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In right angle $$\triangle ABC,   \angle B=90^o,   \angle A=45^o$$, then $$\sin { 45^o } =$$

In right angle $$\triangle ABC,   \angle B=90^o,   \angle A=45^o$$, then $$\tan { 45^o } =$$

In right angle $$\triangle ABC,   \angle B=90^o,   \angle A=45^o=\angle C$$, then $$\sec { 45^o} =$$

In right angled $$\triangle ABD,   \angle B=60^o,   \angle A=30^o$$.

In right angle $$\triangle ABD,   \angle B={ 60 }^{ o  },   \angle A={ 30 }^{ o  }$$, then $$\cot { { 60 }^{ o  } } =$$

In $$\triangle ABC,   \angle B=90^o,   AB=3\   cm,   AC=6\   cm,   \angle A=$$

In right angle $$\triangle ABC,   \angle B=90^o,   \angle A=45^o$$, then $$\cos { 45^o } =$$

In $$\triangle ABC,   \angle B=90^o,   \angle A=30^o,   AB =9  cm\ $$, then $$BC =$$

Value of $$\left(\sin{60^o}\cos{30^o}-\cos{60^o}\sin{30^o}\right)$$ is 

Value of $$\left(\tan{30^0}\csc{60^0} + \tan{60^0}\sec{30^0}\right)$$ is