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Research Aptitude Test - 3

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Research Aptitude Test - 3
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Weekly Quiz Competition
  • Question 1
    2 / -0.5

    Directions:  For each of the below questions, identify which option(s) logically follow based on the given statement.
    Whenever my mother scolds me, I either hide behind my father or complain to my grandma.

    Solution

    If whenever my mother scolds me, I either hide behind my father or complain to my grandma. Then, if I did not complain to my grandma &did not hide behind my father, my mother must not have scolded me. Correct option is (a) 

  • Question 2
    2 / -0.5

    Directions to Solve

    In each of the following questions find out the alternative which will replace the question mark.

    Question -

    REASON : SFBTPO :: THINK : ?

    Solution

    Hence, the correct ans is UIJOL which is option b.

  • Question 3
    2 / -0.5

    At what angle the hands of a clock are inclined at 15 minutes past 5?

    Solution

    15 past 5 means  quarter  past 5 = (5:15)
    ⇒ (11*15 - 60*5)/2 = 67.5

  • Question 4
    2 / -0.5

    Priya can do 1/2 of the work in 8 days, while Preeti can do 1/3 of the work in 6 days. How long will it take for both of them to finish the work?

    Solution

    Priya ’s days work = (½)/8 = 1/16

    Preeti ’s days work

    ⇒(⅓)/6 = 1/18 days

    Together they can finish in.

  • Question 5
    2 / -0.5

    find the difference between the simple and the compound interest at 5% per annum for 2 years on a principal of Rs. 2000.

    Solution

    To find the difference between simple interest and compound interest at 5% per annum for 2 years on a principal of Rs. 2000, follow these steps:

    • Simple Interest (SI) :

      • Formula: SI = (Principal ×Rate ×Time) / 100
      • Calculation: SI = (2000 ×5 ×2) / 100 = Rs. 200
    • Compound Interest (CI) :

      • Formula: CI = Principal ×(1 + Rate/100)Time - Principal
      • Calculation: CI = 2000 ×(1 + 5/100)2 - 2000
      • Simplified: CI = 2000 ×1.1025 - 2000 = Rs. 205
    • Difference between CI and SI:

      • Difference = CI - SI = 205 - 200 = Rs. 5

     

  • Question 6
    2 / -0.5

    What is the simple interest for five years on a sum of Rs. 700 if the rate of interest for the first 3 years is 8% per annum and for another 2 years is 7% per annum?

    Solution

  • Question 7
    2 / -0.5

    Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 45 kmph, respectively. In how much time will they cross each other, if they are running in the same direction?

    Solution

    Relative speed = (45-40)kmph = 5 kmph.

    = (5 x (5/18))m/sec = (25/18) m/sec

    Total distance covered = Sum of the length of trains = 350 m

    ∴ Time taken = (350 x (18/25))sec = 252 sec.

  • Question 8
    2 / -0.5

    It is postulated that huge deposits of NaCI (rock salt) and CaCO3(chalk and marble) are sites of erstwhile oceans, where the salts had been concentrated through weathering by rain and wind and leaching by rivers. Select the correct explanatory statement in this context.

    Solution

    The solubility of CaCO3 in water is pH dependent and is enhanced by acidic atmospheric gases. Hence, CaCO3 may be leached into water during weathering.

  • Question 9
    2 / -0.5

    If log 2 = 0.30103 and log 3 = 0.4771, find the number of digits in (648) 5.

    Solution

    You must know and Remember that No. of Significant Digit before decimal = [ (Characteristic)base 10 + 1]. To find (Characteristic)base10 ,

    Log (648)5 = 5(log 648) = 5(log 23 .34 ) = 5(3.log2 + 4 log 3) = 5(3(0.301) + 4(0.4771))

    (Characteristic)base10 ,= 14

    So, Answer is 14 + 1 = 15

  • Question 10
    2 / -0.5

    A man can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 km/h and the rest at 5km/h. The total distance is

    Solution

    You must Know Km/hr (5/18) = m/sec

    Say Total Distance be d

    (2d/3)/4 + (d/3)/5 = 1+24/60

    So, get d = 6 Km

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