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  • Question 1
    1 / -0

    The displacement s of a point moving in a straight line is given by s = 8t2 + 5t - 5, where s being in cm and t in s. The initial velocity of the particle is

    Solution

    Given, s = 8t2 + 5t - 5
    Velocity \'v\' = ds/dt = 16t + 5
    At t = 0 sec, initial velocity = 16(0) +5 = 5 cm/s

     

  • Question 2
    1 / -0

    The acceleration due to gravity on the Moon is one-sixth that on the Earth. A high-jumper can jump 2 m on Earth. What distance can he jump on the Moon?

    Solution

    The initial potential energies on both the Earth and the Moon will be same. So, by equating the energies, we get,
    mgh = mg'h'
    g x 2 = g/6 x h'
    h' = 12 m

     

  • Question 3
    1 / -0

    Tripling the speed of a motor car multiplies the distance needed for stopping it by

    Solution

    v2 - u2 = 2as
    As v =0; -u2 = 2as
    s = u2/2a (since a is negative so negative sign cancels each other)
    s is proportional to u2
    s = ku2
    Hence, tripling the speed makes the distance 9 times for stopping.

     

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