SAT (Stage-1) Mock Test

Result

SAT (Stage-1) Mock Test - 82

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Directions For Questions

Read the following information carefully and answer the given question.

Raman had his first day at gym today. He exercised hard over there for the first time. After reaching home, he realised his calves were paining. His mother advised him to take rest and not to get worried as he had got cramps. Raman followed his mother's advice.

...view full instructions

Which of the following substances is accumulated in muscles during cramps formation?

A
Ethanol

B
Glucose

C
Lactic acid

D
Pyruvate

Solution

The substance that is accumulated in muscles during cramp formation is lactic acid. This formation in muscles occurs when insufficient oxygen is supplied to the muscles. This results in the release of energy via anaerobic cellular respiration.
Question 2
1 / -0

Which of the following statements is not true about blood plasma?

A
It is a faint yellow fluid.

B
It contains corpuscles.

C
It can clot.

D
It is the fluid part of blood.

Solution

Blood plasma is a light amber liquid component of blood that is freed from blood cells, but holds proteins and other constituents of whole blood in suspension. It makes up about 55% of the body's total blood volume. Plasma itself can clot, because it possesses fibrinogen.
Question 3
1 / -0

In the figure, when an ideal voltmeter is connected across 4000 Ω resistance, it reads 30 volts. If the voltmeter is connected across 3000 Ω resistance, it will read

A
20.2 volts

B
22.5 volts

C
35.4 volts

D
40 volts

Solution

Voltage across 4000 Ω resistance is 30 V.

Hence, current through the 4000 Ω resistance,

As an ideal voltmeter has infinite resistance, and 4000 Ω resistance and 3000 Ω resistance are in series, so the current through both is the same.

Voltage across 3000 Ω resistance is
Question 4
1 / -0

In the given circuit, the potential difference across PQ will be nearest to

A
9.6 V

B
6.6 V

C
4.8 V

D
3.2 V

Solution

Potential difference across PQ i.e., potential difference across the resistance of 20Ω, which is V = i × 20
Question 5
1 / -0

The power dissipated across an 8 Ω resistor in the circuit shown here is 2 W. The power dissipated (in watts) across a 3 Ω resistor is:

A
2.0

B
1.0

C
0.5

D
3.0

Solution

We know P = V² / R
For 8 Ω resistance, we have
V² = P × R = 2 × 8 = 16
V = 4 V
We know that voltage is same in parallel combination of resistors.
So, current through upper limb having equivalent resistance of 4 Ω (resistances 1 Ω and 3 Ω are in series),

Now, current through 3 Ω resistance will also be 1 A.
So, power across 3 Ω resistor = I²R = 3 watt
Question 6
1 / -0

In the given circuit, it is observed that the current I is independent of the value of resistance R₆.

Then, the resistance values must satisfy

A
R₁R₂R₅ = R₃R₄R₆

B

C
R₁R₄ = R₂R₃

D
R₁R₃ = R₂R₄ = R₅R₆

Solution

Current I will be independent of the resistance R₆ if resistance R₆ is ineffective. This will be possible only when resistances R₁, R₂, R₃ and R₄ form a balanced Wheatstone bridge, i.e.

R₁/R₂ = R₃ / R₄or R₁R₄ = R₂R₃
Question 7
1 / -0

A 100 W bulb B₁ and two 60 W bulbs B₂ and B₃ are connected to a 250 V source as shown in the figure. W₁, W₂ and W₃ are the output powers of the bulbs B₁, B₂ and B₃, respectively. Which of the following options is correct?

A
W₁ > W₂ = W₃

B
W₁ > W₂> W₃

C
W₁ < W₂ = W₃

D
W₁ < W₂ < W₃

Solution
Question 8
1 / -0

At what height above the earth's surface does the acceleration due to gravity fall to 1% of its value at the earth's surface?

A
9R

B
10R

C
99R

D
100R

Solution

Let at height 'h', acceleration due to gravity falls to 1% of the value at surface of earth.
Question 9
1 / -0

A ray falls on a prism ABC (AB = BC) and travels as shown in the figure. The minimum refractive index of the prism material should be

A
4/3

B
√2

C
3/2

D
√3

Solution

Angle of incidence at the face AB is 45°.

The ray will not emerge out if the angle of incidence is greater than the critical angle of incidence.

45° ≥ i_c

Or, minimum refractive index of the prism is μ = √2
Question 10
1 / -0

An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eye piece is 36 cm and the final image is formed at infinity. The focal length f_o of the objective and the focal length f_e of the eye piece are

A
f_o = 45 cm and f_e = –9 cm

B
f_o = 7.2 cm and f_e = 5 cm

C
f_o = 50 cm and f_e = 10 cm

D
f_o = 30 cm and f_e = 6 cm

Solution

And length of telescope = f_o + f_e = 36 ………..(ii)
Solving (i) and (ii), we get
f_e = 6 cm and f_o = 30 cm
Question 11
1 / -0

A rod 1.5 m long is placed along the principal axis of a convex mirror of focal length 60 cm. The near end of the rod is 1 m from the pole of the convex mirror. The length of the image of the rod is

A
15.00 cm

B
14.44 cm

C
6.24 cm

D
10.88 cm

Solution

The mirror formula is:

For the end point 1,

u = -100 cm, f = 60 cm

v = 37.5 cm

For the end point 2,

u = -250 cm, f = 60 cm

v' = 48.38 cm

Image length, v' - v = 48.38 - 37.5 = 10.88 cm
Question 12
1 / -0

A convex lens and a concave lens, each having the same focal length of 25 cm, are put in contact to form a combination of lenses. The power in diopters of the combination is

A
25

B
50

C
infinite

D
zero

Solution

Focal length of combination of lenses placed in contact is

For convex lens, f₁ = 25 cm

For concave lens, f₂ = −25 cm

Hence,
Question 13
1 / -0

A lamp hanging 4 metres above the table is lowered by 1 metre. The illumination on the table

A
decreases by 25%

B
increases by 25%

C
decreases by 66.7%

D
increases by 77.7%

Solution

As the intensity of the light is inversely proportional to the square of the distance.

Let the intensity (brightness) at distance r₁= 4 m is I_1,and the intensity at a distance r₂= 3 m is I_2.
Question 14
1 / -0

The magnetic field at a distance r from a long wire carrying current i is 0.4 T. The magnetic field at a distance 2r is

A
0.2 T

B
0.8 T

C
0.1 T

D
1.6 T

Solution

Magnetic field at any point due to the straight wire is inversely proportional to the distance from the wire.

Magnetic field at a distance 2r from the wire is B'.
Question 15
1 / -0

An electron moving with a uniform velocity along the positive x-direction enters a magnetic field directed along the positive y-direction. The force on the electron is directed along

A
positive y-direction

B
negative y-direction

C
positive z-direction

D
negative z-direction

Solution

The force on the positive charge moving in the magnetic field is given by Fleming's left hand rule which states that if we stretch the thumb, the centre finger and the middle finger of our left hand such that they are mutually perpendicular to each other, the centre finger gives the direction of current and middle finger points in the direction of magnetic field, then the thumb points towards the direction of the force or motion of the conductor. Direction of the moving electron is opposite to the direction of the thumb. Here, the electron is moving in the positive direction and the magnetic field is directed in the positive y-direction, so the force on the electron will be directed in negative z-direction.