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Physics Test - 20

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Physics Test - 20
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  • Question 1
    1 / -0

    A body floats in a liquid contained in a beaker. The whole system falls freely under gravity. The upthrust on the body due to the liquid is

    Solution

    For a body falling freely under gravity, the effective value of g is zero. Hence, the upthrust is zero.

  • Question 2
    1 / -0

    A small drop of water of surface tension  is squeezed between two clean glass plates, so that a thin layer of thickness d and area A is formed between them. If the angle of contact is zero, then the force required to pull the plates apart is

    Solution

  • Question 3
    1 / -0

    A body of density ρ is dropped from rest at a height 'h' into a lake of density 'σ', where σ > ρ . Neglecting all the dissipative forces, calculate the maximum depth to which the body sinks before returning to float on the surface.

    Solution

  • Question 4
    1 / -0

    A small particle is released inside the depth of a liquid in the vessel. The volume of the particle is V. Density and viscosity of the liquid are ρ and η, respectively. Buoyant force on the particle is greater than the weight of the particle. The variation of velocity of the particle with time is

    Solution

    Initially the up thrust is more than its weight, so it will accelerate, i.e. its velocity increases. As the viscosity increases, the viscous force also increases. The acceleration decreases at a time when the viscous force and the weight acting downward balance the up thrust. Finally, the acceleration will become zero and it will move with a constant velocity.

  • Question 5
    1 / -0

    The excess pressure inside a spherical drop of water is four times that of another drop. Then, their mass ratio is

    Solution

  • Question 6
    1 / -0

    The Leaning Tower of Pisa does not fall because

    Solution

    The Leaning Tower of Pisa does not fall because the vertical line through the centre of gravity of the tower falls within its base.

  • Question 7
    1 / -0

    If the Earth stops rotating, the value of g at the equator will

    Solution

    At the equator, the value of acceleration due to gravity is g' = g - ω2R.

    If the Earth stops rotating, ω = 0, g' = g

    So, the value of acceleration due to gravity will increase.

  • Question 8
    1 / -0

    If Earth suddenly contracts to 1.5% of its present size, without any change in its mass, then how would the value of acceleration due to gravity change?

    Solution

  • Question 9
    1 / -0

    Kepler's second law states that the straight line joining a planet to the sun sweeps out equal areas in equal time. This statement is equivalent to the statement that

    Solution

    Earth and all other planets move around the sun under the effect of gravitational force. This force always acts along the line joining the centre of the planet and the sun and is directed towards the sun. In other words, a planet moves around the sun under the effect of a purely radial force. Therefore, areal velocity of the planet must always remain constant.

  • Question 10
    1 / -0

    The angular velocity of a planet revolving in an elliptical orbit around the sun __________ when it comes near the sun

    Solution

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