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Quantitative Aptitude Test - 2

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Quantitative Aptitude Test - 2
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Weekly Quiz Competition
  • Question 1
    1 / -0
    In how many ways can eight people comprising four married couples sit at a circular table such that no two men sit together and no husband sits beside his wife?
     
    Solution

    Let H1, H2, H3 and H4 be the husbands and W1, W2, W3 and W4 be their wives respectively. The number of ways in which H1, H2, H3 and H4 can sit at the table is (4 – 1)! = 3! = 6.
    Only two arrangements are possible for each of the above 6 cases (as illustrated by the figure given below for one of the cases):



    So the answer = 2 × 6 = 12

  • Question 2
    1 / -0

    What is the value of

    Solution

  • Question 3
    1 / -0
    P +1/Q =Q+ 1/R =1,where P, Q and R are real numbers. What is the value of PQR +R +1/P ?
     
    Solution

  • Question 4
    1 / -0

    The figure below represents the total number of students and the number of girls in college XYZ for the five years from 2009-10 to 2013-14. During this period, the total number of students increased from 100 to 1000, while the number of girls increased from 25 to 450.

    Total number of students = Number of boys + Number of girls
    The highest percentage growth in the total number of students, relative to the previous year, occurred in
    Solution


  • Question 5
    1 / -0

    The figure below represents the total number of students and the number of girls in college XYZ for the five years from 2009-10 to 2013-14. During this period, the total number of students increased from 100 to 1000, while the number of girls increased from 25 to 450.

    Total number of students = Number of boys + Number of girls

    The highest percentage growth in the total number of girls, relative to the previous year, occurred in

    Solution


  • Question 6
    1 / -0

    The figure below represents the total number of students and the number of girls in college XYZ for the five years from 2009-10 to 2013-14. During this period, the total number of students increased from 100 to 1000, while the number of girls increased from 25 to 450.

    Total number of students = Number of boys + Number of girls

    If X is defined as the ratio of the total number of girls to the total number of students, then X was maximum in the year

    Solution
    Year Students Girls Boys
    2009-10 100 25 100-25 = 75
    2010-11 200 50 150
    2011-12 400 100 300
    2012-13 450 250 200
    2012-14 1000 450 550

    X was maximum in the year 2012-13.The value of X was 250/450 = 5/9
    For other years X is less than the above mentioned value.

  • Question 7
    1 / -0

    The figure below represents the total number of students and the number of girls in college XYZ for the five years from 2009-10 to 2013-14. During this period, the total number of students increased from 100 to 1000, while the number of girls increased from 25 to 450.

    Total number of students = Number of boys + Number of girls

    With reference to X as defined in previous question , it can be concluded that

    Solution
    Year Students Girls Boys
    2009-10 100 25 100-25 = 75
    2010-11 200 50 150
    2011-12 400 100 300
    2012-13 450 250 200
    2012-14 1000 450 550
    Year Students Girls x
    2009-10 100 25 25/100 = 0.25
    2010-11 200 50 0.25
    2011-12 400 100 0.25
    2012-13 450 250 0.56
    2012-14 1000 450 0.45

    It is evident, that X remained constant for first 3 years, then there is an increase followed by a decrease.

  • Question 8
    1 / -0

    The following table represents the number of software projects on different domains that were done in different companies in 2006.

    Company Java Asp. Net Oracle C Main framer
    Bamsi 14 12 8 10 4
    Wipro 12 9 17 10 8
    Satyam 3 14 9 7 6
    Flextronics 5 12 13 4 1
    Infosys 20 18 9 13 3
    C.T.S 4 5 2 12 13
    Perot 11 4 7 9 18
    T.C.S 13 4 1 17 11
    Dell 7 5 3 5 12
    Birlasoft 11 9 0 4 3

    There are no other projects done by these companies except those given above.

    How many companies did more Oracle projects than Wirpo or less Java projects than Birlasoft in 2006?

    Solution

    No company did more Oracle projects than Wirpo, but 4 companies did less Java projects than Birlasoft.

  • Question 9
    1 / -0

    The following table represents the number of software projects on different domains that were done in different companies in 2006.

    Company Java Asp. Net Oracle C Main framer
    Bamsi 14 12 8 10 4
    Wipro 12 9 17 10 8
    Satyam 3 14 9 7 6
    Flextronics 5 12 13 4 1
    Infosys 20 18 9 13 3
    C.T.S 4 5 2 12 13
    Perot 11 4 7 9 18
    T.C.S 13 4 1 17 11
    Dell 7 5 3 5 12
    Birlasoft 11 9 0 4 3

    There are no other projects done by these companies except those given above.

    How many companies did more projects than Flextronics?

    Solution

    Total 7

  • Question 10
    1 / -0

    In an examination, it is required to get 296 marks to pass. A student got 222 marks and failed by 10% marks. How much maximum marks a student can get?

    Solution

    296-222= 74

    74 = 10% of max marks 

    hence max marks is 740

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