Laws of Motion Test

Result

Laws of Motion Test - 18

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Question 1
4 / -1

Two masses M and M/2 are joined together by means of light inextensible string passed over a frictionless pulley as shown in the figure. When the bigger mass is released, the small one will ascend with an acceleration of

A

B

C

D
g

Solution
Question 2
4 / -1

A
100 N

B
110 N

C
209 N

D
196 N

Solution
Question 3
4 / -1

The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle θ should be

A
0°

B
30°

C
45°

D
60°

Solution
Question 4
4 / -1

A block B is pushed momentarily along a horizontal surface with an initial velocity v. If μ is the coefficient of sliding friction between B and the surface, block B will come to rest after a time

A

B

C

D

Solution
Question 5
4 / -1

A body is coming with a velocity of 72 kmh^-1 on a rough horizontal surface of coefficient of friction 0.5. If the acceleration due to gravity is 10 ms^-2 , find the minimum distance, it can be stopped.

A
400 m

B
40 m

C
0.40 m

D
4 m

Solution
Question 6
4 / -1

In the arrangement shown in figure, the strings are light and inextensible. The surface over which blocks are placed is smooth. What is the acceleration of each block?

A
8 ms^-2

B
4 ms^-2

C
2 ms^-2

D
14 ms^-2

Solution
Question 7
4 / -1

A block of mass 2 kg rests on a horizontal surface. If a horizontal force of 5 N is applied on the block, the frictional force on it is ( take, µ_k = 0.4 , µ_s = 0.5 )

A
5 N

B
10 N

C
8 N

D
zero

Solution
Question 8
4 / -1

In the given figure, the pulley is assumed massless and frictionless. If the friction force on the object of mass m is f, then its acceleration in terms of the force F will be equal to

A

B

C

D
None of these

Solution
Question 9
4 / -1

A block moving on a surface with velocity 20 ms^-1 comes to rest because of surface friction over a distance of 40 m. The coefficient of dynamic friction is (take, g =10 ms^-2)

A
0.5

B
0.3

C
0.2

D
0.1

Solution
Question 10
4 / -1

Two blocks of masses M and m are connected by a string passing over a pulley as shown in the figure. The downward acceleration of the block with mass m is

A
M / (m + M) g

B
mg / (m + M)

C
(m + M) / mg

D
(n + M) / Mg

Solution