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Mathematics (Paper-1) Mock Test - 4

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Mathematics (Paper-1) Mock Test - 4
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  • Question 1
    3 / -0

    The biggest 5-digit number that can be formed using all the digits 4, 8, 9, 1, 2 is

    Solution

    The biggest number that can be formed using all the digits 4, 8, 9, 1, 2 is 98421.

     

  • Question 2
    3 / -0

    Choose the correct option if numbers 675892, 657892, 756892, 789256 and 789526 are arranged in ascending order.

    Solution

    657892 < 675892

    675892 < 756892

    756892 < 789256

    789256 < 789526

    657892, 675892, 756892, 789256 and 789526 is the ascending order for the given numbers.

     

  • Question 3
    3 / -0

    Simplify the following expression:

    35.105 - 13.65 - 7.754

    Solution

    35.105 - 13.65 - 7.754

    = 21.455 - 7.754 = 13.701

     

  • Question 4
    3 / -0

    Convert (3/5) into percentage.

    Solution

    In order to convert a fraction into percentage form, we multiply it by 100.
    So, the percentage form of 3/5 will be
     (3/5) × 100 = 60%

     

  • Question 5
    3 / -0

    The biggest 5-digit number that can be formed using the digits 8, 9, 0, 2 and 3, without repetition, is

    Solution

    The biggest 5-digit number that can be formed using the digits 8, 9, 0, 2 and 3, without repetition, is 98,320.

     

  • Question 6
    3 / -0

    Simplify the following expression:

    3 + 1/100 + 2 + 3/1000

    Solution

    Given: 3 + 1/100 + 2 + 3/1000

    = 3 + 2 + 0.01 + 0.003 = 5.013

     

  • Question 7
    3 / -0

    Write 348 in Roman numerals.

    Solution

    348 = 300 + 40 + 8
    = (100 + 100 + 100) + (50 - 10) + 8
    = CCCXLVIII

     

  • Question 8
    3 / -0

    Value of (800 × 15) ÷ {(100 ÷ 10) + (45 - 35)} is

    Solution

    (800 × 15) ÷ {(100 ÷ 10) + (45 - 35)}
    = 12000 ÷ (10 + 10)
    = 12000 ÷ 20 = 600

     

  • Question 9
    3 / -0

    The biggest even number that can be formed using the digits 4, 8, 3, 9 only once is

    Solution

    The biggest even number that can be formed using the digits 4, 8, 3, 9 only once is 9834.

     

  • Question 10
    3 / -0

    A flight left Delhi at 02:45 PM on Monday and reached London at 3:15 AM on Tuesday. The duration of the journey is

    Solution

    Flight left Delhi at 2:45 PM.
    From 2:45 PM to 2:45 AM, it covers 12 hours journey.
    From 2:45 AM to 3:15 AM, it takes 30 minutes.
    So, total time taken by flight is 12 hours and 30 minutes.

     

  • Question 11
    3 / -0

    What number should be subtracted from 986575 to make it equal to the sum of 25698 and 456125?

    Solution

    25698 + 456125 = 481823
    Required number = 986575 - 481823 = 504752

     

  • Question 12
    3 / -0

    Three dogs weigh 6 kg, 12 kg and 9 kg. How much more is the weight of the heaviest dog than the average weight of the three dogs?

    Solution

    Weights of three dogs are 6 kg, 12 kg and 9 kg respectively.
    Average of the weight of three dogs = 6 + 12 + 9 / 3 ⇒ 27/3 = 9 kg
    Heaviest dog is 12 kg
    So, difference = 12 – 9 = 3 kg

     

  • Question 13
    3 / -0

    The fraction equivalent to 1.75 is

    Solution

    The fraction equivalent of 1.75 = 175/100 = 7/4

     

  • Question 14
    3 / -0

    Amy bought an old phone for Rs. 9,000 and spent Rs. 900 on its maintenance. If she sold the old phone for Rs. 8,550, then her loss percentage is

    Solution

    Total cost price = 9,000 + 900 = Rs. 9,900
    Selling price = Rs. 8,550
    Loss = 9,900 – 8,550 = Rs. 1,350
    Loss percentage = (1350 / 9900) × 100 = 13.63%

     

  • Question 15
    3 / -0

    Which of the following statements is false?

    Solution

    All rhombuses are not square as measure of each interior angle is not 90° in rhombus.

     

  • Question 16
    3 / -0

    Which of the following measures of interior angles of a triangle can form a triangle?

    Solution

    Sum of angles of a triangle is 180°.
    42° + 63° + 75° = 180°

     

  • Question 17
    3 / -0

    What would be the volume of a cubical box if its side is 3 m?

    Solution

    Given: Side = 3 m
    Volume of a cubical box = Side × Side × Side = 3 × 3 × 3 = 27 m3

     

  • Question 18
    3 / -0

    There is a rectangular park which is 60 m long and 15 m wide. Find the perimeter of a square room whose area is equal to that of the rectangular park.

    Solution

    Area of rectangle = Length × Breadth = 60 × 15 = 900 m2

    According to the question, area of square is equal to the area of rectangle.

    So, area of square = 900 m2

    Side of the square = √900 m = 30 m

    Perimeter of square= 4 × Side = 4 × 30 = 120 m

     

  • Question 19
    3 / -0

    What would be the next column of numbers?

    9 25 41
    20 38 56
    31 51 71
    Solution

    Starting number of each column is 16 more than the first number of previous column and each of the numbers in a column increases in odd numbers.
    For first column, it increases in 11.
    For second, it increases in 13.
    For third, it increases in 15.
    For fourth, it increases in 17.
    So, the next column will be 41 + 16, 41 + 16 + 17, 41 + 16 + 17 + 17
    i.e. 57, 74, 91.

     

  • Question 20
    3 / -0

    Round off 45525 to the nearest thousands.

    Solution

    When we round off 45525 to the nearest thousands, it will be rounded up to 46000 as the hundreds digit is 5.
    So, when the digit is 5 or more, the number rounds up.

     

  • Question 21
    3 / -0

    A bus has to cover a distance of 579.5 km. If the speed of the bus is 61 km/hr, then how much time will the bus take to cover the distance?

    Solution

    Time = Distance / Speed

    = 579.5 / 61

    = 19/2

    = 9.5 hours or 9 hours and 30 minutes

     

  • Question 22
    3 / -0

    A car can cover 72 km in 3 hours. What is the speed of car in m/s?

    Solution

    Distance = 72 km
    Time = 3 hours
    Speed = distance / time = 72/3 = 24 km/hr
    = 24 × 5/18 = 6.67 m/sec

     

  • Question 23
    3 / -0

    A man is riding motorcycle at a speed of 10 m/sec. Convert it into km/hr.

    Solution

    To convert m/sec into km/hr, we multiply by (18/5) .

    So, 10 m/sec = (10 × 18/5) = 36 km/hr

     

  • Question 24
    3 / -0

    Raman has 16 match boxes. Dimensions of each box are 5 cm × 4 cm × 3 cm. He arranged the boxes in such a way so as to form a cuboid with no space leftover in between. What is the volume of the resulting cuboid?

    Solution

    Volume of 1 box = 5 cm × 4 cm × 3 cm = 60 cm3
    Volume of the resulting cuboid = 60 × 16 = 960 cm3

     

  • Question 25
    3 / -0

    A basketball court is 15 m long and 8 m wide. What will be the total cost of flooring the court with wood at the rate of Rs. 2000 per square metre?

    Solution

    Area of the court = (15 × 8) m2 = 120 m2
    Total cost = 120 × 2000 = Rs. 2,40,000

     

  • Question 26
    3 / -0

    Amaira painted 3/7 of a painting. Her friend helped and painted 4/7 of the painting. What fraction of painting did they paint altogether?

    Solution

    Fraction of painting painted by Amaira = 3/7
    Fraction of painting painted by her friend = 4/7
    Total fraction of painting painted by Amaira and her friend = 3/7 + 4/7 = 1

     

  • Question 27
    3 / -0

    Daniel has 1/7 of a sack of sugar. He divides the sugar equally into 3 bags. What fraction of the full sack of sugar is in each bag?

    Solution

    Fraction of sugar with Daniel = 1/7
    Daniel divides sugar into 3 bags.
    Therefore, required fraction = 1/7 × 1/3 = 1/21

     

  • Question 28
    3 / -0

    A square-shaped classroom has side 44 m. What is the total cost of flooring the classroom if the cost for 1 cm2 is Rs. 0.74?

    Solution

    Side of the classroom = 44 m
    Area of the classroom = (44 × 44) m2
    = 1936 m2 = 1,93,60,000 cm2 (1 m2 = 10,000 cm2)
    Now, cost of flooring = Rs. 0.74/cm2
    Total cost = Rs. 0.74 × 1,93,60,000 = Rs. 1,43,26,400

     

  • Question 29
    3 / -0

    Find the greatest common factor of 112, 84 and 504.

    Solution

    112 = 2 × 2 × 2 × 2 × 7
    84 = 2 × 2 × 3 × 7
    504 = 2 × 2 × 2 × 3 × 3 × 7
    ∴ Greatest common factor = 2 × 2 × 7 = 28

     

  • Question 30
    3 / -0

    Rohit's pen is 20 cm long. What does the pen measure in mm?

    Solution

    1 cm = 10 mm
    20 cm = 200 mm

     

  • Question 31
    3 / -0

    A Private Limited Company, in its first year, makes a profit of Rs. 1,00,420 and in the second year, it doubles the profit made in the first year, and in the third year, it doubles the profit made in the second year. How much profit has the company made in its three years?

    Solution

    Profit made in the first year = Rs. 1,00,420
    Profit made in the second year = Rs. 1,00,420 × 2 = Rs. 2,00,840
    Profit made in the third year = Rs. 1,00,420 × 4 = Rs. 4,01,680
    Total profit made in three years = Rs. 1,00,420 + 2,00,840 + 4,01,680 = Rs. 7,02,940

     

  • Question 32
    3 / -0

    There are 46 rooms in a school. Each room has 58 benches. Each bench has been made by using 4 pieces of wood. Find the total number of pieces of wood used to make the benches of the school.

    Solution

    Total number of rooms = 46
    Number of benches in every room = 58
    Total number of benches = 46 × 58 = 2668
    Each bench is made of 4 pieces of wood.
    Total number of pieces of wood that will be used = 2668 × 4 = 10,672

     

  • Question 33
    3 / -0

    What is 20% of 1 km?

    Solution

    1 km = 1000 m
    20% of 1000 m = (20/100) × 1000 = 200 m

     

  • Question 34
    3 / -0

    An athlete runs around a square ground of side 50 m. Find the distance covered by the athlete if he takes 15 rounds of the ground.

    Solution

    Side of the ground = 50 m
    Perimeter of the ground = 4 × 50 = 200 m
    Number of rounds made = 15
    Total distance covered = 15 × 200 = 3000 m

     

  • Question 35
    3 / -0

    Find the sum of the number 25,048 and the number obtained by interchanging the places of 5 and 4.

    Solution

    The number obtained by interchanging 5 and 4 is 24,058.
    Therefore, the sum is:
    25,048 + 24,058 = 49,106

     

  • Question 36
    3 / -0

    The cost of a pack of 20 eggs is Rs. 100 and a pack of 15 breads is Rs. 375. If Harry bought 1 egg and 1 bread, then how much would he pay to the shopkeeper?

    Solution

    Cost of 1 egg = 100/20 = Rs. 5
    Cost of 1 bread = 375/15 = Rs. 25
    Harry would pay Rs. 25 + Rs. 5 = Rs. 30 to the shopkeeper

     

  • Question 37
    3 / -0

    The perimeter of a square room is 120 m. What is the area of the room?

    Solution

    Given, Perimeter = 120 m
    Perimeter = 4 x Side
    Area of square (A) = a2
    Side of square room = 120/4 = 30 m
    Area = 30 × 30 = 900 m2

     

  • Question 38
    3 / -0

    The greatest number that divides 57 and 107 leaving remainder 7 in each case is:

    Solution

    57 ÷ 50 = Quotient 1, remainder 7
    107 ÷ 50 = Quotient 2, remainder 7

    The greatest number that divides 57 and 107 leaving remainder 7 in each case is 50.

     

  • Question 39
    3 / -0

    Julie bought a laptop for Rs. 26,000 and sold it for Rs. 25,480. What was her loss or gain percent?

    Solution

    Cost price of laptop = Rs. 26,000
    Sale price of laptop = Rs. 25,480
    Loss = CP – SP = 26,000 - 25,480 = Rs. 520
    Loss % = (520 / 26000) × 100 = 2%

     

  • Question 40
    3 / -0

    Virat had two cars. He sold one car for Rs. 18,52,324 and other car for Rs. 15,34,432. He bought both cars for Rs. 39,50,000. How much money did he lose?

    Solution

    CP of 2 cars = Rs. 39,50,000
    SP of 2 cars = (18,52,324 + 15,34,432) = Rs. 33,86,756
    Loss = CP – SP = 39,50,000 - 33,86,756 = Rs. 5,63,244

     

  • Question 41
    3 / -0

    The smallest even number formed using the digits 1, 5, 7, 2 and 3 is

    Solution

    As we look at the numbers, we see that 2 has to be at units place.
    Now, we need to find the smallest number in the ascending order among these numbers.

     

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