Statistics Test

Result

Statistics Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

The mode of a set of observations is the value which

A
occurs most frequently

B
is central

C
is between maximum and minimum

D
None of these

Solution

By definition, mode is the value which occurs most frequently.
Question 2
1 / -0

The mean of first six multiples of 4 is

A
13.5

B
14.5

C
14

D
16

Solution

Mean = = 14
Question 3
1 / -0

The frequency polygon is drawn :

A
by joining the mid points of the class intervals of corresponding rectangles.

B
end points of classes and frequencies.

C
upper limits of classes less than the cumulative frequencies.

D
upper limit of classes.

Solution

Frequency polygons are a graphical representation for understanding the shapes of distributions. They can be drawn by joining the midpoints of the class internals of corresponding rectangles.
Option 1 is correct.
Question 4
1 / -0

What is the mode?

A
mode is the middle most value in a set of data.

B
mode is the value that appears most often in a set of data.

C
mode is the maximum value in a set of data.

D
mode is the minimum value in a set of data.

Solution

The value which appears most often in a set of data is known as mode.
Option 2 is correct.
Question 5
1 / -0

The mean of first five prime numbers is

A
5.6

B
3.6

C
6.83

D
5.2

Solution

Mean = = = 5.6
Question 6
1 / -0

The mean of x-5y, x-3y,x-y, x+ y, x + 3y and x+ 5y is 12. Then the value of x is

A
18

B
12

C
cannot be determined

D
data is not sufficient

Solution

Mean
=
12 =
x = 12
Question 7
1 / -0

The A.M of d -2, d, d, d+2 is

A
d + 2

B
d

C
d -2

D
3d

Solution

A.M = = = d
Option 2 is correct.
Question 8
1 / -0

Formula for the median of grouped data is

A
L+

B
L+

C
L+

D
L+

Solution

Median formula of grouped data = L +

Where L = Lower class boundary of the median class
F = Cumulative frequency of the groups before the median group
f = Frequency corresponding to the median class
N = Total number of values
C = Group width
Question 9
1 / -0

The mean and median for a unimodel data are 43, 43.4 respectively. Find the mode.

A
43.4

B
42.4

C
44.2

D
49.3

Solution

Mode = 3 Median – 2 Mean
= 3 × 43.4 - 2 × 43
= 130.2 - 86
= 44.2
Question 10
1 / -0

The mean of , ,,and is

A

B

C

D
none of these

Solution

Mean =
=
Question 11
1 / -0

The sum of 15 numbers is 420. The mean of those numbers is

A
25

B
30

C
28

D
none of these

Solution

Mean =
= 28
Question 12
1 / -0

The sum of all the deviations of the observations of a data from its A.M. is

A
0

B
maximum

C
minimum

D
negative number

Solution

= =
Option 1 is correct.
Question 13
1 / -0

In a frequency distribution, C= 3, l = 66.5, t =42, m = 23 n = 102. Find the median of the distribution.

A
65.5

B
68.5

C
66.9

D
67.5
Question 14
1 / -0

The mean of a data is 'P'. If each observation is multiplied by 3 and then 1 is added to each result, the mean of the new observations so obtained is

A
P

B
3p

C
p + 1

D
3p + 1

Solution

Mean = 3p + 1
Question 15
1 / -0

The mean of 20 observations is p. If each observation is multiplied by 3 and then 1 is added to it, the new mean obtained will be

A
3p + 20

B
p + 20

C
3p + 1

D
3(p + 1)

Solution

Mean of 20 observations is p.
So, sum of the observations will be 20p.
When each observation is multiplied by 3, the mean will become (3 × 20p)/20
When 1 is added to each observation, new mean will be (20 + 60p)/20
So, new mean obtained after multiplying each observation by 3 and adding 1 to it = (20 + 60p)/20 = 3p + 1.
Question 16
1 / -0

The median of 10, 20, 15, 30, 35, and 42 is

A
29.5

B
30

C
25

D
31

Solution

Ascending order of the numbers:
10, 15, 20, 30, 35, 42

Median = = 25

Option 3 is correct.
Question 17
1 / -0

The median and A.M of a unimodel data are 30.5 and 26.2 respectively. Find its mode.

A
31.2

B
35.1

C
40.4

D
39.1

Solution

Mode = 3 Median – 2 Mean
= 3 × 30.5 - 2 × 26.2
= 91.5 - 52.4
= 39.1
Question 18
1 / -0

The mean of 11 observations is 17.5. If an observation '15' is deleted, the mean of the remaining observations will be

A
16

B
17.75

C
17.5

D
17.25

Solution

Sum of 11 observations = 17.5 11 = 192.5
After deleting '15', the sum of the remaining 10 observations = 192.5 - 15 = 177.5
Mean of the remaining observations = = 17.75
Question 19
1 / -0

The arithmetic mean of a - 2, a and a + 2 is

A
a + 2

B
a - 2

C
a

D
3a

Solution

A.M = (a - 2 + a + a + 2)/3 = a
Option 3 is correct
Question 20
1 / -0

One of the properties of mode is

A
not easy to calculate

B
not affected by the greatest and the least values

C
algebraic

D
difference of the greatest and the least values

Solution

Mode is a value which appears most often in a set of data and is independent of the greatest and least values.
Option 2 is correct.