Chemistry Test - 21

Bromine is a p-block element having an atomic number 35. Bromine belongs to group 17 which is known as halogens.

Higher the value of \(\mathrm{K_H}\) at a given pressure, higher is the solubility of the gas in the liquids regarding Henry's law is not correct.

Concentration of \(\mathrm{SO}_4{ }^{2-}\) in \(\mathrm{BaSO}_4\) solution

\(M_1 V_1=M_2 V_2 \)

\(1 \times 50=M_2 \times 500 \)

\(M_2=\frac{1}{10}\)

For just precipitation

lonic product \(=\mathrm{K}_{\mathrm{sp}}\)

\(\left[\mathrm{Ba}^{2+}\right]\left[\mathrm{SO}_4{ }^2\right]=\mathrm{K}_{\mathrm{sp}}\left(\mathrm{BaSO}_4\right)\)

\(\left[\mathrm{Ba}^{2+}\right] \times \frac{1}{10}=10^{-10}\)

\(\left[\mathrm{Ba}^{2+}\right]=10^{-9} \mathrm{M}\) in \(500 \mathrm{~mL}\) solution

Thus \(\left[\mathrm{Ba}^{2+}\right]\) in original solution

\((500-50=450 \mathrm{~mL})\)

\(\Rightarrow \mathrm{M}_1 \times 450=10^{-9} \times 500\)

[ where \(\mathrm{M}_1=\) Molarity of original solution]

\(\mathrm{M}_1=\frac{500}{450} \times 10^{-9}=1.11 \times 10^{-9} \mathrm{M}\)

\(\mathrm{HIO}_4>\mathrm{HBrO}_4>\mathrm{HCIO}_4\) statements about acid strength is false.

Oxygen is more electronegative than chlorine. With an increase in the number of \(\mathrm{O}\) atoms attached to \(\mathrm{Cl}\), more electrons are pulled away from the \(\mathrm{(O - H})\) bond and weaker becomes the \(\mathrm{O - H}\) bond. This increases the acid strength.

The decreasing order of acidic strength is \(\mathrm{HClO} _4> \mathrm{HClO} _3> \mathrm{HClO} _2> \mathrm{HClO}\).

C₃H₅Bris an allyl bromide.

Allyl Bromide is also known as 3-Bromo-1-propene, 3-Bromopropylene, 3-Bromopropene, 1-Propene, 3-bromo-, Bromallylene, 3-bromoprop-1-ene, Propene with Molecular Formula of C₃H₅Br and Molecular Weight of 120.9758.

Organic compound having covalent bond is carbon tetrachloride.

Covalent compound are generally formed between two non--metals. Carbon tetrachloride is covalent compounds and also organic compound. Carbon tetrachloride is a nonpolar covalent compound because the electrons shared by the carbon and chlorine atoms are nearly at the center of the bond. Therefore, the carbon tetrachloride CCl₄ is a covalent compound.

\(\mathrm{KMnO}_4\) is the strong oxidizing agent. When a small amount of \(\mathrm{KMnO}_4\) is treated with \(\mathrm{H}_2 \mathrm{SO}_4\), then \(\mathrm{Mn}_2 \mathrm{O}_7\) is formed.

\(2 \mathrm{KMnO}_4(\mathrm{~s})+2 \mathrm{H}_2 \mathrm{SO}_4(\mathrm{aq})\rightarrow 2 \mathrm{KHSO}_4(\mathrm{~s})+\mathrm{H}_2 \mathrm{O}(\mathrm{aq})+\mathrm{Mn}_2 \mathrm{O}_7(\mathrm{aq})\)

\(\mathrm{Mn}_2 \mathrm{O}_7\) is a green-colored volatile compound that is explosive in nature.

\(\mathrm{Mn}_2 \mathrm{O}_7\) becomes explosive in nature at \(55^{\circ} \mathrm{C}\) or above.

Sucrosedoes not give a silver mirror test with Tollen's reagent.

Silver mirror test with Tollen's reagent is given by the molecule which contains an aldehyde group. But, sucrose has no aldehyde group and the rest of the molecule have an aldehyde group. Hence, glucose, fructose, and lactose, each gives a silver mirror test except sucrose.

Fibers can be repeatedly stretched more than \(500\%\) of its original size and can also recover back; immediately to its original size and shape once the tension is relaxed. Fibres possess high tensile strength and high modulus. Fibres impart crystalline nature. Characteristic features of fibres are due to strong intermolecular forces like hydrogen bonding. Fibers used in clothing are used to cover the body, to protect our body, etc.