Measurement Test

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Measurement Test - 1

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Weekly Quiz Competition

Question 1

1 / -0

Match the following.

Derived unit	Unit name
(i) Power	(a) Volt
(ii) Energy	(b) Pascal
(iii) Work	(c) Joule
(iv) Pressure	(d) Watt
(v) Electromotive	(e) Joule

(i) - (a), (ii) - (b), (iii) - (c), (iv) - (d), (v) - (e)

(i) - (d), (ii) - (e), (iii) - (c), (iv) - (b), (v) - (a)

(i) - (d), (ii) - (c), (iii) - (e), (iv) - (b), (v) - (a)

Both (2) and (3)

Solution

Power - Watt
Energy - Joule
Work - Joule
Pressure - Pascal
Electromotive - Volt

Question 2
1 / -0

Which of the following has the highest value?

A
Deca

B
Hecto

C
Giga

D
Mega

Solution

Giga = 10⁹
Question 3
1 / -0

Consider the following numbers.
a - 6.120
b - 74.32
c - 7532
d - 0075

Find the number of significant figures in each given number.

A
a - 3, b - 2, c - 4, d - 4

B
a - 4, b - 4, c - 4, d - 4

C
a - 3, b - 4, c - 4, d - 4

D
a - 3, b - 4, c - 4, d - 2

Solution

Correct Answer: a - 4, b - 4, c - 4, d - 4
Question 4
1 / -0

In which of the following pairs are unit symbol and quantity not correctly matched?

A
Momentum - kgms^-2

B
Velocity - ms^-1

C
Density - kgm^-3

D
Acceleration - ms^-2

Solution

Momentum has unit kgms^-1 and is defined as kilogram metre per second .
Question 5
1 / -0

Which of the following formulae is correct for the calculation of the least count of vernier scale?

A
Pitch of main scale x Number of division on vernier scale

B

C

D

Solution

Least count of vernier arrangement =, where pitch of main scale is the magnitude of the smallest scale division.
Question 6
1 / -0

Which of the following is true regarding physical quantity?

A
It is a quantity that can be expressed in terms of other quantities.

B
It is a quantity to which a unit can be ascribed and that can be measured.

C
It is a quantity that cannot be expressed in terms of other quantities.

D
None of these
Question 7
1 / -0

Which of the following has the same units as that of time in seconds?

A

B

C

D
Both (1) and (2)

Solution

Frequency =
Time period or time, T =
Similarly, T = , time period of a pendulum, which is also expressed in seconds.
Question 8
1 / -0

Which of the following is not correct?

A
Oscillation is the one complete to and fro motion of a simple pendulum.

B
Frequency is the number of oscillations in one second.

C
Periodic time is the time for one oscillation.

D
Amplitude is the minimum displacement from mean position

Solution

Options (1), (2) and (3) are correct while option (4) is not correct as amplitude is the maximum displacement from mean position.
Question 9
1 / -0

Which of the following is not correct?

A
Mass is a scalar quantity.

B
Weight is a vector quantity.

C
Mass is the quantity of matter contained in a body that supports it.

D
Weight remains the same everywhere for a body.

Solution

Option (4) is not correct as the weight of a body changes on different positions on earth, e.g. weight of body is not the same on surface, poles and equator of earth.
Question 10
1 / -0

In which of the following cases is percentage error more?

A
Length of 10 cm is measured as 9.8 cm.

B
Length of 20 cm is measured as 19.8 cm.

C
Length of 50 cm is measured as 49.8 cm.

D
All have the same frequency error.

Solution

(1) Error = 10 cm - 9.8 cm = 0.2 cm
Percentage error = = 2%
(2) Error = 20 cm - 19.8 cm = 0.2 cm
Percentage error = = 1%
(3) Error = 50 cm - 49.8 cm = 0.2 cm
Percentage error =
Therefore, percentage error in option (1) is more.
Question 11
1 / -0

How many femtoseconds are there in 100 picoseconds?

A
10^-5

B
10⁵

C
10³

D
10^-3

Solution

1 picosecond = 10^-12 sec
100 picoseconds = 10^-10 sec
Also, 1 femtosecond = 10^-15 sec
Therefore, number of femtoseconds = or 10⁵ in 100 picoseconds
Therefore, 10⁵ femtoseconds are present in 100 picoseconds.
Question 12
1 / -0

How many milligrams are there in 100 tonnes (t)?

A
10¹¹

B
11¹⁰

C
10^-11

D
10⁷

Solution

1 tonne = 10³ kg........... (1)
1 milligram = 10^-6 kg........(2)
or 100 tonnes = 100 (10³) kg
100 tonnes = 10⁵ kg
From (2), 1 kg = 10⁶ milligram
Therefore, 100 tonnes have 10⁵ x 10⁶ milligrams or 10¹¹ milligrams.
Question 13
1 / -0

We have three pendulums; A, B and C having frequency 50 Hz, 30 Hz and 20 Hz respectively. Which pendulum has the highest length?

A
A

B
B

C
C

D
Cannot be determined

Solution

Since T =
Frequency =
This implies that frequency .Therefore, the pendulum having the lowest frequency C has the highest length.
Question 14
1 / -0

If four pendulums P, Q, R and S are having length 10 cm, 20 cm, 30 cm and 40 cm respectively, which pendulum has the lowest frequency?

A
P

B
Q

C
R

D
S

Solution

Since frequency (F) = where T =
F =
Therefore, F
Thus, the frequency of pendulum or pendulum having the highest length has the lowest frequency or pendulum S has the lowest frequency.
Question 15
1 / -0

If four pendulums; A, B, C andv D have frequency 20 Hz, 30 Hz, 40 Hz and 50 Hz respectively, which pendulum has the lowest frequency?

A
D

B
C

C
B

D
A

Solution

Since T =
F =
Therefore, pendulum A has the lowest frequency.
Question 16
1 / -0

How many millilitres are there in 100 m³ of water?

A
10⁸ ml

B
10^-8 ml

C
10⁴ ml

D
10⁶ ml

Solution

1 m³ = 1000000 cm³
100 m³ = 10⁸ cm³
1 litre = 1000 cm³ or 1000 ml
Therefore, 100 m³ has 10⁸ ml of water.
Question 17
1 / -0

How many milli seconds are needed to make a mega second?

A
10⁹

B
10⁸

C
10⁷

D
10¹⁰

Solution

1 milli second = 10^-3 seconds
1 mega second = 10⁶ seconds
Therefore, number of milliseconds to make a mega second is or 10⁹ milli seconds are needed to make a mega second.
Question 18
1 / -0

Which of the following is true in case of a team balance?

A
Beam balance works on the principle of moments.

B
Levelling screws are used to adjust the final horizontal position of the beam.

C
Arrestment knob raises and lowers the beam.

D
Pans hold the body and the standard mass.

Solution

All options are true, except option (2). Adjusting screws are used to adjust the final horizontal position of the beam, while levelling screws level the base.
Question 19
1 / -0

Find the length of the pendulum having time period 4 seconds and frequency 1 Hz.

A
3.96 cm

B
3.37 cm

C
396.8 cm

D
34.56 cm

Solution

T² = 4
or = l
l = = 396.8 cm
Therefore, l = 396.8 cm