Force Test

Result

Force Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

A body of mass 2 kg is sliding with a constant velocity of 4 m/s on a frictionless horizontal table. The force required to keep the body moving with the same velocity is

A
8 N

B
0 N

C
2 × 10⁴N

D
1/2 N
Question 2
1 / -0

In a game of snooker, two balls each of mass 200 g are moving in the same straight line but in the opposite directions with a velocity of 2 ms^-1 each. The balls then collide and stick together.
What is the velocity of combined balls after the collision?

A
2 ms^-1

B
4 ms^-1

C
Zero

D
6 ms^-1
Question 3
1 / -0

A ball of mass 2 kg bounces with a horizontal velocity of 2 ms^-1 in a stationary box with frictionless wheels. The mass of the box is 6 kg. What will be the velocity of the ball as the box starts moving?

A
0.5 ms^-1

B
2 ms^-1

C
1 ms^-1

D
2.5 ms^-1
Question 4
1 / -0

A body of weight w₁ is suspended from the ceiling of a room using a chain of weight w₂. What is the force with which the ceiling pulls the chain?

A
w₁

B
w₁ + w₂

C
w₁ - w₂

D
0
Question 5
1 / -0

A scooter generally slips on an oily road because

A
friction between the tyres and the road increases

B
friction between the tyres and the road decreases

C
inertia between the tyres and the road increases

D
all the above
Question 6
1 / -0

Work done by a body against friction 1 always results in a loss of its

A
kinetic energy

B
potential energy

C
both (1) and (2)

D
none of these

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Re-Attempt Weekly Quiz Competition

Force Test - 4

Result

Force Test - 4

Score

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Rank

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SHARING IS CARING

Question 1

8 N

0 N

2 × 104 N

1/2 N

Question 2

2 ms-1

4 ms-1

Zero

6 ms-1

Question 3

0.5 ms-1

2 ms-1

1 ms-1

2.5 ms-1

Question 4

w1

w1 + w2

w1 - w2

0

Question 5

friction between the tyres and the road increases

friction between the tyres and the road decreases

inertia between the tyres and the road increases

all the above

Question 6

kinetic energy

potential energy

both (1) and (2)

none of these

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2 × 10⁴N

2 ms^-1

4 ms^-1

6 ms^-1

0.5 ms^-1

2 ms^-1

1 ms^-1

2.5 ms^-1

w₁

w₁ + w₂

w₁ - w₂