Introduction to...

If $$\text{cosec} \theta-\cot \theta = q,$$ then the value of $$\text{cosec} \theta$$ is

If $$\displaystyle x= \frac{2\sin \alpha}{1+\cos \alpha+\sin \alpha}$$ then $$\displaystyle \frac{1-\cos \alpha+\sin \alpha}{1+\sin \alpha}$$ is equal to

If $$\displaystyle \sin \theta_{1}+\sin \theta_{2}+\sin \theta_{3} = 3,$$ then $$\displaystyle \cos \theta_{1}+\cos\theta_{2}+\cos \theta_{3} $$is equal to

If $$\displaystyle \sin x+cosec x= 2 $$ then $$\displaystyle \sin ^{n}x+cosec^{n}x $$ is equal to

If $$\displaystyle sin \theta - cos \theta = 1$$, then the value of $$\displaystyle sin^3 \theta - cos^3 \theta$$ is

If $$cosec \theta -\sin \theta =m$$ and  $$\sec \theta -\cos \theta =n$$, eliminate $$\theta $$.

If $$\displaystyle \frac{x}{a}\cos \theta +\frac{y}{b}\sin \theta =1,\frac{x}{a}\sin \theta-\frac{y}{b}\cos \theta=1,$$ then eliminate $$\theta $$

The value of the expression $$\displaystyle \frac {tan^2 20^0 - sin^2 20^0}{tan^2 20^0 . sin^2 20^0}$$ is

If $$\displaystyle \sec \theta +\tan \theta=p$$, then find the value of $$\tan \theta$$.

If $$\displaystyle \left ( \sec \theta +\tan \theta  \right )\left ( \sec \phi +\tan \phi  \right )\left ( \sec \psi  +\tan \psi  \right )=\tan \theta \tan \phi \tan \psi $$ ,then $$\displaystyle \left ( \sec \theta -\tan \theta  \right )\left ( \sec \phi -\tan \phi  \right )\left ( \sec \psi  -\tan \psi  \right )$$ is equal to