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SAT (Stage-1) Mock Test - 90

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SAT (Stage-1) Mock Test - 90
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  • Question 1
    1 / -0

    A box of marbles and a book cost £6.2. If the book costs £3.5 less than 1 box of marbles, then find the total cost of 4 books and 2 boxes of marbles.

    Solution

    Let the cost of 1 book be £x.
    And cost of 1 box of marbles = £y
    x + y = 6.2 .…(1)
    x = y - 3.5
    or x - y = -3.5 ….(2)
    Adding equations (1) and (2):
    x + x = 6.2 + (-3.5)
    2x = 6.2 - 3.5
    2x = 2.7
    x = 2.7/2
    x = 1.35
    Put x = 1.35 in equation (1):
    1.35 + y = 6.2
    y = 6.2 - 1.35
    y = 4.85
    Cost of 4 books and 2 boxes = 4x + 2y
    = 4 × 1.35 + 2 × 4.85
    = 5.4 + 9.7 = £15.1 

     

  • Question 2
    1 / -0

    Which digit is at the 99th decimal place in the decimal value of 5/7?

    Solution

    5/7 = 0.71428571428571...
    Period is 714285 and periodicity is 6.
    99 = 6(16) + 3. So, at the 99th decimal place, the digit is 4.

     

  • Question 3
    1 / -0

    Solution

     

  • Question 4
    1 / -0

    If a2/bc + b2/ca + c2/ab = 3 and a ≠ b, then a + b + c = ?

    Solution

    Hence, a3 + b3 + c3 = 3abc
    a3 + b3 + c3 - 3abc = 0
    Hence, (a + b + c)(a2 + b2 + c2 - ab - bc - ca) = 0
    ∴ a + b + c = 0

     

  • Question 5
    1 / -0

    What number should be subtracted from 2x2 - 7x - 12 so that the resulting polynomial has a factor 2x + 3?

    Solution

     

  • Question 6
    1 / -0

    A bag contains 6 white and 9 black balls. If three balls are drawn at random, then find the probability that all of them are black.

    Solution

    Total number of outcomes = 15C3
    Number of favourable outcomes = 9C3

     

  • Question 7
    1 / -0

    If a and b are the roots of x2 + px - q = 0, and g and d are the roots of x2 + px + r = 0, then the value of (a - g)(a - d) is

    Solution

    a + b = g + d = -p
    ab = -q, and
    gd = r
    Value of (a - g)(a - d) = a2 - ga + gd - ad = a- (g + d)a + gd = a2 - (a + b)a + gd = gd - ab = r + q

     

  • Question 8
    1 / -0

    In a parallelogram ABCD, ∠A : ∠B = 1 : 2. Find the value of ∠C.

    Solution

    ∠A : ∠B = 1 : 2



    Let ∠A = x and ∠B = 2x
    Also, ∠A + ∠B = 180° [Adjacent angles of a parallelogram are supplementary.]
    ⇒ x + 2x = 180°
    ⇒ 3x = 180°
    ⇒ x = 180°/3 = 60°
    And ∠A = ∠C [∵Opposite angles of a parallelogram are equal.]
    ⇒ ∠C = 60°
    Alternate method: ∠A = ∠C and ∠B = ∠D [∵ Opposite angles of a parallelogram are equal.]
    And ∠A : ∠B = 1 : 2
    ⇒ ∠A = x and ∠B = 2x
    Then, ∠A + ∠B + ∠C + ∠D = 360° [Angle sum property of a quadrilateral]
    ⇒ x + 2x + x + 2x = 360°
    ⇒ 6x = 360° ⇒ x = 60°
    ⇒ ∠A = ∠C = 60°

     

  • Question 9
    1 / -0

    Mean of seven numbers is 52 and six of those numbers are 17, 19, 15, 8, 5 and 12. Find the missing number.

    Solution

    Let the 7th number be x.

    52 × 7 = 17 + 19 + 15 + 8 + 5 + 12 + x

    364 = 76 + x

    Or, x = 364 - 76

    x = 288

     

  • Question 10
    1 / -0

    A tap drips at an average rate of 2 drops every 3 seconds. It takes 2080 such drops of water collected to completely fill a vessel of hemispherical shape (radius 8.3 cm). How many times can the vessel be filled in this manner over 13 hours?

    Solution

    Average rate of dripping = 2/3 drops/sec
    Total number of drops in the completely filled vessel = 2080
    Then, time taken by the tap to drip 2080 drops = 3/2 × 2080 = 3120 sec
     Number of times vessel will be filled over 13 hours = 13 ×3600 / 3120 = 15

     

  • Question 11
    1 / -0

    In the figure below, the area of triangular region PQR is 36 sq. units. What is the area of triangular region SQR?

     

    Solution

    In triangle PQSPQ2 + PS2 = QS2
    42 + PS2 = 52
    PS2 = 9 units
    PS = 3 units
    Area of triangle PQS = 1/2 × 4 × 3 = 6 sq. units
    Now, area of triangle SQR = ar(PQR) - ar(PQS)
    = 36 - 6 = 30 sq. units

     

  • Question 12
    1 / -0

    Solution

     

  • Question 13
    1 / -0

    The angle of elevation of a 15 m high tower is 60° from the bottom of an electric pole. The angle of elevation of the tower from the top of the electric pole is 30°. Find out the height of the electric pole.

    Solution

    Consider the diagram:

    Let AB and CD be the heights of the tower and the electric pole, respectively.
    Then, ∠ACB = 60°, ∠EDB = 30° and AB = 15 m
    If CD = h,
    then BE = (AB – AE) = (AB – CD) = (15 – h)

     

  • Question 14
    1 / -0

    Standing at a radar base, a person observes an unidentified object at a height of 3000 m flying towards the radar station at an angle of elevation of 30°. After a minute, the person again observes that the flying object is at an angle of elevation of 60°, having the same height. What is the speed of the object?

    Solution

    Distance travelled in 1 minute = ST = QR = PR - PQ

     

  • Question 15
    1 / -0

    If sin2θ + 3 cosθ - 2 = 0, then cos3θ + sec3θ is equal to

    Solution

    Given sin2θ + 3 cosθ - 2 = 0
    ⇒ cos2θ - 3 cosθ + 1 = 0
    ⇒ cos2θ + 1 = 3 cosθ
    dividing by cosΘ on both sides. so,

    from (i)
    ⇒ cos3θ + sec3θ + 3(3) = 27
    ⇒ cos3θ + sec3θ = 18

     

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