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Light Test - 5

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Light Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    A medium through which light passes fully is called

    Solution

    A medium through which light passes fully is called transparent.

     

  • Question 2
    1 / -0

    Which of the following options has the longest wavelength?

    Solution

    Infrared radiation has the longest wavelength.

     

  • Question 3
    1 / -0

    The formation of umbra and penumbra regions of the shadow of an opaque sphere by a small light source is due to

    Solution

    When light from a source falls on an opaque sphere, the shadow is formed by the sphere opposite to the source side. This shadow can divided into two regions called umbra and penumbra. The region where all of the light from the source is blocked by the object is called umbra and the region where the shadow is only partial is called penumbra. This phenomenon occurs due to rectilinear propagation of light.

     

  • Question 4
    1 / -0

    An illuminating object is placed between two plane mirrors mutually perpendicular to each other. The number of images formed is

    Solution

    An illuminating object is placed between two plane mirrors mutually perpendicular to each other. The number of images formed is 3.
    n = 360/90 - 1 = 4 - 1 = 3

     

  • Question 5
    1 / -0

    When an object is placed beyond the centre of curvature for the concave mirror, the characteristics of the image will be

    Solution

    When an object is placed beyond the centre of curvature for the concave mirror, the characteristics of the image will be real and inverted.

     

  • Question 6
    1 / -0

    A dentist uses a small mirror that gives a magnification of 4 when it is held 0.60 cm from a tooth. The radius of curvature of the mirror is

    Solution

    m = -v/u
    4 = -v/(-0.6)
    v = 2.4 cm
    1/f = 1/v + 1/u
    1/f = 1/2.4 - 1/0.6
    1/f = -3/2.4
    f = - 0.8 cm
    R = - 1.6 cm
    Mirror is concave.

     

  • Question 7
    1 / -0

    A coin dropped in water of refractive index 4/3 up to a real depth of 28 cm will apparently seem to be at a depth of

    Solution

    μ = Real depth/Apparent depth
    4/3 = 28/Apparent depth
    Apparent Depth = 21 cm

     

  • Question 8
    1 / -0

    Where should an object be placed so that a real and inverted image of the same size is obtained using a convex lens?

    Solution

    At twice the focal length a real and inverted image of the same size is obtained using a convex lens.

     

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