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Force Test - 5

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Force Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    When a constant force is applied to a body, it moves with uniform

    Solution

    When a constant force is applied, the body moves with a constant acceleration.
    F = ma

    If F is constant, a is constant.

     

  • Question 2
    1 / -0

    When a force of constant magnitude always acts perpendicular to the motion of a particle, then

    Solution

    When a force of constant magnitude acts perpendicular to the motion of a particle, it only changes the direction of the particle and hence the speed remains constant, but there is change in the velocity.

    Hence, K.E. (Kinetic Energy) remains constant as it is independent of the direction.

     

  • Question 3
    1 / -0

    A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/s comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

    Solution

    Initial velocity = 4 m/s
    Mass = 2 kg
    Time after it rests = 2 s

    Final velocity = 0
    v = u + at
    0 = 4 + a (2) ⇒ a = – 2 m/s2

    Hence, an opposing force of F = 2(–2) = – 4 N is acting on the body.
    Therefore, to maintain its speed at 4 m/s, a force of 4 N is required.

     

  • Question 4
    1 / -0

    A surface is hit elastically and normally by n balls per unit time. All the balls have the same mass m and moving with the same velocity u. The force on the surface is

    Solution

    Using the relation for one ball,
    F. t = Δmv
    F = m(v1 - v2) (as t = 1 s)
    Here, v1 = U

    V2 = - U (as balls hit elastically, therefore, there is no loss of energy)
    F = m (20)
    For n balls, F = 2mnu

     

  • Question 5
    1 / -0

    A rocket is ejecting 1 kg of gases per sec at a velocity of 60 km/s. The accelerating force on the rocket is

    Solution

    According to Newton`s third law of motion, every action has an equal and opposite reaction.
    Expelled force due to gas = 60 × 103 m/s × 1 kg/s
    = 6 × 104 N

    The same force acts on the rocket = 6 × 104 N

     

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