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  • Question 1
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    The constraints –x + y ≤ 1, −x + 3y ≤ 9 and x, y ≥ 0 defines on-

  • Question 2
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    What is the scalar projection of \(\vec{a}=\hat{i}-2 \hat{j}+\hat{k}\) on \(\vec{b}=4 \hat{i}-4 \hat{j}+7 \hat{k} ?\)

  • Question 3
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    Find the shortest distance between the lines \(\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1}\) and \(\frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-7}{1}\).

  • Question 4
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    Find the value ofsinθ(1+tanθ)+cosθ(1+cotθ)

  • Question 5
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    Consider the following equations for two vectors \(\vec{a}\) and \(\vec{b}\):

    1. \((\vec{a}+\vec{b}) \cdot(\vec{a}-\vec{b})=|\vec{a}|^{2}-|\vec{b}|^{2}\)

    2. \((|\vec{a}+\vec{b}|)(|\vec{a}-\vec{b}|)=|\vec{a}|^{2}-|\vec{b}|^{2}\)

    3. \(|\vec{a} \cdot \vec{b}|^{2}+|\vec{a} \times \vec{b}|^{2}=|\vec{a}|^{2}|\vec{b}|^{2}\)

    Which of the above statement are correct?

  • Question 6
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    If the line, \(\frac{(x-3)}{1}=\frac{(y-2)}{-1}=\frac{(z+\lambda)}{-2}\) lie in the plane, \(2 x-4 y+3 z=2\), then the shortest distance between this line and the line \(\frac{(x-1)}{12}=\frac{y}{9}=\frac{z}{4}\) is:

  • Question 7
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    Find the differentiation of the following function \(\sec ^{-1} \tan x .\)

  • Question 8
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    For \(x \neq 0\), find the value of \(f(x)=\frac{x\left(3^{x}-1\right)}{1-\cos x}\):

  • Question 9
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    The mean of 20 observations is \(15 .\) On checking, it was found that two observations were wrongly copied as 3 and 6 . If wrong observations are replaced by correct values 8 and 4 , then the correct mean is:

  • Question 10
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    If \(m\left[\begin{array}{ll}-3 & 4\end{array}\right]+n\left[\begin{array}{ll}4 & -3\end{array}\right]=\left[\begin{array}{ll}10 & -11\end{array}\right]\), then find \(m\) and \(n\).

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