Physics Test 27...

A second pendulum is mounted in a space shuttle. Its period of oscillations will decrease when rocket is:

Find the amplitude of the S.H.M whose displacement y in cm is given by equation y= 3 sin157t + 4 cos157t, where t is time in seconds.

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

What is the maximum Kinetic energy and minimum potential energy of a harmonic oscillator with amplitude 0.03m, force constant 4 × 10⁵ N/m and total mechanical energy of 230 J.

The velocity and acceleration amplitudes of body executing simple harmonic motion is

A particle of mass m is executing oscillation about the origin on X-axis. Its potential energy is V(x)=K∣x∣³. Where K is a positive constant. If the amplitude of oscillation is a, then its time period T is proportional to.

Energy is supplied to the damped oscillatory system at the same rate at which it is dissipating energy, then the amplitude of such oscillations would become constant. Such oscillations are called

What determines the natural frequency of a body?

In the ideal case of zero damping, the amplitude of simple harmonic motion at resonance is:

The necessary condition for phenomenon of interference to occur is