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Force and Pressure Test - 2

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Force and Pressure Test - 2
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following options is/are TRUE?

    Solution

    Buoyant force is defined as the weight of the liquid displaced.
    Buoyant force = Density of the liquid × Volume of the liquid displaced × Acceleration due to gravity
    Hence, greater is the volume displaced, greater is the buoyant force. Volume displaced will be maximum when it is fully immersed. Greater is the density of the liquid, greater is the buoyant force.

     

  • Question 2
    1 / -0

    Read the following statements and choose the correct option.

    Statement A: Buoyant force on a fully immersed sphere will be more than that on a cube which is made of the same material and has the same mass as the sphere.

    Statement B: Sphere will displace less volume as compared to the cube.

    Solution

    Volume of the sphere will be less as compared to the cube hence it will displace less liquid in which it is immersed, so it will experience less buoyant force.

     

  • Question 3
    1 / -0

    A solid piece of iron sinks in water but floats in mercury. This is because the

    Solution

    The object will float in liquid if its density is less than the liquid in which it is immersed so density of iron is more than that of water but less than that of mercury.

     

  • Question 4
    1 / -0

    A sphere made of iron is immersed in water. Another sphere of same dimensions but made of aluminium is immersed in alcohol. Choose the correct statement from the following.

    Solution

    Buoyant force = Density of the liquid × Volume of the liquid displaced × Acceleration due to gravity

    Greater is the density of the liquid, greater is the buoyant force. Water has more density as compared to alcohol and will exert more buoyant force as compared to the alcohol.

     

  • Question 5
    1 / -0

    When you press a rubber sucker against a surface, most of the air between its cup and the surface escapes out. To pull the rubber sucker off the surface, the applied force should be

    Solution

    The rubber sucker sticks to the surface because the pressure of atmosphere acts on it. To pull the sucker off the surface, the applied force should be large enough to overcome the atmospheric pressure.

     

  • Question 6
    1 / -0

    What happens when a stream of air is blown through a tube under one of the pans of a physical balance in equilibrium?

    Solution

    As the stream of air is blown through a tube under one of the pans, due to the high air speed, the pressure below the pan decreases as compared to the pressure above the pan. Hence, there will be a net downward force acting on the pan and the pan will go down.

     

  • Question 7
    1 / -0

    A deep sea diver may hurt his eardrum during diving because of

    Solution

    When a diver dives into the deep sea, there is water on the outside of the ear drum, but air on the inside. The pressure inside will still be equal to atmospheric pressure. However, on the outside, the pressure will be greater. This means that the pressure of air inside the ear will not cancel the pressure of the water outside. There will be net inward force due to this pressure difference, as a result of which the eardrum will stretch. This stretching of the eardrum hurts.

     

  • Question 8
    1 / -0

    Water is flowing through a pipe under constant pressure. At some place, the pipe becomes narrow. The pressure of water at this place

    Solution

    As the area of cross section decreases velocity increases. At the narrow end as the area of cross section decreases, velocity increases.
    As the velocity increases, pressure decreases.

     

  • Question 9
    1 / -0

    A raft is 2.35 m wide, 1.25 m long, and 0.365 m deep. What is the buoyant force on the raft, if only 0.125 m of the raft remains above water? (Take g = 10 m/s2)

    Solution

    Upthrust acting on the object = Weight of the water displaced
    Weight of the water displaced = Volume of water displaced (Volume of the object in the water) × Density × g
    Volume of water displaced = 2.35 × 1.25 × 0.24 = 0.705 m3
    Hence, upthrust = 0.705 × 10× 10 = 7050 N

     

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