Force Test

Result

Force Test - 3

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Question 1
1 / -0

A particle is in straight line motion with uniform velocity. A force is not required

A
to increase the speed

B
to decrease the speed

C
to keep the same speed

D
to change the direction

Solution

Force acting on an object moving in a straight line will change its speed. Hence, to maintain the same speed, no force should be applied.
Question 2
1 / -0

A boy sitting on the top most berth in the compartment of a train, which is just going to stop on a railway station, drops an apple aiming at the open hand of his brother sitting vertically below him at a distance of about 2m. The apple will fall

A
in the hand of his brother

B
slightly away from the hands of his brother in the direction of motion of the train

C
slightly away from the hands of his brother in the direction opposite to the direction of motion of the train

D
none of the above

Solution

As the train is about to stop (de-accelerating) then, the tendency for a freely falling body inside the train will be to move slightly in the direction of motion of the train. This is because of inertia of motion. Hence, the apple will fall slightly away from the hands of his brother in a direction of motion of the train.
Question 3
1 / -0

Gravel is dropped into a conveyer belt at a rate of 0.5 kg/s. The extra force required in Newton to keep the belt moving at 2 m/s is

A
1

B
2

C
4

D
0.5

Solution

Rate at which the gravel is dropped = 0.5 kg/s
Velocity with which the belt is moving = 2 m/ s
Force required = 0.5 × 2 = 1 N
Question 4
1 / -0

Two balls, each of mass 0.25 kg, are moving with 3m/s and 1m/s towards each other in a straight line collide. The balls stick together after the collision. The magnitude of the final velocity of the combined mass is

A
4 m/s

B
2 m/s

C
1 m/s

D
(1/2) m/s

Solution

Let `v` be the final velocity of system. Now, according to the "law of conservation of momentum",
Initial momentum = Final momentum

(0.25 ×3) + (0.25 ×-1) = (0.25 + 0.25) v
0.75 - 0.25 = 0.5 v

0.5 = 0.5 v
1 = v

⇒ v = 1 m/ s
Question 5
1 / -0

A body of mass m moving with a constant velocity v hits another body of the same mass moving with same velocity v but in the opposite direction and sticks to it. The velocity of the compound body, after collision, is

A
v

B
2v

C
zero

D
v/2

Solution

mv) + (-mv) = (2m) (v_f)
0 = (2m) V_f
⇒ V_f = 0