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Mathematics (Paper-1) Mock Test - 2

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Mathematics (Paper-1) Mock Test - 2
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Weekly Quiz Competition
  • Question 1
    3 / -0

    While playing a number game, Jimmy got 6 numbers in a row. If the six numbers were 8, 6, 9, 5, 2 and 7, then which of the following can be the largest 6- digit number that can be formed using these digits?

    Solution

    The largest 6-digit number using the given digits will be 9,87,652.

     

  • Question 2
    3 / -0

    Arrange the numbers 63917, 63197, 63971, 63911 and 69371 in ascending order and choose the correct option.

    Solution

    Compare the digits according to place values.
    Ascending order means arranging numbers from the smallest to the largest.
    63197 < 63911 < 63917 < 63971 < 69371

     

  • Question 3
    3 / -0

    21/18 of a leap year = _____ weeks

    Solution

    A leap year has 366 days.
    21×18 × 366 = 427 days
    Number of weeks = 427/7 = 61

     

  • Question 4
    3 / -0

    Evaluate the given expression:

    5 + 8 - 5 + 7 × 4 ÷ 2 - 8

    Solution

    Given expression: 5 + 8 - 5 + 7 × 4 ÷ 2 - 8
    = 5 + 8 - 5 + 7 × 2 - 8
    = 5 + 8 - 5 + 14 - 8
    = 14

     

  • Question 5
    3 / -0

    Convert MMIV to a number and choose the correct option.

    Solution

    M represents 1000.
    IV represents 4.
    So, MMIV = 1000 + 1000 + 4 = 2004

     

  • Question 6
    3 / -0

    Kavya scored 88 out of 200 in a test. What is her percentage in the test?

    Solution

    Percentage = 88/200 × 100 = 44%

     

  • Question 7
    3 / -0

    Which of the following numbers is divisible by 7?

    Solution

    1841 = 7 × 263 + 0 (1841 is divisible by 7.)
    1851 = 7 × 263 + 10 (1851 is not divisible by 7.)
    1849 = 7 × 263 + 8 (1849 is not divisible by 7.)
    1843 = 7 × 263 + 2 (1843 is not divisible by 7.)

     

  • Question 8
    3 / -0

    What is the sum of 85.02, 88.02, 35.21 and 82.03?

    Solution

    Here, we have to add the numbers.

    85.02
    + 88.02
    + 35.21
    + 82.03
    _______
    290.28
    _______

     

  • Question 9
    3 / -0

    What is the measure of the angle supplementary to the angle measuring 105°?

    Solution

    Let the given angle be ∠a.
    We know that
    ∠a + 105° = 180° (Supplementary angles)
    ∠a = 75°

     

  • Question 10
    3 / -0

    Veena bought a fan, which cost (5/6)th of her total salary. She spent (3/4)th as much on buying a frying pan as she spent on buying the fan. What fraction of salary did she spend on buying the frying pan?

    Solution

    Fraction of the amount spent on buying the fan = 5/6
    Fraction of the amount spent on buying the frying pan = 5/6 × 3/4 = 5/8

     

  • Question 11
    3 / -0

    The smallest 4-digit number that can be formed using all the digits 4, 8, 9 and 0, without repeating the digits, is

    Solution

    The smallest 4-digit number that can be formed using all the digits 4, 8, 9 and 0, without repeating the digits, is 4089.
    Note: 0489 is not a 4-digit number.

     

  • Question 12
    3 / -0

    Which of the following numbers are arranged in descending order?

    Solution

    (1) 2/3, 4/5, 0.9 = 0.666... < 0.8 < 0.9 (Ascending Order)

    (2) 0.95, 6/7, 3/4 = 0.95 > 0.857 > 0.75 (Descending Order)

    (3) 0.05, 1/4, 0.5 = 0.05 < 0.25 < 0.5 (Ascending Order)

    (4) 0.3, 0.35, 0.4 = 0.3 < 0.35 < 0.4 (Ascending Order)

     

  • Question 13
    3 / -0

    A number that must be subtracted from 8,14,453 to make it equal to the sum of 1,23,140 and 2,41,310 will be

    Solution

    The first step to solve this question would be to add 1,23,140 and 2,41,310.
    i.e. 1,23,140 + 2,41,310 = 3,64,450
    Then, we will subtract 3,64,450 from 8,14,453.
    i.e. 8,14,453 - 3,64,450 = 4,50,003

     

  • Question 14
    3 / -0

    The average of marks of Yash in seven tests is 40. If the sum of the marks in the first six tests is 242, then how many marks does Yash obtain in his seventh test?

    Solution

    The average of marks of Yash in seven tests is 40.
    Then, sum of marks in all the seven tests = 7 × 40 = 280
    But the sum of the marks in the first six tests is 242.
    Then, the marks obtained by Yash in the seventh test will be: 280 - 242 = 38 marks
    Hence, he obtained 38 marks in the seventh test.

     

  • Question 15
    3 / -0

    Ankit starts for school at 6:45 in the morning. He reaches the school in 55 minutes. At what time does he reach the school?

    Solution

    Ankit starts for school at 6:45 in the morning.
    He reaches the school in 55 minutes.
    So, time by which he reaches the school = 6:45 + 15 min + 40 min = 7:40 a.m.

     

  • Question 16
    3 / -0

    In a college, a botanical garden is built which is 65 m long and 34 m wide. The teacher asks the students to collect the amount for fencing the garden with steel wires. What amount of money will be required if the cost of the wire of length 1 cm is 50 paise?

    Solution

    Length of the garden = 65 m
    Width of the garden = 34 m
    For fencing, we need perimeter.
    Perimeter = 2(65 + 34) = 198 m
    198 m = 19,800 cm
    19,800 × 0.50 = Rs. 9,900

     

  • Question 17
    3 / -0

    Round off 26,174 to the nearest ten thousands.

    Solution

    By rounding 26,174 we see the thousand place of the number if it is more than equal to 5 we round it up and if it is less 5 we round it down.
    26,174 rounded off to the nearest ten thousands = 30,000

     

  • Question 18
    3 / -0

    1/9 = ___%

    Solution

    Given fraction: 1/9
    So, 1/9 in percentage = 100/9 = 11.11%

     

  • Question 19
    3 / -0

    Edward purchased a toy car at a cost of Rs. 5600. He sold it at a loss of Rs. 580. At what cost did he sell the toy car?

    Solution

    We know
    Loss = CP - SP
    580 = 5600 - SP
    SP = 5600 - 580 = Rs. 5020

     

  • Question 20
    3 / -0

    A car travels a distance of 300 km in 6 hours. Find the speed of the car.

    Solution

    Distance = 300 km, Time = 6 hours
    We know
    S = D/T = 300/6 = 50 km/hr

     

  • Question 21
    3 / -0

    A building has 72 floors. Each floor has 108 windows. Each window is to be decorated with 38 small candles. How many candles would be needed to decorate all the windows?

    Solution

    Number of candles needed = 72 × 108 × 38 = 2,95,488

     

  • Question 22
    3 / -0

    The smallest number that divides 75 and 85 leaving 5 as a remainder in each case is

    Solution

    10 is the smallest number among all the options because when we divide 75 and 85 by 10, it leaves the remainder 5.
    We need to find the HCF of (75 - 5) and (85 - 5), which is the HCF of 70 and 80, i.e. 10.

     

  • Question 23
    3 / -0

    What is the sum of 50.25, 50.025, 50.002 and 50.225?

    Solution

    The given numbers are:
    50.25, 50.025, 50.002 and 50.225
    So, when we add these numbers, we get
    50.25 + 50.025 + 50.002 + 50.225 = 200.502
    Hence, the answer is 200.502.

     

  • Question 24
    3 / -0

    Which of the following pairs represents complementary angles?

    Solution

    When two angles add up to 90°, we say they are complementary angles.
    27° + 63° = 90°

     

  • Question 25
    3 / -0

    The smallest 4-digit number that can be formed using the digits 4, 9, 2 and 8 without repetition is

    Solution

    The smallest 4-digit number that can be formed using the digits 4, 9, 2 and 8 without repetition is 2489.

     

  • Question 26
    3 / -0

    Katie was playing in rain by making paper boats and she noticed that her boat was flowing with a speed of 0.9 km/hr. Find out its speed in m/sec.

    Solution

    In order to convert the speed in km/h to m/sec, we need to divide the given speed by (5/18).
    So, 0.9 km/hr = 0.9 × 5/18 = 0.25 m/sec

     

  • Question 27
    3 / -0

    Find the sum of the number 21,574 and the number obtained by interchanging the places of 2 and 4.

    Solution

    The number obtained after interchanging the places of 2 and 4 is 41,572.
    Now, 21,574 + 41,572 = 63,146

     

  • Question 28
    3 / -0

    The average marks of Rohan in three tests were 45. If the marks he scored in the first and the second test respectively are 32 and 52, then how many marks did he score in the third test?

    Solution

    The average marks of Rohan in three tests were 45.
    Then, sum of the marks obtained in all the tests = 45 × 3 = 135 marks
    Now, if the marks scored in the first and second test are 32 and 52, respectively.
    So, he scored: (32 + 52) = 84 marks
    Then, marks he scored in the third test = 135 - 84 = 51

     

  • Question 29
    3 / -0

    The temperature in the afternoon was 82.4°F. What is this temperature in degree Celsius? [Use C= (5/9)(F - 32)]

    Solution

    (82.4 − 32) × 5/9 = 28°C

     

  • Question 30
    3 / -0

    There are 75 computers on every floor of a company. There are 50 floors in the building of the company. Each computer needs to be installed with 2 speakers. How many speakers would be required to install in every computer of the company?

    Solution

    Total number of speakers = 50 × 75 × 2 = 7500

     

  • Question 31
    3 / -0

    A book contains 204 pages. Emily reads (2/3)rd of the pages on Monday and (1/4)th of the remaining pages on Tuesday. She wants to complete the reading of the book on Wednesday. How many pages does she have to read on Wednesday?

    Solution

    Total number of pages = 204
    Number of pages read on Monday = 2/3 × 204 = 136
    Number of remaining pages = 204 - 136 = 68
    Number of pages read on Tuesday = 1/4 × 68 = 17
    Number of remaining pages she will read on Wednesday = 68 - 17 = 51

     

  • Question 32
    3 / -0

    A girl walks around the park of side 40 m. How much distance has she walked, if she takes 8 rounds of the park?

    Solution

    Side of the park = 40 m
    Perimeter of the park = 4 × 40 = 160 m
    Number of rounds made = 8
    Total distance walked = 8 × 160 = 1280 m

     

  • Question 33
    3 / -0

    Rajeev bought 2 cars worth Rs. 15,25,000. He sold one of them for Rs. 9,00,000 and the other one for Rs. 8,75,000. What amount of money did he gain?

    Solution

    Rajeev brought 2 cars for Rs. 15,25,000.
    He sold 2 cars for Rs. (9,00,000 + 875000) = Rs. 17,75,000.
    Gain = 17,75,000 - 15,25,000 = Rs. 2,50,000

     

  • Question 34
    3 / -0

    What is the number of rectangular tiles of size 9 cm × 5 cm, required for flooring a squared basement of side 4.5 m?

    Solution

    Area of one rectangular tile = 9 × 5 = 45 cm2
    = 45 cm2 = 0.0045 m2
    Area of the basement = 4.5 × 4.5 m2 = 20.25 m2
    Number of tiles required = 20.25 ÷ 0.0045 = 4500

     

  • Question 35
    3 / -0

    Two friends went to a stationery shop. The first friend bought 3 pencils and 5 books and the second friend bought 3 books and 2 pencils. The first friend paid money for both of them. How much money did he pay to the shopkeeper if the cost of one pencil was Rs. 5 and the cost of one book was Rs. 30?

    Solution

    Cost of 1 pencil = Rs. 5
    So, cost of (3 + 2) 5 pencils = 5 × 5 = Rs. 25
    Cost of 1 book = Rs 30
    So, cost of (5 + 3) 8 books = 30 × 8 = Rs. 240
    Total money paid = Rs. (25 + 240) = Rs. 265

     

  • Question 36
    3 / -0

    A square room has side 15 m. What will be the cost of flooring the room if the cost of flooring 1 sq. cm is Rs. 0.25?

    Solution

    Side of the room = 15 m
    Area of the room = 15 × 15 m2 = 225 m2
    = 22,50,000 cm2
    Now, cost of flooring = Rs. 0.25/cm2
    Therefore, total cost = Rs. 0.25 × 12,50,000 = Rs. 5,62,500

     

  • Question 37
    3 / -0

    How many cubical boxes of side 6 m will be needed to make a cuboidal box of dimensions 15 m × 12 m × 6 m?

    Solution

    Let us first find the volume of the cubical box of side 6 m.
    Volume = 6 m × 6 m × 6 m = 216 m3
    Now, volume of the cuboidal box = 15 m × 12 m × 6 m = 1080 m3
    So, number of cubical boxes of side 6 m needed to make a cuboidal box of dimensions 15 m × 12 m × 6 m
    = 1080/216 = 5

     

  • Question 38
    3 / -0

    Two parks, one rectangular and the other square, have equal perimeter. The length and the breadth of the rectangular park are 30 m and 24 m, respectively. What is the area of the square park?

    Solution

    Perimeter of the rectangular park = 2(l + b)
    = 2(30 + 24) = 108 sq. m
    Perimeter of the square park = 4a
    108 = 4a
    a =  108/4 = 27
    Area of the square park = a × a = 27 × 27 = 729 sq. m

     

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