed.

     

  • Question 7
    1 / -0

    It is not advised to store curd and other sour substances in copper or brass vessels because

    Solution

    All sour substances like curds and pickles contain acids, and acids react with metals.
    Such food if kept in brass or copper vessels will cause chemical reactions, which are likely to yield toxic products.

     

  • Question 8
    1 / -0

    Which of the following statements is/are the correct reason(s) for rubbing a magnesium ribbon with sand paper before burning it in air ?

    I. The surface is covered with a layer of magnesium oxide.
    II. Cleaning gives a better reaction as magnesium is a moderately reactive metal.

    Solution

    Magnesium is a reactive metal and it reacts with the atmospheric oxygen to form a layer of magnesium oxide on its surface.
    This oxide of magnesium further reacts with the CO2 and water vapour in the air to form a layer of basic magnesium [MgCO3.Mg(OH)2].
    In order to remove this layer, the magnesium ribbon is cleaned with sand paper.

     

  • Question 9
    1 / -0

    Consider the balanced equation of the reaction between the aqueous solutions of barium chloride and sodium sulphate:

    BaCl2 + Na2SO4 → BaSO4 + 2NaCl

    Which of the following species can be separated from the mixture as a solid precipitate?

    Solution

    This is a double replacement reaction in which an exchange of ions takes place between the reactant species.
    BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)
    The BaSO4 formed is an insoluble salt and appears as a white ppt.

     

  • Question 10
    1 / -0

    Why does a solution of copper sulphate change its colour when an iron nail is dipped into it?

    Solution

    When an iron nail is dipped in the copper sulphate solution, the iron displaces copper from the copper sulphate because iron is more reactive than copper. Therefore, the colour of the solution changes from the blue of copper sulphate to the green of ferrous sulphate.

     

  • Question 11
    1 / -0

    What is the most significant limitation of Dobereiner's classification of elements?

    Solution

    The main limitation of the Dobereiner's classification was that all the known elements could not be classified into triads on the basis of their properties.
    Only three triads were identified:

    1. Triad of alkali metals
    2. Triad of alkaline earth metals
    3. Triad of halogens.

     

  • Question 12
    1 / -0

    The position of an element in the periodic table is related to its electronic configuration. In this context, identify the correct statement among the following.

    Solution

    In the modern periodic table, atoms with similar electronic configuration are placed in the same vertical column or group and they exhibit similarity in their chemical properties. Hence, option (2) is correct.
    In a group, the number of valence electrons remains the same.
    Elements across a period show an increase in the number of valence electrons.

     

  • Question 13
    1 / -0

    How many moles of iron will react with excess of water to produce four moles of hydrogen gas?

    Fe + 4H2O → Fe3O4 + 4H2

    Solution

    A balanced equation should have equal number of atoms of each element on each side of the equation.
    All the elements besides Fe are already balanced.
    The balanced equation shows that 3 moles of Fe react with 4 moles of H2O to produce 1 mole of Fe3O4 and 4 moles of H2.

     

  • Question 14
    1 / -0

    Look at the following reaction equations and choose which one shows double displacement?

    I. 2KBr (aq) + Bal2 (aq) → 2KI (aq) + BaBr2 (aq)
    II. 2KBr (aq) + F2 (aq) → 2KF (aq) + Br2 (aq)

    Solution

    A double displacement reaction is the one in which an exchange of ions takes place between the reactant species.
    Option I depicts a double displacement reaction.
    2KBr (aq) + Bal2 (aq) → 2KI (aq) + BaBr2 (aq)
    Option II depicts a displacement reaction in which a more reactive halogen displaces a less reactive one.

     

  • Question 15
    1 / -0

    Gibberellins were discovered by a Japanese botanist while studying the "foolish seedling" disease in rice. They were first isolated from the fungus known as

    Solution

    Gibberellins were discovered in 1926 by a Japanese scientist, Eiichi Kurosawa, studying bakanae, the "foolish seedling" disease in rice. It was first isolated in 1935 by Teijiro Yabuta and Sumuki, from fungal strain (Gibberella fujikuroi) provided by Kurosawa.

     

  • Question 16
    1 / -0

    What kind of epithelium is found in our respiratory system?

    Solution

     

    Ciliated epithelial tissue is found in our respiratory tract and in the Fallopian tubes of women. Ciliated epithelium contains goblet cells, which secrete mucous. This mucous, combined with the cilia on the tissue, helps move harmful particles out of our bodies to keep us healthy.

     

  • Question 17
    1 / -0

    It is a biological fact that human stomach produces acid. Which of the following is not a role of hydrochloric acid produced by the stomach?

    Solution

    The primary role of hydrochloric acid is to sterilise the food you eat and to prevent harmful bacteria from entering the GI tract. HCl also triggers the release of enzymes such as pepsin, which are essential for the digestion of protein.

     

  • Question 18
    1 / -0

    Villi are adapted for the maximum absorption of digested food molecules. Which property makes them suitable for the same?

    Solution

    Villi are adapted for the maximum absorption of digested food molecules. This is because the folded villi greatly increase the surface area of the intestine; the villi are made of a single layer of thin cells; beneath the villi is an extensive blood capillary network to distribute the absorbed food molecules.

     

  • Question 19
    1 / -0

    Site of transfer of oxygen and other nutrients from the bloodstream to other tissues in the body is

    Solution

    Capillaries are the smallest of the body's blood vessels. They are only one cell thick, and they are the site of the transfer of oxygen and other nutrients from the bloodstream to other tissues in the body. They also collect carbon dioxide waste materials and fluids for return to the veins.

     

  • Question 20
    1 / -0

    It is practically impossible to kill a sponge. This is due to the process of

    Solution

    All sponges possess a remarkable ability to regenerate lost parts. A piece cut from the body of a sponge is capable of growing into a complete sponge. Due to this, it is impossible to kill a sponge.

     

  • Question 21
    1 / -0

    "These are very beneficial for an organism while reproducing. These are distributed easily by air to far-off places to avoid competition at one place. Large numbers are produced in a single sporangium and they are also covered with thick walls to avoid dehydration."

    From the passage of the arguments given above, find out the unit of reproduction being discussed.

    Solution

    A spore is a unit of sexual or asexual reproduction that may be adapted for dispersal and for survival, often for extended periods of time, in unfavourable conditions. The description given is of fungal spores.

     

  • Question 22
    1 / -0

    Consider the statements given below regarding biomagnification and choose the correct option that follows.

    Statement I: Biomagnification is the increasing concentration of a substance, such as a toxic chemical in the tissues of an organism.
    Statement II: Bioaccumulation occurs within a trophic level whereas biomagnification occurs across trophic (food chain) levels.

    Solution

    Both the statements are true. Biomagnification is the increasing concentration of a substance, such as a toxic chemical, in the tissues of organisms at successive higher levels in a food chain. Bioaccumulation occurs within a trophic level whereas biomagnification occurs across trophic (food chain) levels.

     

  • Question 23
    1 / -0

    A highly polluted city will not show the growth of

    Solution

    The hardy lichens are useful bio-indicators for air pollution, especially sulphur dioxide pollution, since they derive their water and essential nutrients mainly from the atmosphere rather than from the soil.

     

  • Question 24
    1 / -0

    The presence of which of the following metals causes the teeth of the children to discolour?

    Solution

    Excess fluoride in water leads to yellowing of teeth. It causes a condition known as dental fluorosis.

     

  • Question 25
    1 / -0

    The structure that prevents the acidic contents of the stomach from moving upward into the esophagus is

    Solution

    The cardiac sphincter, at the upper portion (cardia) of the stomach, prevents the acidic contents of the stomach from moving upward into the esophagus.

     

  • Question 26
    1 / -0

    The primary form of sugar transported from the site of photosynthesis to the rest of the plant is

    Solution

    The primary form of sugar transported from the site of photosynthesis to the rest of the plant is sucrose. Starch is the storage form of carbohydrates.

     

  • Question 27
    1 / -0

    The pathway which is common to both aerobic and anaerobic pathways of respiration is

    Solution

    Glucose is broken down by the process of glycolysis. This is the common pathway for both aerobic and anaerobic conditions. Under aerobic conditions, pyruvate formed enters the Kreb's cycle. Under anaerobic conditions, pyruvate is converted into lactate in muscles.

     

  • Question 28
    1 / -0

    Match the below mentioned parts of human heart in column I with their appropriate functions in column II.

    Column I Column II
    (a) Septum (i) Carry the deoxygenated blood to right atrium of the heart
    (b) Pulmonary artery (ii) Receives blood from lungs
    (c) Inferior vena cava (iii) Maintains rigidity and support to the heart
    (d) Left auricle (iv) Transports oxygen-depleted blood to lungs
    Solution

    Septum is responsible for maintaining rigidity and support to the heart and it helps in proper functioning of the heart.
    Inferior vena cava carries de-oxygenated blood from the lower half of the body to the right atrium of the heart. Pulmonary artery is responsible for transporting oxygen-depleted blood away from the heart and towards the lungs.
    Left auricle receives blood from the lungs.

     

  • Question 29
    1 / -0

    Urea, the principal nitrogenous excretory compound in humans, is synthesised

    Solution

    Urea is the principal nitrogenous compound which is excreted by the humans. It is synthesised in the liver by urea cycle but excreted via kidneys.

     

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