Oscillations Test

Result

Oscillations Test - 27

Score
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Weekly Quiz Competition

Question 1
4 / -1

The displacement equation of a particle is x = 3 sin 2t + 4 cos 2t. The amplitude and maximum velocity will be respectively

A
5, 10

B
3, 2

C
4, 2

D
3, 4

Solution
Question 2
4 / -1

A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the velocity in m sec^–1 at the centre of oscillation is

A
20 π

B
100

C
40 π

D
100 π

Solution
Question 3
4 / -1

A particle executes S.H.M. with a period of 6 second and amplitude of 3 cm. Its maximum speed in cm/s is

A
π /2

B
π

C
2 π

D
3 π

Solution
Question 4
4 / -1

A
300

B

C
100

D

Solution
Question 5
4 / -1

A S.H.M. has amplitude \'a\' and time period T. The maximum velocity will be

A

B

C

D

Solution
Question 6
4 / -1

A

B

C
20

D
16

Solution
Question 7
4 / -1

If the displacement of a particle executing S.H.M. is given by y = 0.30 sin (220t + 0.64) in metre, then the frequency and maximum velocity of the particle is

A
35 Hz, 66 m/s

B
45 Hz, 66 m/s

C
58 Hz, 113 m/s

D
35 Hz, 132 m/s

Solution
Question 8
4 / -1

A particle executes simple harmonic motion with a time period of 16 s. At time t = 2 s, the particle crosses the mean position while at t = 4s, its velocity is 4 ms^–1. The amplitude of motion in metre is

A

B

C

D

Solution
Question 9
4 / -1

The amplitude of a particle executing S.H.M. is 4 cm. At the mean position the speed of the particle is 16 cm/s. The distance of the particle from the mean, position at which the speed of the particle becomes 8√3 cm/s, will be

A

B

C
1 cm

D
2 cm

Solution
Question 10
4 / -1

The maximum velocity of a particle executing S.H.M. is V. If the amplitude is doubled and the time period of oscillation decreased to 1/3 of its original value, the maximum velocity becomes

A
18 V

B
12 V

C
6 V

D
3 V

Solution