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Physics Test 272

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Physics Test 272
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Weekly Quiz Competition
  • Question 1
    4 / -1

    A second pendulum is mounted in a space shuttle. Its period of oscillations will decrease when rocket is:

    Solution

     

  • Question 2
    4 / -1

    Find the amplitude of the S.H.M whose displacement y in cm is given by equation y= 3 sin157t + 4 cos157t, where t is time in seconds.

    Solution

    When the displacement of a SHM is:

    y=a sin wt+ b cos wt

    • Amplitude of the SHM will be:
      A=√a2+b2

    Here, a = 3, b = 4

    Amplitude, A= √(32+42) = 5 cm

    Hence option B is correct.

     

  • Question 3
    4 / -1

    A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

    Solution

     

  • Question 4
    4 / -1

    What is the maximum Kinetic energy and minimum potential energy of a harmonic oscillator with amplitude 0.03m, force constant 4 × 105 N/m and total mechanical energy of 230 J.

    Solution

    K. E=1/2 K(A2-x2)

    Max of mean position,

    K. E=1/2 KA2

    =1/2 x4x105x(3x10-2)2

    =180J

    T.M. E=180+P.E

    230=180+P.E

    P.E=230-180

    P.E=50J

     

  • Question 5
    4 / -1

    The velocity and acceleration amplitudes of body executing simple harmonic motion is

    Solution

    Maximum velocity: v = ωA, where ω is uniform angular velocity and a is the radius of the circle in which a reference particle executing S.H.M.

    Velocity is maximum at mean positions. The maximum value of velocity is called velocity amplitude in SHM.

    Acceleration is maximum at extreme position given by A = - ω2A. The maximum value of acceleration is called acceleration amplitude in SHM.

     

  • Question 6
    4 / -1

    A particle of mass m is executing oscillation about the origin on X-axis. Its potential energy is V(x)=K∣x∣3. Where K is a positive constant. If the amplitude of oscillation is a, then its time period T is proportional to.

    Solution

     

  • Question 7
    4 / -1

    Energy is supplied to the damped oscillatory system at the same rate at which it is dissipating energy, then the amplitude of such oscillations would become constant. Such oscillations are called

    Solution

    Energy is supplied to the damped oscillatory system at the same rate at which it is dissipating energy, and then the amplitude of such oscillations would become constant. Such oscillations are called maintained oscillations. By the definition of maintained oscillations.

     

  • Question 8
    4 / -1

    What determines the natural frequency of a body?

    Solution

    Natural frequency is the frequency at which a body tends to oscillate in the absence of any driving or damping force.

    Free vibrations of any elastic body are called natural vibration and happen at a frequency called natural frequency. Natural vibrations are different from forced vibration which happen at frequency of applied force .

     

  • Question 9
    4 / -1

    In the ideal case of zero damping, the amplitude of simple harmonic motion at resonance is:

    Solution

    In an ideal environment where there is no resistance to oscillatory motion, that is, damping is zero, when we oscillate a system at its resonant frequency, since there is no opposition to oscillation, a very large value of amplitude will be recorded. Forced oscillation is when you apply an external oscillating force.

     

  • Question 10
    4 / -1

    The necessary condition for phenomenon of interference to occur is

    Solution

    The necessary condition for phenomenon of interference to occur are:

    1. There should be two coherent sources.

    2. The frequency and amplitude of both the waves should be same.

    3. The propagation of waves should be simultaneously and in same direction.

    These are the conditions, no explanation.

     

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