SAT (Stage-2) Mock Test

Result

SAT (Stage-2) Mock Test - 62

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Directions For Questions

Observe the group 17 of the periodic shown below:

Group 17

F

Cl

Br

I

At

...view full instructions

Identify the correct statement about the elements.

I. The reactivity of the elements decreases down the group.
II. The atomic radius decreases down the group.
III. The number of valence electrons remain the same for all the elements.
IV. The valency remains the same for all the elements.

A
I only

B
II only

C
I, III and IV

D
I and III

Solution

The electronegativity of the halogens decreases down the group and hence the reactivity also decreases down the group.
Hence, statement I is correct.
Both valence electrons (here 7) and valency (here 1) are constant for all the elements in a group.

Hence, the statements III and IV are correct.
However, the atomic radius increases down the group.
Hence, the statement II is incorrect.
Question 2
1 / -0

Read the information given in statement I and II and hence answer the question asked in the statement III

I. The first shell can accommodate 2 electrons and the period I has 2 elements.
II. The second shell can accommodate 8 electrons and the period II has 8 elements.
III. The third shell can accommodate 18 electrons and the number of elements in the period III are:

A
8

B
18

C
10

D
3

Solution

Although the third shell (M shell, n = 3) can accommodate 18 electrons (according to the 2n² rule), the third period has only 8 electrons.
This is because the third shell has three sub-shells:

Sub-shell Number of electrons it can accommodate

3s 2

3p 6

3d 10

The 3d sub-shell gets filled after the 4s is filled.
Hence, period III has only 8 elements.
Question 3
1 / -0

Which of the following is a crystalline form of carbon?

A
Lamp black

B
Coke

C
Coal

D
Buckminsterfullerene

Solution

Buckminsterfullerene is a crystalline allotrope of carbon.
Coal, coke and lamp black are amorphous forms of carbon.
Question 4
1 / -0

Select the correct statement.

A
A saturated solution is always dilute but an unsaturated solution may be concentrated or dilute.

B
An unsaturated solution is always dilute but a saturated solution may be concentrated or dilute.

C
A saturated solution is always concentrated but an unsaturated solution may be concentrated or dilute.

D
An unsaturated solution is always concentrated but a saturated solution may be concentrated or dilute.

Solution

A saturated solution is always concentrated and cannot dissolve any more solute at the given temperature, but an unsaturated solution may be concentrated or dilute.
Question 5
1 / -0

An organic compound gives red colour with litmus solution. Which of the following is the probable functional group in the compound?

A
-OH

B
-CHO

C
-COOH

D
-COOR

Solution

-COOH is the functional group in carboxylic acids which give red colour with litmus solution.

Question 6

1 / -0

Match the following.

List I (Alloy)	List II (Composition)
I. Bronze	(A) Lead, Antimony and Tin
II. Brass	(B) Copper, Zinc and Nickel
III. German Silver	(C) Copper and Zinc
IV. Type Metal	(D) Copper and Tin

I - D, II - C, III - B, IV - A

I - B, II - A, III - D, IV - C

I - A, II - D, III - C, IV - B

I - C, II - A, III - D, IV - B

Solution

List I (Alloy)	List II (Composition)
I. Bronze	(D) Copper and Tin
II. Brass	(C) Copper and Zinc
III. German silver	(B) Copper, Zinc and Nickel
IV. Type metal	(A) Lead, Antimony and Tin

Question 7
1 / -0

Metals being good conductors of heat and having high melting points have a utility as materials for making cooking vessels.

Aluminium vessels are anodised as a final step of the manufacturing process. What is the advantage of this technique?

A
Anodising causes the reduction of the metal to raise its melting point.

B
Anodising improves the conducting capacity of the metal.

C
Anodising oxidises the metal to make it inert.

D
Anodising decreases the specific heat of the metal which helps to save fuel.

Solution

During the process of anodising, Al₂O₃ is used as the electrolyte and releases O₂ at the anode, which reacts with the aluminium vessel taken as the anode. This forms a thick sturdy layer of Al₂O₃ on the metal, which protects it from corrossion and also makes it inert and thereby renders it safe to be used for cooking.
Question 8
1 / -0

The induced emf produced when a magnet is inserted into a coil does not depend upon

A
number of turns in the coil

B
resistance of the coil

C
magnetic moment of the magnet

D
speed of approach of the magnet

Solution

The induced emf produced when a magnet is inserted into a coil does not depend upon resistance of the coil.
Question 9
1 / -0

Which of the following statements about electromagnets is not true?

A
They are strong temporary magnets.

B
They are strong permanent magnets.

C
Their strength depends on the strength of current that passes through them.

D
They can be made in different shapes and sizes.

Solution

No, electromagnets are not permanent magnets.
Question 10
1 / -0

A body of mass 2 kg is sliding with a constant velocity of 4 m/s on a frictionless horizontal table. The force required to keep the body moving with the same velocity is

A
8 N

B
zero

C
2 × 4² N

D

Solution

When a body is moving with a constant velocity on a frictionless surface, acceleration is zero. Hence, no force is being applied on it.

This is because f = ma and if a is zero, then F is also zero.
Question 11
1 / -0

A body of mass M collides against a wall with velocity V and rebounds with the same speed. Its change of momentum is

A
zero

B
2 MV

C
- 2 MV

D
- MV

Solution

Mass of body = M
Initial velocity = V
Initial momentum = MV
Final velocity = - V
Final momentum = - MV
Change = Final momentum - Initial momentum
Change = - MV - (MV)
= - 2MV
Question 12
1 / -0

The earth's radius is R and acceleration due to gravity at its surface is g. If a body of mass m is sent to a height h = R/6 from the earth's surface, the potential energy (PE) increases by

A
mgh

B
(7/6) mgh

C
(6/7) mgh

D
(1/7) mgh

Solution
Question 13
1 / -0

Directions For Questions

A particle of mass m is taken along different frictionless paths AB as indicated by the following diagrams. In each case, the particle starts from rest at A and reaches point B. All the paths are in a vertical plane and the external forces act such that the particle moves along the respective paths without restraint.

...view full instructions

Which of the following statements will be true in respect of the given diagrams?

A
The kinetic energy of the particle will remain conserved.

B
The potential energy of the particle will remain conserved.

C
The work done in the motion from A to B by the external forces will be the same for all paths.

D
All of the above

Solution

Work done in moving a body by a certain distance against gravity is directly proportional to the height to which the body is moved and is independent of the path followed. Now, in all cases, 'h' is same. Therefore, the work done by the forces in attaining motion from A to B is the same.
Question 14
1 / -0

Dispersion produced by a prism depends upon

A
size of the prism

B
its refracting index

C
height of the prism

D
one of the angles at the base of the prism

Solution

As the refractive index (μ) of the prism is different for different colors, therefore different colors deviate from different angles on passing through the prism. Hence, they are seen as separate. This is the cause of dispersion.
Question 15
1 / -0

In a room, artificial rain is produced at one end and a strong source of white light is switched on at the other end. To observe the rainbow, an observer must

A
look anywhere in the room

B
look towards the sun

C
look towards the raindrops with his back towards the source of light

D
look in a direction equally inclined to the source of raindrops

Solution

In atmosphere, rainbow is observed when the observer looks towards the water droplets in the air after the rain with his back towards the sun. To observe the rainbow in the mentioned room, the observer must look towards the raindrops with his/her back towards the source of the white light.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Sub-shell	Number of electrons it can accommodate
3s	2
3p	6
3d	10

SAT (Stage-2) Mock Test - 62

Result

SAT (Stage-2) Mock Test - 62

Score

-

Rank

-

SHARING IS CARING

Question 1

I only

II only

I, III and IV

I and III

Solution

Question 2

8

18

10

3

Solution

Question 3

Lamp black

Coke

Coal

Buckminsterfullerene

Solution

Question 4

A saturated solution is always dilute but an unsaturated solution may be concentrated or dilute.

An unsaturated solution is always dilute but a saturated solution may be concentrated or dilute.

A saturated solution is always concentrated but an unsaturated solution may be concentrated or dilute.

An unsaturated solution is always concentrated but a saturated solution may be concentrated or dilute.

Solution

Question 5

-OH

-CHO

-COOH

-COOR

Solution

Question 6

I - D, II - C, III - B, IV - A

I - B, II - A, III - D, IV - C

I - A, II - D, III - C, IV - B

I - C, II - A, III - D, IV - B

Solution

Question 7

Anodising causes the reduction of the metal to raise its melting point.

Anodising improves the conducting capacity of the metal.

Anodising oxidises the metal to make it inert.

Anodising decreases the specific heat of the metal which helps to save fuel.

Solution

Question 8

number of turns in the coil

resistance of the coil

magnetic moment of the magnet

speed of approach of the magnet

Solution

Question 9

They are strong temporary magnets.

They are strong permanent magnets.

Their strength depends on the strength of current that passes through them.

They can be made in different shapes and sizes.

Solution

Question 10

8 N

zero

2 × 42 N

Solution

Question 11

zero

2 MV

- 2 MV

- MV

Solution

Question 12

mgh

(7/6) mgh

(6/7) mgh

(1/7) mgh

Solution

Question 13

2 × 4² N