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Statistics Test - 16

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Statistics Test - 16
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  • Question 1
    1 / -0
    Find the median number of newspaper purchased in a story by $$9$$ customers.
    $$2, 4, 5, 1, 6, 8, 9, 4, 7$$
    Solution
    The median of a set of data is the middlemost number in the set.
    So, first arrange the data in order.
    $$1, 2, 4, 4, 5, 6, 7, 8, 9$$
    The median is $$5$$.
  • Question 2
    1 / -0
    $$12-n, 12, 12+n$$
    What is the average (arithmetic mean) of the $$3$$ quantities in the list above?
    Solution
    Given $$3$$ Quantities: $$12$$ $$-$$ $$n$$, $$12$$, $$12$$ $$+$$ $$n$$

    Average of the above $$3$$ Quantities $$=$$ $$\dfrac {\text{Sum of the above}\: 3\: \text{Quantities}} {\text{Number of Quantities}} $$

    $$=$$ $$\dfrac { 12 \space - \space n \space + \space 12 \space + \space 12 \space + \space n }{3}$$

    $$=$$ $$\dfrac {12 \times 3}{3}$$


    $$=$$ $$12$$


    Therefore, average of the Quantities listed above is $$12$$.
  • Question 3
    1 / -0
    Find the average of the expressions $$2x+4, 5x-1$$ and $$-x+3$$.
    Solution
    Average of the expression $$=$$ $$\dfrac{sum \quad of \quad expression }{total \quad no. \quad of \quad expressions}$$
    $$\Rightarrow \dfrac{2x+4+5x-1-x+3}{3}$$
    $$\Rightarrow \dfrac{6x+6}{3}$$
    $$\Rightarrow \dfrac{3(2x+2)}{3}=2x+2$$
  • Question 4
    1 / -0
    The age of $$13$$ school students are listed below. Find the median.
    $$12, 9, 8, 13, 15, 14, 6, 18, 7, 11, 9, 14, 10$$
    Solution
    The median of a set of data is the middlemost number in the set.
    So, first arrange the data in order.
    $$6, 7, 8, 9, 10, 10, 11, 12, 13, 14, 14, 15, 18$$
    The median is $$11$$.
  • Question 5
    1 / -0
    The _____ of a set of data is the middlemost number in the set.
    Solution
    The median of a set of data is the middlemost number in the set.
    Example: $$3, 4, 5, 1, 1, 8, 10$$
    So, first arrange the data in order.
    So, $$1, 1, 3, 4, 5, 8, 10$$
    The middle number is median $$= 4$$
  • Question 6
    1 / -0
    Find mode of the following data.

    Solution
    Here, the highest frequency of receiving letters is $$80$$.
    So, the mode is $$480$$.
  • Question 7
    1 / -0
    The George family drove through $$11$$ states on their Spring vacation. Gasoline prices varied from state to state. Find the median gasoline price.
    $$42, 54, 12, 89, 56, 75, 29, 13, 20, 11, 34$$
    Solution
    The median of a set of data is the middlemost number in the set.
    So, first arrange the data in order.
    $$11, 12, 13, 20, 29, 34, 42, 54, 56, 75, 89$$
    The median gasoline price is $$34$$.
  • Question 8
    1 / -0
    The mode is the number that is repeated more _____ than any other.
    Solution
    The mode is the number that is repeated more often than any other.
    Example: In a group of data: $$11, 12, 12, 13, 14, 12, 15, 16, 12, 11$$
    $$12$$ is the mode. (Because $$12$$ occurs more often than any other numbers.)
  • Question 9
    1 / -0
    If $$i < m < n$$, then the median of the list $${i, m, n}$$ is ____.
    Solution
    The median of a set of data is the middlemost number in the set.
    So, the median of the list $${i, m, n}$$ is $$m$$.
  • Question 10
    1 / -0
    Find AM of divisors of $$100$$.
    Solution
    Divisors of 100 are:
    $$1, 2, 4, 5, 10, 20, 25, 50, 100$$
    $$\therefore n=9$$
    $$\therefore S=1+2+4+5+10+20+25+50+100=217$$
    $$\therefore A.M.=\dfrac{S}{n}=\dfrac{217}{9}=24.11$$
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