SAT (Stage-1) Mock Test - 88

They do not bind, support and pack together different organs of the body. This is a function of connective tissues.

Endoplasmic reticulum, golgi apparatus, lysosomes and vesicles are part of the endomembrane system.

Testosterone stimulates the development of secondary sexual characteristics in males at puberty such as moustache and beard, hair on the body, deepening of voice, broadening of the shoulders, enlarged and stronger bones and muscles. Thus, this is the correct answer.

Ornithorhyncus is a connecting link between reptiles and mammals, not aves and mammals. It has mammalian characteristics as it has mammary glands, hair, diaphragm, etc. It has reptilian characteristics as it lays eggs with yolk and shell.

Nerves in depolarised state have positive interior and negative exterior. It happens as more Na⁺ ions enter the cell because of the opening of voltage gated Na⁺ ions channels due to the stimulus.

Sea cucumbers are echinoderms from the class Holothuroidea. They are marine animals, hence have water vascular system.

Chiton, Pila and Cuttlefish all belong to phylum Mollusca.

Eutrophication is the natural ageing of the lake by biological enrichment of water. In the first step, the aquatic body becomes rich in phosphates and nitrates naturally or by human activities. Due to enrichment by phosphates and nitrates, planktonic algae growth takes place excessively. This is referred to as algal bloom. As algae die, bacteria feed on them and increase their number, which leads to depletion of dissolved oxygen.

Nematocysts are stinging cells exclusive to Coelenterates and not Porifera. They act as organs of offence and defence. Hence, it is the correct option.

In plants, capillarity is aided by the small diameter of tracheids and vessel elements.

One nuclear division results into two daughter cells with two nuclei.

Biomagnification of mercury in fishes through a food chain results in Minamata disease in fish-eating population of the region.

Let R₁ is the resistance of the bulb and R₂ is the resistance which is to be connected in series with the bulb.

If R is the equivalent resistance of the circuit, then R = V/I = 12/0.5 = 24 Ω.

But R = R₁ + R₂, therefore 24 = 22 + R_2.

Hence, R₂ = 2 Ω.

Effective resistance in series = 8 Ω

Current in the circuit = I = V/R = 220/8 = 27.5 A

Power consumed by 3 Ω  resistance, P = I²R = (27.5)² × 3 = 2268.75 W

So, answer is 1 as 2268.75 = 1/4 × 9075 W.

F = 200 N
v = 1 m/s
Power = ?
Power = F ^_x v = 200 x 1
= 200 watts