Force and Pressure Test

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Force and Pressure Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Force of friction on an object lying on a table is 29.4 N. What is the mass of the object if the coefficient of friction between the object and the table surface is 0.3?

A
2.94 kg

B
10 kg

C
98 kg

D
8.82 kg

Solution

F (Force of friction) = 29.4 N
μ (coefficient of friction) = 0.3
F = μR (R = mg)
29.4 = 0.3 x m x g
29.4 = 0.3 x m x 9.8
m = 10 kg
Question 2
1 / -0

A bullet of mass 50 g is horizontally fired with a velocity of 200 ms^–1 from a pistol of mass 4 kg. What is the magnitude of recoil velocity of the pistol?

A
2.5 ms^–1

B
2 ms^–1

C
3 ms^–1

D
1.5 ms^–1

Solution

m_B = 50 g = 0.05 kg
v_B = 200 m/s
m_p = 4 kg
Initial momentum = final momentum
m_B v_B + m_p V_p= 0
0.05 x 200 + 4 x v_p = 0
- 10/4 = v_p
- 2.5 m/s = v_p
The magnitude of recoil velocity = 2.5 m/s
Question 3
1 / -0

Two balls A and B of masses 2 kg and 3 kg are moving with velocities 3 ms^–1 and 2 ms^–1 respectively, towards each other. During the collision, they stick together. What will be the velocity of the combined balls after the collision?

A
2.4 ms^–1

B
0 ms^–1

C
5 ms^–1

D
1 ms^–1

Solution

m_A = 2 kg, m_B = 3kg
u_A = 3 m/s; u_B = 2 m/s
Acc. to the law of conservation of momentum:
m_A u_A + m_B u_B = (m_A+ m_B) v
2 x 3 + (-(3 x 2)) = (2 + 3) v (since balls are moving towards each other)
6 – 6 = 5 x v
0 m/s = v
Question 4
1 / -0

A ball of mass 200 g is moving with a velocity of 6 ms^–1. It is brought to rest after travelling a distance of 2 m by applying a resistive force. What is the value of the resistive force applied?

A
1.2 N

B
0.6 N

C
1.8 N

D
2 N

Solution

m = 200 g = 0.2 kg
U = 6 m/s
S = 2 m
Using v² – u² = 2aS
0 – 36 = 2 x F/m x S
- 36 = 2 x F/0.2 x 2
- 36 = 40/2 × F
- 36 = 36/20 = -1.8 N
Question 5
1 / -0

An applied force of 24 N [forward] causes a steel block to move across a horizontal greased steel surface. What is the approximate value of mass of the block?
(Take coefficient of friction = 0.15) (g = 9.8 m/s²)

A
2.4 kg

B
36 kg

C
1.6 kg

D
16 kg

Solution

F= 24 N
u = 0.15
F = uR
24 = 0.15 x m x 9.8
m = 16.3 kg

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Re-Attempt Weekly Quiz Competition

Force and Pressure Test - 4

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Force and Pressure Test - 4

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SHARING IS CARING

Question 1

2.94 kg

10 kg

98 kg

8.82 kg

Solution

Question 2

2.5 ms–1

2 ms–1

3 ms–1

1.5 ms–1

Solution

Question 3

2.4 ms–1

0 ms–1

5 ms–1

1 ms–1

Solution

Question 4

1.2 N

0.6 N

1.8 N

2 N

Solution

Question 5

2.4 kg

36 kg

1.6 kg

16 kg

Solution

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Question Analysis

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2.5 ms^–1

2 ms^–1

3 ms^–1

1.5 ms^–1

2.4 ms^–1

0 ms^–1

5 ms^–1

1 ms^–1