Chemistry Test

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Chemistry Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

What are the end products of the reaction given below as per Groove's process?

Ethanol \(+\mathrm{HCl} \rightarrow\)

A
Ethyl chloride and water

B
Ethene and \(\mathrm{HOCl}\)

C
Ethanal and \(\mathrm{HCl}\)

D
Ethene and water

Solution

Ethanol \(+\mathrm{HCl} \rightarrow\)Ethyl chloride and water.
Question 2
1 / -0

What is the main factor responsible for weak acidic nature of B-F bonds in BF₃?

A
Large electronegativity of F

B
Three centered two electron bonds in BF₃

C
\(p \pi-d \pi\)back bonding

D
\(p \pi-p \pi\)back bonding

Solution

\(p \pi-p \pi\) back-bonding is the main factor responsible for the weak acidic nature of B-F bonds in BF₃.
Question 3
1 / -0

Which of the following is incorrect?

A

Hydrolysis of \(\mathrm{NCl}_{3}\) gives \(\mathrm{NH}_{3}\) and \(\mathrm{HOCl}\).

B
\(\mathrm{NH}_{3}\) is less stable than \(\mathrm{PH}_{3}\).

C
\(\mathrm{NH}_{3}\) is a weak reducing reagent as compared to \(\mathrm{PH}_{3}\)

D
Nitric oxide in solid state exhibits diarr

Solution

\(\mathrm{NH}_{3}\) is less stable than \(\mathrm{PH}_{3}\).
Question 4
1 / -0

The number average molar mass and the mass average molar mass of a polymer is 30000 and 40000, respectively. The polydispersity index (PDI) of the polymer is:

A
-1

B
0

C
> 1

D
< 1

Solution

We know that,

Polydispersity index \((\mathrm{PDI})=\frac{\text { Mass average molar mass }}{\text { Number average molar mass }}\)

\(=\frac{\mathrm{M}_{\mathrm{w}}}{\mathrm{M}_{\mathrm{h}}}\)

\(=\frac{40,000}{30,000}=1.3>1\)
Question 5
1 / -0

Perlon is:

A
Terylene

B
Rubber

C
Nylon-\(6\)

D
Polyester

Solution

Nylon-\(6\) is also called perlon. It is a polymer of caprolactam.
Question 6
1 / -0

Which of the following statements best explains the law of conservation of mass, concerning a chemical change?

A
100 g of water is heated to give steam.

B
A sample of \(N_{2}\) gas is heated at constant pressure without any change in mass.

C
36 g of carbon combines with 32 g of oxygen to form 68 g of\(CO_{2}\).

D
10 g of carbon is heated in vacuum without any change in mass.

Solution

The statement that best explains the law of conservation of mass, concerning a chemical change is "36 g of carbon combines with 32 g of oxygen to form 68 g of \(CO_{2}\)".
Question 7
1 / -0

The solubility of the gas in a liquid solution _____ with increase in temperature.

A
Decreases

B
Increases

C
Remains same

D
None of these

Solution

The solubility of the gas in a liquid solution decreases with increase in temperature. This is because, with an increase in temperature, the kinetic energy of the gas molecule increases, thus it becomes difficult for liquid molecules to hold them.
Question 8
1 / -0

Starch is converted into disaccharide in presence of:

A
Diastase

B
Maltose

C
Zymose

D
Lactose

Solution

Starch is converted into disaccharide in presence ofDiastase.

In the presence of diastase, starch breaks down to maltose. Maltose is a disaccharide consisting of 2 glucose units.

A diastase is any one of a group of enzymes that catalyses the breakdown of starch into maltose. Alpha amylase degrades starch to a mixture of the disaccharide maltose; the trisaccharide maltotriose, which contains three α (1-4)-linked glucose residues; and oligosaccharides, known as dextrins, that contain the α (1-6)-linked glucose branches.
Question 9
1 / -0

What is the IUPAC name of t-butyl alcohol?

A
2–Methyl-propan–2-ol

B
Propanol-2

C
Butanol–2

D
Butanol–1

Solution

Below is the structure of tertiary butyl alcohol. Longest carbon chain contains 3 carbons and one methyl group and one hydroxy group at 2 position.

Therefore, the IUPAC name of tertiary butyl alcohol is 2-methyl-2-propanol.
Question 10
1 / -0

For the cell reaction: \(Cu ^{2+}( aq )\left( C _1\right)+ Zn ( s ) \rightarrow Zn ^{2+}( aq )\left( C _2\right)+ Cu ( s )\) the change in free energy \(\Delta G\) at a given temperature is a function of:

A
\(\operatorname{lnC}_1\)

B
\(\ln \left(\frac{C_2}{C_1}\right)\)

C
\(\ln \left(C_2+C_2\right)\)

D
\(\ln \left( C _2\right)\)

Solution

We know \(\Delta G = nFE\)

Again according to Nernst equation,

\(E =\frac{0.059}{ n } \log \frac{\left[ Zn ^{2+}\right]}{\left[ Cu ^{2+}\right]}\) at \(25^{\circ} C\)

So \(\Delta G\) (free energy change) in an electrochemical cell at a given temperature is a function of

\(\ln \frac{\left[ Zn ^{2+}\right]}{\left[ Cu ^{2+}\right]}=\ln \frac{ [C _2]}{ [C _1]}\)

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Chemistry Test - 22

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Chemistry Test - 22

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Question 1

Ethyl chloride and water

Ethene and \(\mathrm{HOCl}\)

Ethanal and \(\mathrm{HCl}\)

Ethene and water

Solution

Question 2

Large electronegativity of F

Three centered two electron bonds in BF3

\(p \pi-d \pi\)back bonding

\(p \pi-p \pi\)back bonding

Solution

Question 3

Hydrolysis of \(\mathrm{NCl}_{3}\) gives \(\mathrm{NH}_{3}\) and \(\mathrm{HOCl}\).

\(\mathrm{NH}_{3}\) is less stable than \(\mathrm{PH}_{3}\).

\(\mathrm{NH}_{3}\) is a weak reducing reagent as compared to \(\mathrm{PH}_{3}\)

Nitric oxide in solid state exhibits diarr

Solution

Question 4

-1

0

> 1

< 1

Solution

Question 5

Terylene

Rubber

Nylon-\(6\)

Polyester

Solution

Question 6

100 g of water is heated to give steam.

A sample of \(N_{2}\) gas is heated at constant pressure without any change in mass.

36 g of carbon combines with 32 g of oxygen to form 68 g of\(CO_{2}\).

10 g of carbon is heated in vacuum without any change in mass.

Solution

Question 7

Decreases

Increases

Remains same

None of these

Solution

Question 8

Diastase

Maltose

Zymose

Lactose

Solution

Question 9

2–Methyl-propan–2-ol

Propanol-2

Butanol–2

Butanol–1

Solution

Question 10

\(\operatorname{lnC}_1\)

\(\ln \left(\frac{C_2}{C_1}\right)\)

\(\ln \left(C_2+C_2\right)\)

\(\ln \left( C _2\right)\)

Solution

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Three centered two electron bonds in BF₃