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SAT (Stage-2) Mock Test - 21

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SAT (Stage-2) Mock Test - 21
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Weekly Quiz Competition
  • Question 1
    1 / -0

    In the region around a moving charge, there is

    Solution

    In the region around a moving charge, there is electric field as well as magnetic field. A charged particle moving without acceleration produces an electric as well as a magnetic field.

     

  • Question 2
    1 / -0

    An eye specialist prescribes spectacles having a combination of convex lens of focal length 50 cm in contact with a concave lens of focal length 25 cm. The power of this combination of lenses (in dioptre) is

    Solution

    Power for convex lens = 100/50 = 2 D
    Power for concave lens = -100/25 = -4 D
    Total power = -4 D + 2 D = -2 D

     

  • Question 3
    1 / -0

    Coloured band of light obtained by dispersion of white light is called

    Solution

    Coloured band of light obtained by dispersion of white light is called spectrum.

     

  • Question 4
    1 / -0

    The sound of a lion is different from that of a mosquito because

    Solution

    Roaring of a lion produces a sound of low pitch and high intensity/loudness, whereas the buzzing of a mosquito produces a sound of high pitch and low intensity/loudness. This is how the roar of a lion can be differentiated from the buzzing of a mosquito.

     

  • Question 5
    1 / -0

    Two different experiments were conducted in which 56 ml each of Oand H2 gas was collected under same conditions of temperature and pressure.
    In context of the above data, analyse the two statements given below and select the correct option.

    Statement I: The two samples of gas will contain the same number of atoms and molecules.
    Statement II: The two samples of gas will weigh the same.

    Solution

    According to Avogadro's law, equal moles of gases under similar conditions of temperature and pressure occupy equal volumes.
    Conversely, equal volumes of gases under similar conditions of temperature and pressure will constitute equal moles.
    Therefore, equal moles of O2 and H2 will have equal molecules and since both the gases are diatomic, they will constitute equal number of atoms.
    Hence, statement I is correct.
    However, since the gases have different molar masses, equal moles of these gases will have different weights.

     

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