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Sorting And Separation of Materials Test - 5

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Sorting And Separation of Materials Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Select from the given options the pair of objects/substances that will float in water.
    Solution
    Pencil and ice have a lesser density than water, i.e. they are lighter than water.
    Hence, they float in water.
  • Question 2
    1 / -0
    Classify the following objects into different groups and choose the correct option among those given below:

    1. Pencil
    2. Wooden table
    3. Notebook
    4. Bucket
    5. Polythene bag
    6. Plastic chair
    7. Bullock cart
    Solution
    Pencil, wooden table, notebook and bullock cart are classified together in group I as they are made up of wood/paper and are biodegradable; whereas bucket, polythene bag and chair are plastic products and are non-biodegradable, so they are classified together in group II.
  • Question 3
    1 / -0
    Shreya is provided with the following objects and asked to put them in a bucket containing water.

    Wooden toy, iron nail, stone, plant leaf, and plastic ball

    Which among the given objects will float and which will sink in water?
    Solution
    Objects like wooden toy, plant leaf and plastic ball being less dense will float in water, whereas iron nail and stone will sink as they have a greater density than water.
  • Question 4
    1 / -0
    Classify the following materials on the basis of their appearance and choose the correct option.

    1. Cardboard 5. Wood
    2. Copper wire 6. Iron nail
    3. Aluminium sheet 7. Steel rod
    4. Chalk 8. Silver coin
    Solution
    Cardboard, chalk and wood are classified together in group I as they are not metallic materials.
    However, copper wire, aluminium sheet, iron nail, steel rod and silver coin are classified together in group II as they are metallic objects.
  • Question 5
    1 / -0
    Four students are provided with four different substances as listed below:

    Student A - Chalk powder
    Student B - Salt
    Student C - Sand
    Student D - Sugar

    When these substances are added to water, which of the students will obtain a solution?
    Solution
    Salt and sugar are water soluble substances as they completely dissolve in water to form true solutions. However, sand and chalk powder are insoluble in water and form a suspension when mixed with water and settle down if left undisturbed.
  • Question 6
    1 / -0
    Which of the following properties of materials is not considered during classification?
    Solution
    Materials can be classified into soluble or insoluble substances on the basis of their solubility in water or any other given solvent.
    They may be grouped as conductors or insulators, on the basis of their conductivity.
    They may be classified as transparent, translucent or opaque on the basis of transmission of light.
    However, mass is not an appropriate property to classify the materials.
  • Question 7
    1 / -0
    Which of the following statements is/are incorrect?

    a. Iodine crystals have lustre.
    b. All metals have a silvery white lustre.
    c. Wood is a non-lustrous material.
    Solution
    Statement 'b' is not correct as all metals do have a lusture, but it may not always be silvery white.
    For example, gold has a yellow lusture and copper has a reddish brown lusture.
    Iodine crystals have lusture and wood is a non-lustrous material. Hence, statements 'a' and 'c' are correct.
  • Question 8
    1 / -0
    Which of the following statements is correct about homogeneous and heterogeneous mixtures?
    Solution
    Salad is a typical example of a heterogeneous mixture.

    The other statements are incorrect as all mixtures (homogeneous or heterogeneous) have a variable composition.
    All the components in a homogeneous mixture are in the same phase.
  • Question 9
    1 / -0
    Which of the following mixtures is a true solution?
    Solution
    True solution is a homogeneous mixture of two or more mutually inert substances.
    The particles of the solute are less than 10-9 m or 1 nm radius and impart the characteristic properties to the solution.
    Simple solution of salt in water is an example of true solution.
  • Question 10
    1 / -0
    Which of the following statements is not true regarding methane?
    Solution
    Methane is a compound and is formed by the chemical combination of its elements in fixed proportions.
  • Question 11
    1 / -0

    Rohan's class teacher explained the difference between pure substances and mixtures, and gave some examples from daily life. Choose the option which is a pure substance among the following.

    Solution

    A pure substance is made up of only one type of component particles. All elements and compounds are made up of the same kind of molecules or atoms and are pure substances. Gold being an element is a pure substance.

  • Question 12
    1 / -0
    Which of the following statements is false regarding compounds?
    Solution
    This is the correct answer because new substances formed exhibit completely different properties from their constituent elements.
  • Question 13
    1 / -0
    If 20 ml of alcohol is present in 400 ml of its aqueous solution, calculate the concentration of this solution.
    Solution
    This is the correct option. This solution also contains a liquid solute (alcohol) mixed with a liquid solvent, i.e. water (because it is an aqueous solution), so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol).

    Here, volume of solute (alcohol) = 20 ml
    Volume of solution = 400 ml
    So, concentration of solution =

    = = 5%
  • Question 14
    1 / -0
    A solution contains 20 g of salt dissolved in 180 g of water. Calculate the concentration of this solution.
    Solution
    This solution contains a solid solute (salt) dissolved in a liquid solvent (water). We have to calculate the concentration of this solution in terms of mass percentage of solute.

    Now, concentration of solution = x 100
    Here, mass of solute = 20 g
    Mass of solution = 180 g
    Thus, mass of solution = Mass of solute + Mass of solvent
    = 20 + 180 = 200 g
    Thus, concentration of solution = x 100 = 10%
    This is the correct option.
  • Question 15
    1 / -0
    If 200 litres of kerosene is present in 1000 litres of a solution, calculate the concentration of this solution.
    Solution
    This solution contains kerosene mixed with a solution; so we need to calculate the concentration of this solution in terms of volume percentage of solute.

    Here, volume of solute = 200 litres

    Volume of solution = 1000 litres

    Therefore, concentration of solution =

    =

    = 20%

    Thus, this is the correct option.
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