NSO - Mock Test

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NSO - Mock Test - 5

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Weekly Quiz Competition

Question 1
1.2 / -0

What is the mirror image of the word MOUSE, if the mirror is placed in the manner as given below?

A

B

C

D

Solution

The mirror image of the word MOUSE is as shown below:
Question 2
1.2 / -0

A number series is given with one term missing. Choose the correct option that will continue the same pattern

(3, 5) (4, 7) (5, 9) (6, 11) (7, 13) (__, __)

A
(7, 14)

B
(7, 15)

C
(8, 14)

D
(8, 15)

Solution

The pattern which follows in the given series is that the first digit is increased by 1 and the second digit is increased by 2, like 6 + 1 = 7 and 11 + 2 = 13. So, accordingly, the missing term is: (8, 15).
Question 3
1.2 / -0

Complete the following series:

36 33 37 34 38 ?

A
35

B
37

C
39

D
41

Solution

The pattern that follows in the series is as below:
36 – 3 = 33
33 + 4 = 37
37 – 3 = 34
34 + 4 = 38
38 – 3 = 35
Question 4
1.2 / -0

A family consists of six members P, Q, R, X, Y and Z. Q is the son of R, but R is not mother of Q. P and R are a married couple. Y is the brother of R. X is the daughter of P. Z is the brother of P. Who is the brother-in-law of R?

A
Z

B
P

C
Y

D
None of these

Solution

R is the husband of P, and Z is the brother of P, so Z is the brother-in-law of R.
Question 5
1.2 / -0

If in a certain language, VOLTAS is written as UNKSZR, then how will TEACH be written in that code?

A
SDZBG

B
SZDBG

C
SDZGB

D
GDZBS

Solution

Coding is as below:
V – 1 = U
O – 1 = N
L – 1 = K
T – 1 = S
A – 1 = Z
S – 1 = R
Similarly, TEACH in that code will be written as SDZBG.
Question 6
1.2 / -0

In the following series, how many 5's are there which are immediately preceded by a symbol and immediately followed by 8?

8963*#23%52^&58@568

A
One

B
Two

C
Three

D
None

Solution

There is only one 5 which is immediately preceded by a symbol and immediately followed by 8, i.e. "&58".
Question 7
1.2 / -0

Find out the missing number in the following pattern:

A
146

B
145

C
142

D
140

Solution

The logic followed is that take away 12 from every number that are on the both ends of line, like 144 – 12 = 132.
Similarly, 158 - 12 = 146
Question 8
1.2 / -0

If '+' means '-' and '÷' means 'x', then what is the value of (32 + 24) ÷ 5?

A
20

B
30

C
40

D
50

Solution

We know that '+' means '-' and '÷' means 'x', as per the question.
Accordingly, (32 + 24) ÷ 5 means (32 – 24) x 5.
Solving, we get
8 x 5 = 40
Question 9
1.2 / -0

Kavya started walking towards her office from her house. She walked 3 km towards west, then took a right turn and walked 2 km, and then again took a left turn and walked just 0.5 km, and then finally she reached her office. In what direction is Kavya's office from her house?

A
North

B
West

C
North-west

D
South-west

Solution

Kavya's office is in the north-west direction from her house.
Question 10
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Directions: In the following question, there is a certain relationship between two terms given on one side of (::) and one term is given on the other side of (::), while another term is to be found from the given alternatives having the same relationship with this term as the terms of the given pair bear. Choose the best alternative.

9 : 729 :: 11 : ?

A
1001

B
1111

C
1221

D
1331

Solution

The left side of the :: shows that the second number is the cube of the first number.
Accordingly, 11³= 1331
Question 11
1.2 / -0

Pewter is a tin-based alloy used as a material from which domestic utensils were fashioned.
It is about 91% tin, 7.5% antimony, and 1.5% copper.

How will you classify Pewter as a substance?

A
True solution

B
Colloid

C
Compound

D
Suspension

Solution

Alloys are homogeneous mixtures of two or more metals or metals and non metals. Hence, these are classified as true solutions.
Alloying helps to enhance the properties of the component metals and increases their field of applications.
Question 12
1.2 / -0

Which of the following is NOT a triatomic molecule?

A
Ozone

B
Carbon dioxide

C
Carbon monoxide

D
Nitrous oxide

Solution

Triatomic molecules are molecules composed of three atoms.
Carbon monoxide is diatomic: CO.
All the other options are triatomic.
Ozone: O₃
Carbon dioxide: CO₂
Nitrous oxide: N₂O
Question 13
1.2 / -0

Which of the following definitions best describes canal rays?

A
The positively charged radiation produced in the discharge tube that move towards the cathode

B
The collection of negatively charged particles emitted from cathode in the discharge tube experiment.

C
Produced by atoms of all elements except Hydrogen.

D
The collection of negatively charged particles emitted from cathode as well as from the atoms of the gas in the discharge tube experiment.

Solution

Canal rays are the positively charged radiation produced in the discharge tube that seem to emerge from the anode and move towards the cathode. When a perforated cathode is used, they produce scintillations behind the cathode. Goldstein called these positive rays Kanalstrahlen, "channel rays" or "canal rays", because they could be detected only when a perforated cathode was used.
Question 14
1.2 / -0

Which of the following methods is used to separate two solids that are soluble in the same solvent?

A
Solvent extraction

B
Fractional crystallisation

C
Distillation

D
Chromatography

Solution

Fractional crystallisation is the process of separating the components of a solution on the basis of their different solubilities in the same solvent.
On cooling a solution containing both the solutes, the less soluble component crystallises out first.
Question 15
1.2 / -0

In a species, the number of electrons is 2 less than the number of neutrons and the number of protons is one less than the number of neutrons. If the mass number is 23, the actual number of electrons, protons and neutrons respectively are

A
12, 13, 14

B
10, 11, 12

C
11, 12, 13

D
9, 10, 11

Solution

Let the number of neutrons be x.
Number of electrons = x - 2
Number of protons = x - 1
x + x - 1 = 23
x = 12
Therefore, the number of neutrons = 12
The number of protons = x - 1 = 12 - 1 = 11
Number of electrons = 12 - 2 = 10

The species is
Question 16
1.2 / -0

Which of the following mixtures can be separated by the method of centrifugation?

A
Camphor from salt

B
Iron from sand

C
Salt from sea water

D
Butter from curd

Solution

Centrifugation is the technique which is used to separate a mixture in which the components differ in their densities. e.g. curd from butter.
On agitating the mixture, butter (fat) being less dense will float on the top and can be separated from buttermilk.

A mixture of camphor and salt can be separated by sublimation.
A mixture of iron and sand can be separated by magnetic separation.
Salt is separated from sea water by evaporation.
Question 17
1.2 / -0

Analyze the two statements given below and select the correct option.

Statement I: At higher altitudes, water boils at a temperature below 100°C.
Statement II: Atmospheric pressure decreases with the increase in altitude.

A
Both the statements I and II are correct and statement II is the correct reason for I.

B
Both the statements I and II are correct but statement II is not the correct reason for I.

C
Statement I is correct but statement II is incorrect.

D
Both the statements I and II are incorrect.

Solution

Boiling point is the fixed temperature at which a substance changes its state from liquid to vapour. The liquid begins to boil when the vapour pressure becomes equal to the atmospheric pressure.
At higher altitudes the atmospheric pressure decreases and so does the boiling point.
Hence, both the statements I and II are correct and statement II is the correct reason for I.

Question 18

1.2 / -0

Match the colloidal mixtures listed in column I with the type of colloids listed in column II.

Column I	Column II
A. Milk	(i) Foam
B. Whipped cream	(ii) Gel
C. Ruby glass	(iii) Emulsion
D. Cheese	(iv) Solid sol

A - (iii); B - (iv); C - (i); D - (ii)

A - (iii); B - (i); C - (iv); D - (ii)

A - (ii); B - (i); C - (iv); D - (iii)

A - (iii); B - (i); C - (ii); D - (iv)

Solution

Milk is an example of emulsion in which both the dispersed phase and dispersion medium are liquids.
Whipped cream is an example of foam which is a gas in liquid colloid.
Ruby is an example of solid sol in which both the dispersed phase and the dispersion medium are solids.
Cheese is an example of gel in which the dispersed phase is liquid and dispersion medium is solid.
Hence, option (2) is correct: A - (iii); B - (i); C - (iv); D - (ii)

Question 19
1.2 / -0

Which of the following statements is/are correct?

I. The boiling point of oxygen gas is higher than room temperature.
II. At a temperature between the melting and boiling points, a substance will exist in the liquid state.

A
Both I and II are correct.

B
Both I and II are incorrect.

C
Only II is correct.

D
Only I is correct.

Solution

A substance exists in the gaseous state when it is at a temperature higher the boiling point. Since Oxygen is gaseous at room temperature, its boiling point is much below the room temperature. Hence, statement I is incorrect.
Statement II is correct because a substance will exist in the liquid state at a temperature higher than the melting point and lower than the boiling point.
Question 20
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Which of the following is the chemical name for baking soda?

A. Sodium carbonate
B. Potassium carbonate
C. Potassium hydroxide
D. Sodium bicarbonate

A
D

B
C

C
B

D
A

Solution

Sodium bicarbonate (NaHCO₃) is baking soda.
Question 21
1.2 / -0

If two objects are of equal mass m and traveling with equal speed (v) toward each other then which of the following statements are correct:-

1. Total momentum is 2mv
2. Total kinetic energy is mv²^{3. Total kinetic energy 0.
4. Total momentum is 0.}

A
Statement 1 and 2 are correct

B
Statement 2 and 4 are correct

C
Statement 3 and 4 are correct

D
Statement 1 and 3 are correct

Solution

The velocities are v and -v
Momentum in mv - mv = 0
The Kinetic energy is (mv²/2 + mv²/2) = mv² ^{Hence statement 2 and 4 are correct.}
Question 22
1.2 / -0

Look at the picture and tell the direction in which the road will apply the friction on the car?

A
Right to left ←

B
Left to right →

C
Both ways

D
In none of the given directions

Solution

The force of friction always opposes the translational motion. The car is moving from right to left. The friction will be applied by the road on the car in the direction from left to right →.
Question 23
1.2 / -0

The gravitational force between two different objects is F. If masses of both the objects are halved and the distance between them is also halved, then what would be the gravitational force?

A
F

B
F/2

C
F/4

D
F/16

Solution

According to the Newton' s law of gravitation, force between two masses is directly proportional the product of the masses and inversely proportional to square of distance

--- 1

When each mass is reduced to half and distance is also halved its value, then the force between them is still the same as that of F.
Question 24
1.2 / -0

A student is whirling a stone tied with a thread in a horizontal circular path. If the string breaks, what would happen to the stone?

A
It will continue to move in the circular path.

B
It will move along a straight line tangential to the circular path.

C
It will move along a straight line.

D
It will move along the straight line perpendicular to the circular path.

Solution

If a object is moving in the circle, the direction of the velocity of the object at any point is always tangential to circle. Because of the inertia of direction, the stone will move along a straight line tangential to the circular path when the string is broken..
Question 25
1.2 / -0

The weight of an object at the centre of the Earth with radius R is

A
zero

B
infinite

C
R times the value at the surface of the Earth

D
10 times the value at the surface of the Earth

Solution

The weight of the object is defined as the product of mass and acceleration due to gravity.

Acceleration due to gravity is given by:

The variation of the g with depth d is given by:

At centre of the Earth, d = R; g' = 0

Hence, the weight of the object at the centre of the Earth will be zero.
Question 26
1.2 / -0

A certain object weighed 10 N in air; but when it was in water, it weighed 8 N only. Calculate the weight of the liquid displaced by the object.

A
10 N

B
2 N

C
12 N

D
8 N

Solution

Apparent weight of the object in water = True weight of the object in air - upthrust

Upthrust = Weight of water displaced by the object
Hence, weight of water displaced = True weight - Apparent weight

Weight of water displaced = 10 - 8 = 2 N
Question 27
1.2 / -0

When an object is revolving around sun, then direction of centripetal force is

A
radially toward sun

B
radially away from sun

C
upward perpendicular to earth

D
downward perpendicular to earth

Solution

The centripetal force is due to gravity of sun and hence, it is radially toward the sun.
Question 28
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Here are a few statements about a plant tissue. On the basis of the statements, choose the option which correctly follows all the statements.

Statement I: It is composed of elongated walls and irregularly thickened cells.
Statement II: It provides extra structural support, particularly in regions of new growth.

A
Parenchyma

B
Sclerenchyma

C
Collenchyma

D
Aerenchyma

Solution

Collenchyma cells have thin primary walls with some areas of secondary thickening. Collenchyma provides extra structural support, particularly in regions of new growth.
Sclerenchyma provides the main structural support to a plant.
Question 29
1.2 / -0

Look at the given options. Study them carefully and choose the option which is caused by the bacteria named Helicobacter.

A: Peptic ulcer
B: Gastric ulcer
C: Duodenal ulcer
D: Oesophageal ulcer

A
D

B
C

C
B

D
A

Solution

Peptic ulcer is caused by the bacteria named Helicobacter and is mostly found in the upper gastrointestinal tract.
Question 30
1.2 / -0

Heterocysts are specialised nitrogen-fixing cells that are found in

A
cyanobacteria

B
fungi

C
gymnosperms

D
lichens

Solution

Heterocysts are specialised nitrogen-fixing cells formed during nitrogen starvation by some filamentous cyanobacteria, such as Nostoc punctiforme, Cylindrospermum stagnale, and Anabaena sphaerica.
Question 31
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Which of the following statements about the Cl atom and Cl^- ion are incorrect?

(i) Cl atom being neutral is more stable.
(ii) Cl^-has a higher effective nuclear charge.
(iii) Cl^- has a smaller radius.
(iv) Cl atom is monovalent.

A
(i), (ii) and (iii)

B
(i) and (ii)

C
(ii) and (iv)

D
(ii), (iii) and (iv)

Solution

Cl (Z = 17); electronic configuration: 2, 8, 7
Cl^- has electronic configuration: 2, 8, 8, which is also the configuration of Argon.
Hence, Chloride ion is more stable due to its stable octet configuration and statement (i) is incorrect.

In Chlorine atom, the 17 electrons are being pulled by 17 protons in the nucleus, whereas the same charge is acting on 18 electrons in the Chloride ion.
Hence, the effective nuclear charge is less in the Chloride ion and statement (ii) is incorrect.

The radius of Chloride ion is larger than that of Chlorine atom, due to lesser effective nuclear charge and due to electronic repulsions and statement (ii) is incorrect.
Cl atom reacts by gaining or sharing one electron in order to acquire an octet configuration and is monovalent.
Therefore, option (1) is the correct answer.
Question 32
1.2 / -0

_____________ is given the credit for the discovery of cell nucleus.

A
David Baltimore

B
Erwin Chargaff

C
Robert Brown

D
Raymond Dart

Solution

Scottish botanist Robert Brown (1773-1858) was responsible for discovering the nucleus of a cell.
Question 33
1.2 / -0

Following are the characteristics shown by a certain group of vertebrates.

1. Exoskeleton made up of scales
2. Endoskeleton is made of bone/cartilage
3. Gills serve as the respiratory organ

Choose the correct answer from the options given below.

A
Reptilia

B
Amphibia

C
Pisces

D
Aves

Solution

The characters given in the question are of Pisces. Amphibians have gills in the larval stage only and possess a slimy skin.
Question 34
1.2 / -0

Which of the following eukaryotic organisms have cell wall made up of cellulose?

A
Fungi

B
Animalia

C
Plantae

D
Monera

Solution

Plantae are multicellular eukaryotic organisms with cell wall made up of cellulose.
Question 35
1.2 / -0

Which among the following is a type of plant tissue in which cells keep on dividing?

A
Meristematic tissue

B
Permanent tissue

C
Sclerenchyma

D
Phloem

Solution

Plant tissues in which cells keep on dividing are called meristematic tissue.
Meristematic tissues are present in those parts of plants which keep on growing. A meristem is the tissue in most plants containing undifferentiated cells (meristematic cells), found in zones of the plant where growth can take place. Meristematic cells give rise to various organs of the plant and keep the plant growing.
Question 36
1.2 / -0

______________ is/are a part of the nucleus and assemble(s) ribosomal subunits in eukaryotic cells.

A
Nuclear membrane

B
Nucleolus

C
Nucleoplasm

D
Nuclear pores

Solution

The nucleolus is a round body located inside the nucleus of a eukaryotic cell. It is not surrounded by a membrane but sits in the nucleus. The nucleolus makes ribosomal subunits from proteins and ribosomal RNA, also known as rRNA.
Question 37
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Out of the given options, which one deals with the practice of controlling the establishment, growth and composition, health and quality of forest?

A
Aquaculture

B
Apiculture

C
Silviculture

D
Floriculture

Solution

Silviculture is the practice of controlling the establishment, growth and composition, health and quality of forest to meet the diverse needs and values of the people.
Question 38
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Pine, Cedar, Spruce and Cypress are considered to be the timber producing plants. Look at the options and choose the family they belong to?

A
Gymnosperms

B
Angiosperms

C
Bryophytes

D
Pteridophytes

Solution

Pine, fir, spruce, cedar and cypress are the famous timber-yielding plants. All of these belong to gymnosperms.
Question 39
1.2 / -0

Cause of cholera is a:

A
Bacteria

B
Virus

C
Fungi

D
Protozoa

Solution

Cholera is caused by bacterium Vibrio cholerae.
Question 40
1.2 / -0

Which of the following plays the role of denitrification in nitrogen cycle?

A
Rhizobium

B
Pseudomonas

C
Nitrosomonas

D
Azotobacter

Solution

Pseudomonas play the role in denitrification, which is the conversion of nitrates into free nitrogen.
Question 41
1.2 / -0

Digestion of starch in the mouth begins with the help of the following enzyme:

A
Ptyalin

B
Trypsin

C
Pepsin

D
Lipase

Solution

Ptyalin is an amylase present in saliva that catalyzes the hydrolysis of starch into maltose and dextrin.
Question 42
1.2 / -0

Which of the following is most suitable for the study of mutations?

A
Diploids

B
Haploids

C
Tetraploids

D
Polyploid

Solution

Majority of induced mutations are recessive and therefore are not expressed in diploid cells (due to the presence of dominant allele). Haploids provide a convenient system for the induction of mutations and selection of mutants with desired traits.
Question 43
1.2 / -0

________ is the name of a young one of a cockroach.

A
Nymph

B
Beetle

C
Moth

D
Larvae

Solution

Nymph is the name given to the young one of a cockroach.
Question 44
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The tissue which is primarily instrumental for the conduction of water and solutes, and also for mechanical support is

A
Collenchyma

B
Phloem

C
Parenchyma

D
Xylem

Solution

Xylem is primarily instrumental for the conduction of water and solutes, and also for mechanical support.
Question 45
1.2 / -0

Which of the following is a micronutrient?

A
Zinc

B
Nitrogen

C
Phosphorous

D
Potassium

Solution

(i) Macronutrients: nitrogen, phosphorus, potassium, calcium, magnesium, sulphur(ii) Micronutrients: iron, manganese, boron, zinc, copper, molybdenum, chlorine
Question 46
1.2 / -0

Which part of the human ear collects the sound wave and then directs them through the ear canal?

A
A

B
C

C
B

D
D

Solution

The outer ear consists of a flap like structure called pinna and it is further connected to the ear canal. The pinna collects the sound wave and then directs them through the ear canal. The sound wave on striking the eardrum vibrates it exactly the same way as a sound emitting object vibrates.
Question 47
1.2 / -0

Refer to the bar graph given below:

Water samples from five different points (P, Q, R, S and T) of a river were collected. The BOD of the collected water samples has been shown in the bar graph given above.

On which of the place(s) (P to T), the highest amount of organic matter is released into the river?
Note: Biochemical oxygen demand (BOD) is the amount of dissolved oxygen needed (i.e. demanded) by aerobic biological organisms to break down organic material present in a given water sample at certain temperature over a specific time period.

A
Both P and T

B
Only P

C
Both R and T

D
Only S

Solution

BOD is a measure of the amount of oxygen required to remove waste organic matter from water in the process of decomposition by aerobic bacteria (those bacteria that live only in an environment containing oxygen). As S shows the highest BOD, it implies that greatest amount of organic waste is released at point S.
Question 48
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Look at the following diagram of SONAR which means Sound Navigation and Ranging. It is an Acoustic device which used to measure the depth, direction and speed under water. The distance of the underwater object is calculated from the time taken by echo to return with speed. What is the name of the method for measuring distance?

A
Echo Ranging

B
Ultrasonic pulse

C
Reflected ultrasonic pulse

D
None of these

Solution

The method of measuring the distance is called the Echo – Ranging.
As the Echo [produced by the reflection by the detector which is converted into electric signals the distance d of the underwater object is calculate from the time taken t taken by echo to return with the speed v is given 2d = vX t.
Question 49
1.2 / -0

Refer to the organisms A and B shown above. Choose the correct statement from the following.

A
Both A and B possess flagella.

B
Both A and B lack cell wall.

C
B is a ciliated protozooan which causes malaria.

D
Both A and B have autotrophic mode of nutrition.

Solution

A is paramecium and B is amoeba. As both are unicellular protozooans, they do not possess cell wall. Both of them have heterotrophic mode of nutrition. Amoeba does not cause malaria.Malaria is caused by Plasmodium.
Question 50
1.2 / -0

A solution of calcium carbonate is 10% by mass. What is the number of calcium ions in 1000 g of the solution?

A
1.2044 × 10²³

B
12.044 × 10²³

C
6.022 × 10²³

D
3.011 × 10²³

Solution

Mass of CaCO₃ in 1000 g of solution = 10% of 1000 g = 100 g
Molar mass of CaCO₃ = 100 g mol^-1
Therefore, 1000 g of solution contains 1 mole of CaCO₃ and 1 mole of Ca⁺² ions.
Hence, number of Ca⁺² ions in 1000 g of the solution = 6.022 × 10²³.