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Electricity Test - 9

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Electricity Test - 9
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The process of acquiring temporary electrification under the influence of a charged body is called
    Solution
    The process of acquiring temporary electrification under the influence of a charged body is called induction.In Induction , the positive and the negative charge of the body gets separated under the influence of the another charged body.
  • Question 2
    1 / -0
    A current of 4.8 A is flowing through a conductor. The number of electrons passing per second through the conductor is
    Solution
    I = ne/t
    4.8 = n × 1.6 × 10-19/1
    n = 3 × 1019
  • Question 3
    1 / -0
    Ohm's law gives a relation between
    Solution
    Ohm's law gives a relation between the current flowing through a circuit and the potential difference across it.
  • Question 4
    1 / -0
    When the diameter of a wire is doubled, its resistance becomes
    Solution
    , where The resistance of wire is inversly propotional to the square of the diameter.So,resistance will be one-fourth
  • Question 5
    1 / -0
    The resistance of a wire of uniform diameter D and length L is R. The resistance of another wire of the same material, but diameter 2D and length 4L will be
    Solution


    R =

    The new resistance will be R'.

    R' =
  • Question 6
    1 / -0
    Two resistances are joined in parallel, whose resultant is (6/5). One of the resistance wires is broken and the effective resistance is 2. The resistance of the broken wire is
    Solution
    Req = 6/5 ohmR1 = 2 ohmR2 = ? R2 = 3 ohm
  • Question 7
    1 / -0
    The effective resistance of the network between points A and B is

    Solution
    1/R = 1/6 + 1/6 + 1/6 = 3/6 = 1/2
    R = 2 ohm
  • Question 8
    1 / -0
    A battery and resistances are connected in a circuit as follows. The current flowing through the ammeter A is

    Solution
    As the bridge is a balanced bridge so the current in the circuit will be zero.
  • Question 9
    1 / -0
    Three wires of resistances 18 ohms, 15 ohms and 10 ohms are connected in parallel. The current in the 18 ohm wire is 0.75 A. What is the current in the 15 ohm wire?
    Solution
    V = IR

    Voltage across 18 ohm resistance:

    V = 18 x 0.75 = 13.5 V

    As the resistances are in parallel, the voltage across each resistance will be the same.

    Current through the 15 ohm resistance is:

  • Question 10
    1 / -0
    A geyser of 2.5 kW is connected to a battery of 220 volts. An iron of 1.5 kW is also connected to the battery. To prevent any failure of fuse, the fuse wire must have a current rating of
    Solution
    We know: P = VI
    For geyser, Current I1 = 2500/220
    For iron, I2 = 1500/220
    I2 = 6.8 A
    Total current = I1 + I2 = 18.16 A
    So, the fuse wire must be of a rating more than 18.16 A.
    From all the options given, 20 A is the only rating more than 18.16 A. Hence, it is the answer.
  • Question 11
    1 / -0
    The north pole of a magnet is brought near a stationary positively charged conductor. The north pole exerts a force, which will
    Solution
    The north pole of a magnet is brought near a stationary positively charged conductor. The north pole exerts a force, which will not affect the conductor at all
  • Question 12
    1 / -0
    A cylindrical bar magnet is kept along the axis of a circular coil. If the magnet is rotated about its axis, then
    Solution
    As the magnetic flux linked with the coil is not changing, so no emf will be induced. An induced emf is zero. So, the current in the coil will be zero.
  • Question 13
    1 / -0
    A transformer is used
    Solution
    A transformer is used to obtain suitable ac voltage
  • Question 14
    1 / -0
    A milliammeter of range 10 mA gives full-scale deflection for a current of 100 mA when a shunt of 0.1 Ω is connected in parallel to it. The coil of the milliammeter has a resistance of
    Solution
    Let's consider the given milliammeter.



    Given data:
    Im = 10 mA
    I = 100 mA
    Rsh = 0.1 Ω
    From the above figure, current through shunt resistor Rsh,
    Ish = I - Im = (100 - 10) mA = 90 mA

    From the above figure,

  • Question 15
    1 / -0
    The direction of magnetic field at a point due to an infinitely long wire carrying current is
    Solution
    The direction of magnetic field at a point due to an infinitely long wire carrying current is perpendicular to the plane containing the conductor and the point
  • Question 16
    1 / -0
    Charge Q is divided into two parts, which are then kept some distance apart. The force between them will be the highest, if the two parts are
    Solution
    Charge Q is divided into two parts, which are then kept some distance apart. The force between them will be the highest, if the two parts are Q/2 each.The charge will be equally divided.
  • Question 17
    1 / -0
    Power is transmitted from a power house on high voltage AC because
    Solution
    Power is transmitted from a power house on high voltage AC because it is more economical due to less power wastage
  • Question 18
    1 / -0
    DC can be converted into AC with the help of
    Solution
    DC can be converted into AC with the help of inverter
  • Question 19
    1 / -0
    Molten sodium chloride conducts electricity due to the presence of
    Solution
    Molten sodium chloride conducts electricity due to the presence of free ions.
  • Question 20
    1 / -0
    A small piece of unmagnetised substance gets repelled when it is brought near a powerful magnet. The substance can be
    Solution
    A small piece of unmagnetised substance gets repelled when it is brought near a powerful magnet. The substance can be diamagnetic
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